NCERT Solutions Class 8 Mathematics
Chapter – 2 (Linear Equations in One Variable)
The NCERT Solutions in English Language for Class 8 Mathematics Chapter – 2 Linear Equations in One Variable Exercise 2.5 has been provided here to help the students in solving the questions from this exercise.
Chapter 2: Linear Equations in One Variable
- NCERT Solution Class 8 Maths Ex – 2.1
- NCERT Solution Class 8 Maths Ex – 2.2
- NCERT Solution Class 8 Maths Ex – 2.3
- NCERT Solution Class 8 Maths Ex – 2.4
- NCERT Solution Class 8 Maths Ex – 2.6
Exercise – 2.5
Solve the following linear equations.
1.
Solution –
⇒
⇒
⇒ 3x – 2x =
⇒ x =
⇒ x =
2.
Solution –
⇒
⇒
⇒ 7n = 21 × 12
⇒ n =
⇒ n =
⇒ n = 36
3. x + 7 –
Solution –
x + 7 –
⇒ x –
⇒
⇒
⇒ 5x = – 25
⇒ x =
⇒ x = – 5
4.
Solution –
⇒ 5 (x – 5) = 3 (x – 3)
⇒ 5x – 25 = 3x – 9
⇒ 5x – 3x = -9 + 25
⇒ 2x = 16
⇒ x = 8
5.
Solution –
⇒
⇒
⇒ 9t – 6 – 8t – 12 =
⇒ t – 18 = 8 – 12t
⇒ t + 12t = 8 + 18
⇒ 13t = 26
⇒ t = 2
6. m –
Solution –
⇒ m –
⇒
⇒ 6m – 3(m – 1) + 2(m – 2) = 6
⇒ 6m – 3m +3 + 2m – 4 = 6
⇒ 5m – 1 = 6
⇒ 5m = 7
⇒ m =
Simplify and solve the following linear equations.
7. 3 (t – 3) = 5(2t + 1)
Solution –
3(t – 3) = 5(2t + 1)
⇒ 3t – 9 = 10t + 5
⇒ 3t – 10t = 5 + 9
⇒ -7t = 14
⇒ t =
⇒ t = -2
8. 15(y – 4) –2(y – 9) + 5(y + 6) = 0
Solution –
15(y – 4) –2(y – 9) + 5(y + 6) = 0
⇒ 15y – 60 -2y + 18 + 5y + 30 = 0
⇒ 15y – 2y + 5y = 60 – 18 – 30
⇒ 18y = 12
⇒ y =
⇒ y =
9. 3 (5z – 7) – 2(9z – 11) = 4(8z – 13) – 17
Solution –
3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17
⇒ 15z – 21 – 18z + 22 = 32z – 52 – 17
⇒ 15z – 18z – 32z = -52 – 17 + 21 – 22
⇒ -35z = -70
⇒ z =
⇒ z = 2
10. 0.25(4f – 3) = 0.05(10f – 9)
Solution –
0.25(4f – 3) = 0.05(10f – 9)
⇒ f – 0.75 = 0.5f – 0.45
⇒ f – 0.5f = -0.45 + 0.75
⇒ 0.5f = 0.30
⇒ f =
⇒ f =
⇒ f = 0.6