NCERT Solutions Class 8 Maths Chapter 5 Data Handling Ex 5.1

NCERT Solutions Class 8 Mathematics 
Chapter – 5 (Data Handling) 

The NCERT Solutions in English Language for Class 8 Mathematics Chapter – 5 Data Handling Exercise 5.1 has been provided here to help the students in solving the questions from this exercise. 

Chapter 5: Data Handling

• NCERT Solution Class 8 Maths Ex – 5.2
• NCERT Solution Class 8 Maths Ex – 5.3

Exercise – 5.1 

1. For which of these would you use a histogram to show the data?
(a) The number of letters for different areas in a postman’s bag.
(b) The height of competitors in an athletics meet.
(c) The number of cassettes produced by 5 companies.
(d) The number of passengers boarding trains from 7.00 a.m. to 7.00 p.m. at a station. Give a reason for each.

Solution –
(a) The number of areas cannot be represented in terms of class interval. So, we cannot use the histogram to show the data.

(b) Height of competitors can be divided into intervals. So, we can use a histogram here.
Example – 

(c) Companies cannot be divided into class intervals. So, we cannot use a histogram here.

(d) Time for boarding the train can be divided into intervals. So, we can use a histogram here.
Example –

2. The shoppers who come to a departmental store are marked as man (M), woman (W), boy (B) or girl (G). The following list gives the shoppers who came during the first hour of the morning.
W W W G B W W M G G M M W W W W G B M W B G G M W W M M W W W M W B W G M W W W W G W M M W M W G W M G W M M B G G W.
Make a frequency distribution table using tally marks. Draw a bar graph to illustrate it.

Solution –
Frequency distribution table :-

Shopper	Tally Marks	Number of shoppers
W	|||	28
M		15
B		5
G	||	12
Total		60

Bar-graph :

3. The weekly wages (in ₹) of 30 workers in a factory are:
830, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840.
Using tally marks, make a frequency table with intervals as 800 – 810, 810 – 820 and so on.

Solution – The representation of data by frequency distribution table using tally marks is as follows:

Class Intervals	Tally Marks	Frequency
800–810	|||	3
810–820	||	2
820–830	|	1
830–840	||||	9
840–850		5
850–860	|	1
860–870	|||	3
870–880	|	1
880–890	|	1
890–900	||||	4
Total		30

4. Draw a histogram for the frequency table made for the data in Question 3 and answer the following questions.
(i) Which group has the maximum number of workers?
(ii) How many workers earn ₹ 850 and more?
(iii) How many workers earn less than ₹ 850?

Solution –

(i) 830-840 is the group having a maximum number of workers, 9, compared to other groups.

(ii) Workers earning ₹ 850 and more= 1+3+1+1+4=10

(iii) Workers earning less than ₹ 850= 3+2+1+9+5=20

5. The number of hours for which students of a particular class watched television during holidays is shown in the given graph.
Answer the following:
(i) For how many hours did the maximum number of students watch TV?
(ii) How many students watched TV for less than 4 hours?
(iii) How many students spent more than 5 hours watching TV?

Solution –
(i) 32 students watched TV for 4-5 hours. ∴ The maximum number of students who watched TV for 4 – 5 hours.

(ii) The number of students who watched TV less than 4 hours = 22 + 8 + 4 = 34

(iii) The number of students who spent more than 5 hours watching TV = 8 + 6 = 14