NCERT Solutions Class 7 Mathematics
Chapter – 6 (The Triangle and its Properties)
The NCERT Solutions in English Language for Class 7 Mathematics Chapter – 6 The Triangle and its Properties Exercise 6.2 has been provided here to help the students in solving the questions from this exercise.
Chapter : 6 The Triangles and its Properties
- NCERT Solution Class 7 Maths Exercise – 6.1
- NCERT Solution Class 7 Maths Exercise – 6.3
- NCERT Solution Class 7 Maths Exercise – 6.4
- NCERT Solution Class 7 Maths Exercise – 6.5
Exercise – 6.2
1. Find the value of the unknown exterior angle x in the following diagram:
(i) 
(ii) 
(iii) 
(iv) 
(v) 
(vi) 
Solution –
(i) ∠x = 50° + 70° = 120° (Exterior angle is equal to sum of its interior opposite angles)
(ii) ∠x = 65°+ 45° = 110° (Exterior angle is equal to sum of its interior opposite angles)
(iii) ∠x = 30° + 40° = 70° (Exterior angle is equal to sum of its interior opposite angles)
(iv) ∠x = 60° + 60° = 120° (Exterior angle is equal to sum of its interior opposite angles)
(v) ∠x = 50° + 50° =100° (Exterior angle is equal to sum of its interior opposite angles)
(vi) ∠x = 30° + 60° = 90° (Exterior angle is equal to sum of its interior opposite angle)
2. Find the value of the unknown interior angle x in the following figures:
(i) 
(ii) 
(iii) 
(iv) 
(v) 
(vi) 
Solution –
(i) ∠x + 50° = 115° (Exterior angle of a triangle)
∴ ∠x = 115°- 50° = 65°
(ii) ∠x + 70° = 110° (Exterior angle of a triangle)
∴ ∠x = 110° – 70° = 40°
(iii) ∠ x + 90° = 125° (Exterior angle of a right triangle)
∴ ∠x = 125° – 90° = 35°
(iv) ∠x + 60° = 120° (Exterior angle of a triangle)
∴ ∠x = 120° – 60° = 60°
(v)∠ X + 30° = 80° (Exterior angle of a triangle)
∴ ∠x = 80° – 30° = 50°
(vi) ∠ x + 35° = 75° (Exterior angle of a triangle)
∴ ∠ x = 75° – 35° = 40°
