NCERT Solutions Class 6 Maths
Chapter – 11 (Algebra)
The NCERT Solutions in English Language for Class 6 Mathematics Chapter – 11 Algebra Exercise 11.1 has been provided here to help the students in solving the questions from this exercise.
Chapter 11: Algebra
- NCERT Solution Class 6 Maths Exercise – 11.2
- NCERT Solution Class 6 Maths Exercise – 11.3
- NCERT Solution Class 6 Maths Exercise – 11.4
- NCERT Solution Class 6 Maths Exercise – 11.5
Exercise – 11.1
1. Find the rule which gives the number of matchsticks required to make the following matchsticks patterns. Use a variable to write the rule.
(a) A pattern of letter T as .
(b) A pattern of letter Z as .
(c) A pattern of letter U as .
(d) A pattern of letter V as .
(e) A pattern of letter E as .
(f) A pattern of letter S as .
(g) A pattern of letter A as
Solutions:
(a)
From the figure we observe that two matchsticks are required to make a letter T. Hence, the pattern is 2n.
(b)
From the figure we observe that three matchsticks are required to make a letter Z. Hence, the pattern is 3n.
(c)
From the figure we observe that three matchsticks are required to make a letter U. Hence, the pattern is 3n.
(d)
From the figure we observe that two matchsticks are required to make a letter V. Hence, the pattern is 2n.
(e)
From the figure we observe that 5 matchsticks are required to make a letter E. Hence, the pattern is 5n.
(f)
From the figure we observe that 5 matchsticks are required to make a letter S. Hence, the pattern is 5n.
(g)
From the figure we observe that 6 matchsticks are required to make a letter A. Hence, the pattern is 6n.
2. We already know the rule for the pattern of letters L, C and F. Some of the letters from Q.1 (given above) give us the same rule as that given by L. Which are these? Why does this happen?
Solutions:
We know that T require only two matchsticks. So, the pattern for letter T is 2n. Among all the letters given in question 1, only T and V are the letters which require two matchsticks. Hence, (a) and (d).
3. Cadets are marching in a parade. There are 5 cadets in a row. What is the rule which gives the number of cadets, given the number of rows? (Use n for the number of rows)
Solutions:
Let n be the number of rows
Number of cadets in a row = 5
Total number of cadets = number of cadets in a row × number of rows
= 5n
4. If there are 50 mangoes in a box, how will you write the total number of mangoes in terms of the number of boxes? (Use b for the number of boxes.)
Solutions:
Let b be the number of boxes
Number of mangoes in a box = 50
Total number of mangoes = number of mangoes in a box × number of boxes
= 50b
5. The teacher distributes 5 pencils per students. Can you tell how many pencils are needed, given the number of students? (Use s for the number of students.)
Solutions:
Let s be the number of students
Pencils given to each student = 5
Total number of pencils = number of pencils given to each student × number of students
= 5s
6. A bird flies 1 kilometer in one minute. Can you express the distance covered by the birds in terms of its flying time in minutes? (Use t for flying time in minutes.)
Solutions:
Let t minutes be the flying times
Distance covered in one minute = 1 km
Distance covered in t minutes = Distance covered in one minute × Flying time
= 1 × t
= t km
7. Radha is drawing a dot Rangoli (a beautiful pattern of lines joining dots) with chalk powder. She has 9 dots in a row. How many dots will her Rangoli have for r rows? How many dots are there if there are 8 rows? If there are 10 rows?
Solutions:
Number of dots in a row = 9
Number of rows = r
Total number of dots in r rows = Number of dots in a row × number of rows
= 9r
Number of dots in 8 rows = 8 × 9
= 72
Number of dots in 10 rows = 10 × 9
= 90
8. Leela is Radha’s younger sister. Leela is 4 years younger than Radha. Can you write Leela’s age in terms of Radha’s age? Take Radha’s age to be x years.
Solutions:
Let Radha’s age be x years
Leela’s age = 4 years younger than Radha
= (x – 4) years
9. Mother has made laddus. She gives some laddus to guests and family members; still 5 laddus remain. If the number of laddus mother gave away is l, how many laddus did she make?
Solutions:
Number of laddus mother gave = l
Remaining laddus = 5
Total number of laddus = number of laddus given away by mother + number of laddus remaining
= (l + 5) laddus
10. Oranges are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the oranges from it fill two smaller boxes and still 10 oranges remain outside. If the number of oranges in a small box are taken to be x, what is the number of oranges in the larger box?
Solutions:
Number of oranges in a small box = x
Number of oranges in two small boxes = 2x
Number of oranges remained = 10
Number of oranges in large box = number of oranges in two small boxes + number of oranges remained
= 2x + 10
11. (a) Look at the following matchstick pattern of squares (Fig 11.6). The squares are not separate. Two neighbouring squares have a common matchstick. Observe the patterns and find the rule that gives the number of matchsticks
in terms of the number of squares. (Hint: If you remove vertical stick at the end, you will get a pattern of Cs)
(b) Fig 11.7 gives a matchstick pattern of triangles. As in Exercise 11 (a) above, find the general rule that gives the number of matchsticks in terms of the number of triangles.
Solutions:
(a)
Figure | Number of squares | Number of matchsticks | Pattern |
(a) | 1 | 4 | 3 x 1 +1 |
(b) | 2 | 7 | 3 x 2 +1 |
(c) | 3 | 10 | 3 x 3 +1 |
(d) | 4 | 13 | 3 x 4 +1 |
We may observe that in the given matchstick pattern, the number of matchsticks are 4, 7, 10 and 13, which is 1 more than the thrice of the number of squares in the pattern.
Therefore the pattern is 3x + 1, where x is the number of squares
(b)
Figure | Number of triangles | Number of matchsticks | Pattern |
(a) | 1 | 3 | 2 x 1 + 1 |
(b) | 2 | 5 | 2 x 2 + 1 |
(c) | 3 | 7 | 2 x 3 + 1 |
(d) | 4 | 9 | 2 x 4 + 1 |
We may observe that in the given matchstick pattern, the number of matchsticks are 3, 5, 7 and 9 which is 1 more than the twice of the number of triangles in the pattern.
Therefore the pattern is 2x + 1, where x is the number of triangles.