NCERT Solutions Class 6 Maths Chapter 12 Ratio and Proportion Ex 12.1

NCERT Solutions Class 6 Maths
Chapter – 12 (Ratio and Proportion)

The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 12 Ratio and Proportion Exercise 12.1 has been provided here to help the students in solving the questions from this exercise.

Chapter 12: Ratio and Proportion

Exercise – 12.1

1. There are 20 girls and 15 boys in a class.
(a) What is the ratio of the number of girls to the number of boys?
(b) What is the ratio of the number of girls to the number of students in the class?

Solutions:
(a) Number of girls = 20
Number of boys = 15
∴ Ratio of the number of girls to the number of boys = \frac{(Number of girls)}{(Number of boys)}
= \frac{20}{15} = \frac{20\div5}{15\div5} = \frac{4}{3} or 4 : 3
Thus, the required ratio is 4 : 3.

(b) Ratio of the number of girls to the number of students
Total number of students = 20 + 15 = 35
∴  Ratio of the number of girls to the number of students = \frac{(Number of girls)}{(Total Number of student)}
= \frac{20}{35} = \frac{20\div5}{35\div5} = \frac{4}{7} or 4 : 7
Thus, the required ratio is 4 : 7.

2. Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find the ratio of
NCERT Class 6 Math Solution
(a) Number of students liking football to the number of students liking tennis.

(b) Number of students liking cricket to total number of students.

Solutions :

Number of students in the class = 30
Number of students liking football = 6
Number of students liking cricket = 12
Number of students liking tennis = 30 – (6 + 12) = 30 – 18 = 12

(a) Ratio of the number of the students liking football to the number of students liking tennis.
NCERT Class 6 Math Solution
= \frac{6}{12} = \frac{6\div6}{12\div} = \frac{1}{2}
Thus, the required ratio is 1 : 2.

(b) Ratio of the number of students liking cricket to the total number of students
NCERT Class 6 Math Solution
= \frac{12}{30} = \frac{12\div6}{30\div6} = \frac{2}{5}
Thus, the required ratio is 2 : 5.

3. See the figure and find the ratio of
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(а) Number of triangles to the number of circles inside the rectangle.

(b) Number of squares to all the figures inside the rectangle.
(c) Number of circles to all the figures inside the rectangle.

Solutions:

(a) Number of triangles = 3
Number of circles = 2
∴ Ratio of number of triangles to the number of circles NCERT Class 6 Math Solution
=\frac{3}{2} or 3 : 2
Thus, the required ratio is 3 : 2.

(b) Number of squares = 2
Number of all figures = 7
∴ Ratio of number of squares to the number of all the figures NCERT Class 6 Math Solution
= \frac{2}{7} or 2 : 7
Thus, the required ratio is 2 : 7.

(c) Ratio of number of circles to the number of all the figures = NCERT Class 6 Math Solution
= \frac{2}{7} or 2 : 7
Thus, the required ratio is 2 : 7.

4. Distances travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.

Solutions :

Distance travelled by Hamid = 9 km.
Distance travelled by Akhtar = 12 km.
Speed of Hamid = 9 km per hour
Speed of Akhtar = 12 km per hour
∴ Ratio of speed of Hamid to the speed of Akhtar = NCERT Class 6 Math Solution
= \frac{9}{12} = \frac{9\div3}{12\div3} = \frac{3}{4} or 3 : 4
Thus, the required ratio is 3 : 4.

5. Fill in the following blanks :
NCERT Class 6 Math Solution[Are these equivalent ratios?]

Solution :
NCERT Class 6 Math Solution

Now the fractions, we have
NCERT Class 6 Math Solution

6. Find the ratio of the following:
(a) 81 to 108
(b) 98 to 63
(c) 33 km to 121 km
(d) 30 minutes to 45 minutes

Solutions :

NCERT Class 6 Math Solution

7. Find the ratio of the following:
(a) 30 minutes to 1.5 hours
(b) 40 cm to 1.5 m
(c) 55 paise to ₹ 1
(d) 500 mL to 2 litres

Solutions :

(a) 1 hour = 60 minutes
∴ 1.5 hours = 60 x 1.5 minutes = 90 minutes
∴ Ratio of 30 minutes to 1.5 hours = Ratio of 30 minutes to 90 minutes
NCERT Class 6 Math Solution

(b) 1 m = 100 cm
∴ 1.5 m = 1.5 x 100 cm = 150 cm.
∴ Ratio of 40 cm to 1.5 m = Ratio of 40 cm to 150 cm.
NCERT Class 6 Math Solution

(c) ₹1 = 100 paise
∴ Ratio of 55 paise to ₹ 1 = Ratio of 55 paise to 100 paise
NCERT Class 6 Math Solution

(d) 500 mL to 2 litres
1 litre = 1000 mL
∴ 2 litres = 2 x 1000 mL = 2000 mL
∴ Ratio of 500 mL to 2 litres = Ratio of 500 mL to 2000 mL.
NCERT Class 6 Math Solution

8. In a year, Seema earns ₹ 1,50,000 and saves ₹ 50,000. Find the ratio of
(a) Money that Seema earns to the money she saves.
(b) Money that she saves to the money she spends.

