NCERT Solutions Class 8 Mathematics
Chapter – 4 (Practical Geometry)
The NCERT Solutions in English Language for Class 8 Mathematics Chapter – 4 Practical Geometry Exercise 4.2 has been provided here to help the students in solving the questions from this exercise.
Chapter 4: Practical Geometry
- NCERT Solution Class 8 Maths Ex – 4.1
- NCERT Solution Class 8 Maths Ex – 4.3
- NCERT Solution Class 8 Maths Ex – 4.4
- NCERT Solution Class 8 Maths Ex – 4.5
Exercise – 4.2
1. Construct the following quadrilaterals.
(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
Solution –
Construction :
Step I – Draw LI = 4 cm.
Step II – Draw an arc with centre I and radius 3 cm.
Step III – Draw another arc with centre L and radius 4.5 cm to meet the former arc at F.
Step IV – Join LF and IF.
Step V – Draw an arc with centre L and radius 2.5 cm.
Step VI – Draw another arc with centre I and radius 4 cm to meet the previous arc at T.
Step VII – Join LT and IT.
Thus LIFT is the required quadrilateral.
(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
Solution –
Construction :
Step I – Draw OL = 7.5 cm
Step II – Draw an arc with centre O and radius 10 cm.
Step III – Draw another arc with centre L and radius 5 cm to meet the previous arc at D.
Step IV – Join OD and LD.
Step V – Draw an arc with centre L and D with equal radii of 6 cm to meet each other at G.
Step VI – Join LG and DG.
Thus GOLD is the required quadrilateral.
(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm
Solution –
Construction :
Step I – Draw BN = 5.6 cm.
Step II – Draw the right bisector of BN at O.
Step III – Draw two arcs with centre O and radius × DE, i.e.,
× 6.5 = 3.25 cm to meet the right bisector at D and E.
Step IV – Join BE, EN, ND and BD.
Thus, BEND is the required rhombus.
