NCERT Solutions Class 6 Maths Chapter 8 Decimals Ex 8.2

NCERT Solutions Class 6 Maths Chapter 8 Decimals Ex 8.2

NCERT Solutions Class 6 Maths
Chapter – 8 (Decimals)

Exercise – 8.2

Chapter 8: Decimals

The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 8 Decimals Exercise 8.2 has been provided here to help the students in solving the questions from this exercise.

1. Complete the table with the help of these boxes and use decimals to write the number.

Solutions:

	Ones	Tenths	Hundreds	Number
(a)	0	2	6	0.26
(b)	1	3	8	1.38
(c)	1	2	8	1.28

2.Write the numbers given in the following place value table in decimal form.

Solutions:

(a) 3 + $\frac{2}{10} + \frac{5}{100}$

= 3 + 0.2 + 0.05
= 3.25

(b) 100 + 2 + $\frac{6}{10} + \frac{3}{100}$

= 102 + 0.6 + 0.03
= 102.63

(c) 30 + $\frac{2}{100} + \frac{5}{1000}$

= 30 + 0.02 + 0.005
= 30.025

(d) 200 + 10 + 1 + $\frac{9}{10} + \frac{2}{1000}$

= 211 + 0.9 + 0.002
= 211.902

(e) 10 + 2 + $\frac{2}{10} + \frac{4}{100} + \frac{1}{1000}$

= 12 + 0.2 + 0.04 + 0.001
= 12.241

3. Write the following decimals in the place value table.
(a) 0.29
(b) 2.08
(c) 19.60
(d) 148.32
(e) 200.812

Solutions:

4. Write each of the following as decimals.
(a) 20 + 9 + $\frac{4}{10} +\frac{1}{100}$

(b) 137 + $\frac{5}{100}$

(d) 23 + $\frac{2}{10} + \frac{6}{1000}$

(e) 700 + 20 + 5 + $\frac{9}{100}$

Solutions :

(a) 20 + 9 + $\frac{4}{10} +\frac{1}{100}$

= 29 + 0.4 + 0.01
= 29.41

(b) 137 + $\frac{5}{100}$

= 137 + 0.05
= 137.05

= 0.7 + 0.06 + 0.004
=0.764

(d) 23 + $\frac{2}{10} + \frac{6}{1000}$

= 23 + 0.2 + 0.006
= 23.206

(e) 700 + 20 + 5 + $\frac{9}{100}$

= 725 + 0.09
= 725.09

5. Write each of the following decimals in words.
(a) 0.03
(b) 1.20
(c) 108.56
(d) 10. 07
(e) 0.032
(f) 5.008

Solutions:

(a) 0.03 = zero point zero three
(b) 1.20 = one point two zero
(c) 108.56 = one hundred eight point five six
(d) 10.07 = ten point zero seven
(e) 0.032 = zero point zero three two
(f) 5.008 = five point zero zero eight

6. Between which two numbers in tenths place on the number line does each of the given number lie?
(a) 0.60
(b) 0.45
(c) 0.19
(d) 0.66
(e) 0.92
(f) 0.57

Solutions:

(a) 0.60 lies between 0 and 0.1 in tenths place.
(b) 0.45 lies between 0.4 and 0.5 in tenths place.
(c) 0.19 lies between 0.1 and 0.2 in tenths place.
(d) 0.66 lies between 0.6 and 0.7 in tenths place.
(e) 0.92 lies between 0.9 and 1.0 in tenths place.
(f) 0.57 lies between 0.5 and 0.6 in tenths place.

7. Write as fractions in lowest terms.
(a) 0.60
(b) 0.05
(c) 0.75
(d) 0.18
(e) 0.25
(f) 0.125
(g) 0.066

Solutions:

(a) 0.60 = $\frac{60}{100} = \frac{60\div20}{100\div20}$

∵ H.C.F.(60, 100) = 20

= $\frac{3}{5}$

(b) 0.05 = $\frac{5}{100} = \frac{5\div5}{100\div5}$

∵ H.C.F.(5, 100) = 5

= $\frac{1}{2}$

∵ H.C.F.(75, 100) = 25

= $\frac{3}{4}$

(d) 0.18 = $\frac{18}{100} = \frac{18\div2}{100\div2}$

∵ H.C.F.(18, 100) = 2

= $\frac{9}{50}$

(e) 0.25 = $\frac{25}{100} = \frac{25\div25}{100\div25}$

∵ H.C.F.(25, 100) = 25

= $\frac{1}{4}$

(f) 0.125 = $\frac{125}{1000}= \frac{125\div125}{1000\div125}$

∵ H.C.F.(125, 1000) = 125

= $\frac{1}{8}$

(g) 0.066 = $\frac{66}{1000} = \frac{66\div2}{1000\div2}$

∵ H.C.F.(66, 1000) = 2

= $\frac{33}{500}$

NCERT Class 6^thSolution

NCERT Solutions Class 6 English

NCERT Solutions Class 6 Hindi

NCERT Solutions Class 6 Maths

NCERT Solutions Class 6 Sanskrit

NCERT Solutions Class 6 Science

NCERT Solutions Class 6 Social Science

Hundreds
(100)

Tens
(10)

Ones
(1)

Tenths
$\mathbf{\left ( \frac{1}{10} \right )}$

Hundredths
$\mathbf{\left ( \frac{1}{100} \right )}$

Thousandths
$\mathbf{\left ( \frac{1}{1000} \right )}$