NCERT Solutions Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.6

NCERT Solutions Class 8 Mathematics 
Chapter – 2 (Linear Equations in One Variable) 

The NCERT Solutions in English Language for Class 8 Mathematics Chapter – 2 Linear Equations in One Variable Exercise 2.6 has been provided here to help the students in solving the questions from this exercise. 

Chapter 2: Linear Equations in One Variable

Exercise – 2.6 

Solve the following equations.

1. \mathbf{\frac{8x-3}{3x}} = 2

Solution –

\frac{8x-3}{3x} = 2

⇒ 8x – 3 = 2 × 3x
⇒ 8x – 3 = 6x
⇒ 8x – 6x = 3
⇒ 2x = 3
⇒ x = \frac{3}{2}

2. \mathbf{\frac{9x}{7-6x}} = 15

Solution –

\frac{9x}{7-6x} = 15

⇒ 9x = 15 (7 – 6x)
⇒ 9x = 105 – 90x
⇒ 9x + 90x = 105
⇒ 99x = 105

⇒ x = \frac{105}{99} = \frac{35}{33}

3. \mathbf{\frac{z}{z+15}} = \mathbf{\frac{4}{9}}

Solution –

\frac{z}{z+15}  = \frac{4}{9}

⇒ z × 9 = 4 (z + 15)
⇒ 9z = 4z + 60
⇒ 9z – 4z = 60
⇒ 5z = 60
⇒ z = 12

4. \mathbf{\frac{3y+4}{2-6y} = -\frac{2}{5}}

Solution –

\frac{3y+4}{2-6y} = -\frac{2}{5}

⇒ 5(3y + 4) = -2(2 – 6y)
⇒ 15y + 20 = -4 + 12y
⇒ 15y – 12y = -4 – 20
⇒ 3y = -24
⇒ y = -8

5. \mathbf{\frac{7y+4}{y+2} = -\frac{4}{3}}

Solution –

\frac{7y+4}{y+2} = -\frac{4}{3}

⇒ 3(7y + 4) = -4(y + 2)
⇒ 21y + 12 = -4y – 8
⇒ 21y + 4y = -8 – 12
⇒ 25y = -20

⇒ y = -\frac{20}{25} = -\frac{4}{5}

6. The ages of Hari and Harry are in the ratio of 5 : 7. Four years from now, the ratio of their ages will be 3 : 4. Find their present ages.

Solution –
Let the present ages of Hari = 5x
Let the present ages of Harry = 7x.
4 years later,
Age of Hari = 5x + 4
Age of Harry = 7x + 4
According to the question,
\frac{5x+4}{7x+4} = \frac{3}{4}

⇒ 4(5x + 4) = 3(7x + 4)
⇒ 20x + 16 = 21x + 12
⇒ 21x – 20x = 16 – 12
⇒ x = 4
Hari’s age = 5x = 5 × 4 = 20 years
Harry’s age = 7x = 7 × 4 = 28 years

7. The denominator of a rational number is greater than its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is \mathbf{\frac{3}{2}}. Find the rational number.

Solution –
Let the numerator be x,
the denominator will be (x + 8)
According to the question,
\frac{x+17}{x+8-1} = \frac{3}{2}

\frac{x+17}{x+7} = \frac{3}{2}

⇒ 2(x + 17) = 3(x + 7)
⇒ 2x + 34 = 3x + 21
⇒ 34 – 21 = 3x – 2x
⇒ x = 13
The rational number is \frac{x}{x+8} = \frac{13}{21}

 

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