NCERT Solutions Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

NCERT Solutions Class 6 Maths
Chapter – 14 (Practical Geometry)

The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 14 Practical Geometry Exercise 14.2 has been provided here to help the students in solving the questions from this exercise.

Chapter 14: Practical Geometry

Exercise – 14.2

1. Draw a line segment of length 7.3 cm using a ruler.

Solutions:
$NCERT Class 6 Math Solution$
Using a ruler, we can draw a line segment of length 7.3 cm as follows
Step 1: Mark a point A on the sheet
Step 2: Place the O mark of the ruler against the point P.
Step 3: Mark a point B at a distance of 7.3 cm from A.
Step 4: Join A and B.
Thus $\overline{AB}$ is the line segment of length 7.3 cm.

2. Construct a line segment of length 5.6 cm using ruler and compass.

Solutions:

By using a ruler and compasses, we may draw a line segment of length 5.6 cm as follows
$NCERT Class 6 Math Solution$
Step 1: Draw a line l and mark a point A on this line l.
Step 2: Place the needle of the compass on the zero mark of the ruler and open it upto 5.6 mark.
Step 3: Place the needle at any point A at the line and draw an arc to cut l at B.
Thus, $\overline{AB}$ is the required line segment of length 5.6 cm.

3. Construct $\overline{AB}$ of length 7.8 cm. From this, cut off $\overline{AC}$ of length 4.7 cm. Measure $\overline{BC}$ .

Solutions:

Given that $\overline{AB}$ = 7.8 cm and $\overline{AC}$ = 4.7 cm.
$NCERT Class 6 Math Solution$
Step 1: Place zero mark of the ruler at A.
Step 2: Mark a point B at a distance of 7.8 cm from A.
Step 3: Mark another point C at a distance of 4.7 cm from A such that $\overline{AC}$ = 4.7 cm.
Step 4: On measuring the length of BC, we find that $\overline{BC}$ = 3.1 cm.

4. Given $\mathbf{\overline{AB}}$ of length 3.9 cm. Construct $\mathbf{\overline{PQ}}$ such that the length of $\mathbf{\overline{PQ}}$ is twice that of $\mathbf{\overline{AB}}$ . Verify by measurement.
$NCERT Class 6 Math Solution$
(Hint : Construct $\overline{PX}$ such that the length of $\overline{PX}$ = length of $\overline{AB}$ then cut off $\overline{XQ}$ such that $\overline{XQ}$ also has the length of $\overline{AB}$ .)

Solutions:

Step 1: Draw a line l of suitable length.
Step 2: Draw $\overline{AB}$ = 3.9 cm
$NCERT Class 6 Math Solution$
Step 2: From the line, construct $\overline{PX}$ = $\overline{AB}$ = 3.9 cm.
$NCERT Class 6 Math Solution$
Step 4: Again construct $\overline{XQ}$ = $\overline{AB}$ =3.9 cm
$NCERT Class 6 Math Solution$
Verification : $\overline{PX}$ + $\overline{XQ}$ = $\overline{AB}$ + $\overline{AB}$
Thus twice of $\overline{AB}$ is equal to $\overline{PQ}$ .

5. Given $\mathbf{\overline{AB}}$ of length 7.3 cm and $\mathbf{\overline{CD}}$ of length 3.4 cm, construct a line segment $\mathbf{\overline{XY}}$ such that the length of XY is equal to the difference between the length of $\mathbf{\overline{AB}}$ and $\mathbf{\overline{CD}}$ . Verify the measurement.

Solutions:
$NCERT Class 6 Math Solution$

Step 1: Construct $\overline{AB}$ = 7.3 cm and $\overline{CD}$ = 3.4 cm.
Step 2: Take a point P on the given line l.
Step 3: Construct $\overline{PR}$ such that $\overline{PR}$ = $\overline{AB}$ = $\overline{AB}$ = 7.3 cm.
Step 4: Construct $\overline{RQ}$ = $\overline{CD}$ = 3.4 cm such that PQ = $\overline{AB}$ – $\overline{CD}$ .
Verification : On measuring, we observe that $\overline{PQ}$ = 3.9 cm = 7.3 cm 3.4 cm. = $\overline{AB}$ – $\overline{CD}$
Thus, $\overline{PQ}$ = $\overline{AB}$ – $\overline{CD}$ .

NCERT Class 6^thSolution

NCERT Solutions Class 6 English

NCERT Solutions Class 6 Hindi

NCERT Solutions Class 6 Maths

NCERT Solutions Class 6 Sanskrit

NCERT Solutions Class 6 Science

NCERT Solutions Class 6 Social Science

NCERT Solutions Class 6 Maths Chapter 14 Practical Geometry Ex 14.2