NCERT Solutions Class 6 Maths Chapter 14 Practical Geometry Ex 14.4

NCERT Solutions Class 6 Maths
Chapter – 14 (Practical Geometry)

The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 14 Practical Geometry Exercise 14.4 has been provided here to help the students in solving the questions from this exercise.

Chapter 14: Practical Geometry

Exercise – 14.4

1. Draw any line segment $\mathbf{\overline{AB}}$ . Mark any point M on it. Through M, draw a perpendicular to $\mathbf{\overline{AB}}$ . (use ruler and compasses)

Solutions :
$NCERT Class 6 Math Solution$
Step 1: Draw a line segment $\overline{AB}$ and mark any point M on it.
Step 2: Put the pointer of the compass at M and draw an arc of suitable radius such that it intersects $\overline{AB}$ at P and Q.
Step 3: Take P and Q as centres and radius greater than PM, draw two arcs such that they intersect each other at C.
Step 4: Join M and C.
Thus CM is the perpendicular to $\overline{AB}$ .

2. Draw any line segment $\mathbf{\overline{PQ}}$ . Take any point R not on it. Through R, draw a perpendicular to $\mathbf{\overline{PQ}}$ . (Use ruler and set square).

Solutions:
$NCERT Class 6 Math Solution$
Step 1: Draw a line segment $\overline{PQ}$ and a point R outside of $\overline{PQ}$ .
Step 2: Place a set square on $\overline{PQ}$ such that one side of its right angle be along it.
Step 3: Place a ruler along the longer side of the set square.
$NCERT Class 6 Math Solution$
Step 4: Hold the ruler fix and slide the set square along the ruler till it touches the point R.
Step 5: Join RM along the edge through R.
Thus $\overline{RM}$ ⊥ $\overline{PQ}$ .

3. Draw a line l and a point X on it. Through X, draw a line segment $\mathbf{\overline{XY}}$ perpendicular to l. Now draw a perpendicular to $\mathbf{\overline{XY}}$ at y. (Use ruler and compasses)

Solutions:
$NCERT Class 6 Math Solution$
Step 1: Draw a line l and take a point X on it.
Step 2: Draw an arc with centre X and of suitable radius to intersect the line l at two points P and Q.
Step 3: With P and Q as centres and a radius greater than P draw two arcs to intersect each other at M.
Step 4: Join XM and produce to Y.
Step 5: With Y as centre and a suitable radius, draw an arc to intersect XY at two points R and S.
Step 6: With R and S as centres and a radius greater than YR, draw two arcs to intersect each other at A.
Step 7: Join Y and A.
Thus $\overline{YA}$ ⊥ $\overline{XY}$ .

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NCERT Solutions Class 6 Maths Chapter 14 Practical Geometry Ex 14.4