NCERT Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.3

NCERT Solutions Class 7 Mathematics 
Chapter – 10 (Practical Geometry)

The NCERT Solutions in English Language for Class 7 Mathematics Chapter – 10 Practical Geometry  Exercise 10.3 has been provided here to help the students in solving the questions from this exercise. 

Chapter : 10 Practical Geometry

• NCERT Solution Class 7 Maths Exercise – 10.1
• NCERT Solution Class 7 Maths Exercise – 10.2
• NCERT Solution Class 7 Maths Exercise – 10.4
• NCERT Solution Class 7 Maths Exercise – 10.5

Exercise – 10.3 

1. Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90^o.

Solution –

Steps of construction:
1. Draw a line segment DF = 3 cm.
2. At point D, draw a ray DE to making an angle of 90^o i.e. ∠EDF = 90^o.
3. Along DX, set off DE = 5cm.
4. Join EF.
Then, ΔEDF is the required right angled triangle.

2. Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110^o.

Solution –

Steps of construction:
1. Draw a line segment AB = 6.5 cm.
2. Draw angle of 110° at A and cut AC = 6.5 cm.
3. Join C to B.
Then, ΔABC is the required isosceles triangle.

3. Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

Solution –

Steps of construction:
1. Draw a line segment BC = 7.5 cm.
2. Draw ∠C = 60° such that AC = 5 cm.
3. Join A to B.
Then, ΔABC is the required triangle.