Solutions :

(a) Money earned by Seema = ₹ 1,50,000
Money saved by her = ₹ 50,000
∴ Money spent by her = ₹ 1,50,000 – ₹ 50,000 = ₹ 1,00,000
∴ Ratio of money earned by Seema to the money saved by her 
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(b) Ratio of money saved by Seema to the money.
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9. There are 102 teachers in a school of 3300 students. Find the ratio of the number of teachers to the number of students.

Solutions :

Number of teachers = 102
Number of students = 3300
∴ Ratio of number of teachers to the number of students 
NCERT Class 6 Math Solution 

10. In a college, out of 4320 students, 2300 are girls, find the ratio of
(а) Number of girls to the total number of students.
(b) Number of boys to the number of girls.
(c) Number of boys to the total number of students.

Solutions :

Total number of students = 4320
Number of girls = 2300
∴ Number of boys = 4320 – 2300 = 2020

(a) Ratio of number of girls to the total number of students 
NCERT Class 6 Math Solution

(b) Ratio of number of boys to the number of girls
NCERT Class 6 Math Solution

(c) Ratio of number of boys to the total number of students
NCERT Class 6 Math Solution

11. Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of
(а) Number of students who opted basketball to the number of students who opted table tennis.
(b) Number of students who opted cricket to the number of students opting basketball.
(c) Number of students who opted basketball to the total number of students.

Solutions :

Total number of students = 1800
Number of students opting basketball = 750
Number of students who opted cricket = 800
Number of remaining students who opted table tennis = 1800 – (750 + 800) = 1800 – 1550 = 250

(а) Ratio of number of students who opted basketball to the number of students who opted table tennis.
NCERT Class 6 Math Solution

(b) Ratio of number of students who opted cricket to the number of students opting basketball.
NCERT Class 6 Math Solution

(c) Ratio of number of students who opted basketball to the total number of students.
NCERT Class 6 Math Solution

12. Cost of a dozen pens is ₹ 180 and cost of 8 ball pens is ₹ 56. Find the ratio of the cost of a pen to the cost of a ball pen.

Solutions :

Cost of a dozen pens = ₹ 180

Cost of 1 pen = \frac{180}{12} =  ₹ 15

Cost of 8 ball pens = ₹ 56

Cost of 1 ball pen = \frac{56}{8} = ₹ 7

Ratio of cost of 1 pen to cost of 1 ball pen 
NCERT Class 6 Math Solution
Thus required ratio is 15 : 7.

13. Consider the statement: Ratio of breadth and length of a hall is 2: 5. Complete the following table that shows some possible breadths and lengths of the hall.

Breadth of the hall (in metres) 10 [  ] 40
Length of the hall (in metres) 25 50 [  ]

Solutions :

We have \frac{10}{25} = \frac{10\div5}{25\div5} = \frac{2}{5}
∴ ratio = 2 : 5
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Breadth of the hall (in metres) 10 20 40
Length of the hall (in metres) 25 50 100

14. Divide 20 pens between Sheela and Sangeeta in the ratio of 3: 2.

Solutions:

Terms of 3 : 2 = 3 and 2
Sum of these terms = 3 + 2 = 5
∴ Sheela’s share = \frac{3}{5} x 20 = 3 x 4 = 12 pens.
Sangeeta’s shares = \frac{2}{5} x 20 = 2 x 4 = 8 pens.

Thus Sheela gets 12 pens and Sangeeta gets 8 pens.

15.  Mother wants to divide ₹ 36 between her daughters Shreya and Bhoomika in the ratio of their ages. If age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get?

Solutions :

Given that:
Money got by Shreya : Money got by Bhoomika = 15 : 12
∴ Sum = 15 + 12 = 27
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16. Present age of father is 42 years and that of his son is 14 years. Find the ratio of
(a) Present age of father to the present age of son.
(b) Age of the father to the age of son, when son was 12 years old.
(c) Age of father after 10 years to the age of son after 10 years.
(d) Age of father to the age of son when father was 30 years old.

Solutions :

Present age of father = 42 years.
Present age of his son = 14 years.

(a) Ratio of present age of father to the present age of son
NCERT Class 6 Math Solution

(b) When son was 12 years old, i.e., 14 – 12 = 2 years ago father’s age = 42 – 2 = 40 years.
Ratio of the father’s age to the son’s age 
NCERT Class 6 Math Solution

(c) Ratio of father’s age after 10 years, i.e., 42 + 10 = 52 years
to the age of son after 10 years, i.e., = 14 + 10 = 24 years
NCERT Class 6 Math Solution

(d) Ratio of the son’s age to the age of father when he was only 30 years .
When father was 30 years,
i.e., before 42 – 30 = 12 years
Age of son was = 14 – 12 = 2 years
∴ Required ratio 
NCERT Class 6 Math Solution

 

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