NCERT Solutions Class 6 Maths Chapter 2 Whole Numbers Ex 2.3

NCERT Solutions Class 6 Maths
Chapter – 2 (Whole Numbers)

The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 2 Whole Numbers Exercise 2.3 has been provided here to help the students in solving the questions from this exercise.

Chapter 2: Whole Numbers

Exercise – 2.3

1. Which of the following will not represent zero:

(a) 1 + 0
(b) 0 × 0
(c)
(d)

Solutions:

(a) 1 + 0 = 1
Hence, it does not represent zero

(b) 0 × 0 = 0
Hence, it represents zero

(c)
Hence, it represents zero

(d)
Hence, it represents zero

2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

Solutions:
If product of two whole numbers is zero, definitely one of them is zero
Example: 0 × 1 = 0 and 2 × 0 = 0
If product of two whole numbers is zero, both of them may be zero
Example: 0 × 0 = 0
Yes, if the product of two whole numbers is zero, then both of them will be zero

3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.

Solutions:
If the product of two whole numbers is 1, both the numbers should be equal to 1
Example: 1 × 1 = 1
But 1 × 2 = 2
Hence, its clear that the product of two whole numbers will be 1, only in situation when both numbers to be multiplied are 1

4. Find using distributive property:
(a) 728 × 101
(b) 5437 × 1001
(c) 824 × 25
(d) 4275 × 125
(e) 504 × 35

Solutions:
(a) Given 728 × 101
728 × (100 + 1)
= 728 × 100 + 728 × 1
= 72800 + 728
= 73528

(b) Given 5437 × 1001
= 5437 × (1000 + 1)
= 5437 × 1000 + 5437 × 1
= 5437000 + 5437
= 5442437

(c) Given 824 × 25
= (800 + 24) × 25
= (800 + 25 – 1) × 25
= 800 × 25 + 25 × 25 – 1 × 25
= 20000 + 625 – 25
= 20000 + 600
= 20600

(d) Given 4275 × 125
= (4000 + 200 + 100 – 25) × 125
= (4000 × 125 + 200 × 125 + 100 × 125 – 25 × 125)
= 500000 + 25000 + 12500 – 3125
= 534375

(e) Given 504 × 35
= (500 + 4) × 35
= 500 × 35 + 4 × 35
= 17500 + 140
= 17640

5. Study the pattern:
1 × 8 + 1 = 9
12 × 8 + 2 = 98
123 × 8 + 3 = 987
1234 × 8 + 4 = 9876
12345 × 8 + 5 = 98765
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1)

Solutions:
123456 × 8 + 6 = 987654

Given 123456 = (111111 + 11111 + 1111 + 111 + 11 + 1)
123456 × 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) × 8
= 111111 × 8 + 11111 × 8 + 1111 × 8 + 111 × 8 + 11 × 8 + 1 × 8
= 888888 + 88888 + 8888 + 888 + 88 + 8
= 987648

123456 × 8 + 6 = 987648 + 6
= 987654
Yes, here the pattern works

1234567 × 8 + 7 = 9876543
Given 1234567 = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1)
1234567 × 8 = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) × 8
= 1111111 × 8 + 111111 × 8 + 11111 × 8 + 1111 × 8 + 111 × 8 + 11 × 8 + 1 × 8
= 8888888 + 888888 + 88888 + 8888 + 888 + 88 + 8
= 9876536

1234567 × 8 + 7 = 9876536 + 7
= 9876543
Yes, here the pattern works

 

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