NCERT Solutions Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.4

NCERT Solutions Class 7 Mathematics 
Chapter – 12 (Algebraic Expressions)

The NCERT Solutions in English Language for Class 7 Mathematics Chapter – 12 Algebraic Expressions  Exercise 12.4 has been provided here to help the students in solving the questions from this exercise. 

Chapter : 12 Algebraic Expressions

Exercise – 12.4 

1. Observe the patterns of digits made from line segments of equal length. You will find such segmented digits on the display of electronic watches or calculators.
NCERT Class 7 Maths Solution

If the number of digits formed is taken to be n, the number of segments required to form n digits is given by the algebraic expression appearing on the right of each pattern. How many segments are required to form 5, 10, 100 digits of the kind

Solution –

(a) The number of line segments required to form n digits is given by the expressions.
  = (5n + 1)
For 5 figures, the number of line segments = 5 × 5 + 1
= 25 + 1
= 26

For 10 figures, the number of line segments = 5 × 10 + 1
= 50 + 1
= 51

For 100 figures, the number of line segments = 5 × 100 + 1
= 500 + 1
= 501

(b) The number of line segments required to form n digits is given by the expressions.
=
(3n + 1)

For 5 figures, the number of line segments = 3 × 5 + 1
= 15 + 1
= 16

For 10 figures, the number of line segments = 3 × 10 + 1
= 30 + 1
= 31

For 100 figures, the number of line segments = 3 × 100 + 1
= 300 + 1
= 301

(c) The number of line segments required to form n digits is given by the expressions.
=
(5n + 2)

For 5 figures, the number of line numbers = 5 × 5 + 2
= 25 + 2
= 27

For 10 figures, the number of line segments = 5 × 10 + 2
= 50 + 2
= 52

For 100 figures, the number of line segments = 5 × 100 + 2
= 500 + 2
= 502

2. Use the given algebraic expression to complete the table of number patterns.

S. No. Expression Terms
1st 2nd 3rd 4th 5th 10th 100th
(i) 2n – 1 1 3 5 7 9 19
(ii) 3n + 2 5 8 11 14
(iii) 4n + 1 5 9 13 17
(iv) 7n + 20 27 34 41 48
(v) n2 + 1 2 5 10 17 10001

Solution –

(i) Given expression is 2n – 1
For n = 100,
= 2 × 100 – 1
= 200 – 1 = 199

(ii) Given expression is 3n + 2
For n = 5,
= 3 × 5 + 2
= 15 + 2
= 17

For n = 10,
= 3 × 10 + 2
= 30 + 2
= 32

For n = 100,
= 3 × 100 + 2
= 300 + 2
= 302

(iii) Given expression is 4n + 1

For n = 5,
= 4 × 5 + 1
= 20 + 1
= 21

For n = 10,
= 4 × 10 + 1
= 40 + 1
= 41

For n = 100,
= 4 × 100 + 1
= 400 + 1
= 401

(iv) Given expression is 7n + 20

For n = 5,
= 7 × 5 + 20
= 35 + 20
= 55

For n = 10,
= 7 × 10 + 20
= 70 + 20
= 90

For n = 100,
= 7 × 100 + 20
= 700 + 20
= 720

(v) Given expression is n2 + 1

For n = 5,
= 52 + 1
= 25 + 1
= 26

For n = 10,
= 102 + 1
= 100 + 1
= 101

S. No. Expression Terms
1st 2nd 3rd 4th 5th 10th 100th
(i) 2n – 1 1 3 5 7 9 19 199
(ii) 3n + 2 5 8 11 14 17 32 302
(iii) 4n + 1 5 9 13 17 21 41 401
(iv) 7n + 20 27 34 41 48 55 90 720
(v) n2 + 1 2 5 10 17 26 101 10001

 

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