NCERT Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4

NCERT Solutions Class 6 Maths
Chapter – 8 (Decimals)

The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 8 Decimals Exercise 8.4 has been provided here to help the students in solving the questions from this exercise.

Chapter 8: Decimals

Exercise – 8.4

1. Express as rupees using decimals.
(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90 paise
(e) 725 paise

Solutions:

We know that there are 100 paise in 1 rupees
$\because$ 1 Paise = $\frac{1}{100}$ Rupees

(a) 5 paise = $\frac{5}{100}$ rupees = Rupees 0.05

(b) 75 paise = $\frac{75}{100}$ rupees = Rupees 0.75

(c) 20 paise = $\frac{20}{100}$ rupees = Rupees 0.20

(d) 50 rupees 90 paise = 50 rupees + $\frac{90}{100}$ rupees

= 50 + 0.90 rupees
= Rupees 50.90

(e) 725 paise = $\frac{725}{100}$ rupees = $\frac{700 + 25}{100}$ rupees = $\frac{700}{100} + \frac{25}{100}$ rupees

= 7 rupees + 0.25 rupees
= Rupees 7.25

2. Express as metres using decimals.
(a) 15 cm
(b) 6 cm
(c) 2 m 45 cm
(d) 9 m 7 cm
(e) 419 cm

Solutions:

We know that there are 100 cm in 1 metre.
$\because$ 1 cm = $\frac{1}{100}$ metre.

(a) 15 cm = $\frac{15}{100}$ m = 0.15 m

(b) 6 cm = $\frac{6}{100}$ m = 0.06 m

(c) 2 m 45 cm = 2 m + $\frac{45}{100}$ m = 2 m + 0.45 m = 2.45 m

(d) 9 m 7 cm = 9 m + $\frac{7}{100}$ m = 9 m + 0.07 m = 9.07 m

(e) 419 cm = $\frac{419}{100}$ m = $\frac{400 + 19}{100}$ m = $\frac{400}{100} + \frac{19}{100}$ m

= 4 + 0.19 m = 4.19 m

3. Express as cm using decimals
(a) 5 mm
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93 mm

Solutions:

We know that there are 10 mm in 1 cm
$\because$ 1 mm = $\frac{1}{10}$ cm

(a) 5 mm = $\frac{5}{10}$ cm = 0.5 cm

(b) 60 mm = $\frac{60}{10}$ cm = 6.0 cm

(c) 164 mm = $\frac{164}{10} cm = \frac{160 + 4}{10} cm = \frac{160}{10} + \frac{4}{10}$ cm

= 16 cm + 0.4 cm
= 16.4 cm

(d) 9 cm 8 mm = 9 cm + $\frac{8}{10}$ cm

= 9 cm + 0.8 cm
= 9.8 cm

(e) 93 mm = $\frac{93}{10}$ cm = $\frac{90+3}{10}cm = \frac{90}{10} + \frac{3}{10}cm$

= 9 cm + 0.3 cm
= 9.3 cm

4. Express as km using decimals.
(a) 8 m
(b) 88 m
(c) 8888 m
(d) 70 km 5 m

Solutions:

We know that there are 1000 metres in 1 km.

$\because$ 1 metre = $\frac{1}{1000}$ km

(a) 8 m = $\frac{8}{1000}$ km = 0.008 km

(b) 88 m = $\frac{88}{1000}$ km = 0.088 km

(c) 8888 m = $\frac{8888}{1000}$ km = $\frac{8000 + 888}{1000}$ km = $\frac{8000}{1000} + \frac{888}{1000}$ km

= 8 km + 0.888 km
= 8.888 km.

(d) 70 km 5 m = 70 km + $\frac{5}{1000}$ km

= 70 km + 0.005 km
= 70.005 km

5. Express as kg using decimals.
(a) 2 g
(b) 100 g
(c) 3750 g
(d) 5 kg 8 g
(e) 26 kg 50 g

Solutions:

We know that there are 1000 grams in 1 kg.

$\because$ 1 grams = $\frac{1}{1000}$ kg

(a) 2 g = $\frac{2}{1000}$ kg = 0.002 kg

(b) 100 g = $\frac{100}{1000}$ kg = 0.1 kg

(c) 3750 g = $\frac{3750}{1000}$ kg = $\frac{3000 + 750}{1000}$ kg = $\frac{3000}{1000} + \frac{750}{1000}$ kg

= 3 kg + 0.750 kg
= 3.750 kg

(d) 5 kg 8 g = 5 kg + $\frac{8}{1000}$ kg

= 5 kg + 0.008 kg
= 5.008kg

(e) 26 kg 50 g = 26 kg + $\frac{50}{1000}$ kg

= 26 kg + 0.050 kg
= 26.050kg

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NCERT Solutions Class 6 Maths Chapter 8 Decimals Ex 8.4