NCERT Solutions Class 7 Mathematics
Chapter – 2 (Fractions and Decimals)
The NCERT Solutions in English Language for Class 7 Mathematics Chapter – 2 Fractions and Decimals Exercise 2.7 has been provided here to help the students in solving the questions from this exercise.
Chapter : 2 Fractions and Decimals
- NCERT Solution Class 7 Maths Exercise – 2.1
- NCERT Solution Class 7 Maths Exercise – 2.2
- NCERT Solution Class 7 Maths Exercise – 2.3
- NCERT Solution Class 7 Maths Exercise – 2.4
- NCERT Solution Class 7 Maths Exercise – 2.5
- NCERT Solution Class 7 Maths Exercise – 2.6
Exercise – 2.7
1. Find:
(i) 0.4 ÷ 2 (ii) 0.35 ÷ 5 (iii) 2.48 ÷ 4 (iv) 65.4 ÷ 6
(v) 651.2 ÷ 4 (vi) 14.49 ÷ 7 (vii) 3.96 ÷ 4 (viii) 0.80 ÷ 5
Solution –
(i) 0.4 ÷ 2
=
=
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
Then, = 0.2
(ii) 0.35 ÷ 5
=
=
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
Then, = 0.07
(iii) 2.48 ÷ 4
=
=
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
Then, = 0.62
(iv) 65.4 ÷ 6
=
=
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
Then, = 10.9
(v) 651.2 ÷ 4
=
=
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
Then, = 162.8
(vi) 14.49 ÷ 7
=
=
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
Then, = 2.07
(vii) 3.96 ÷ 4
=
=
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
Then, = 0.99
(viii) 0.80 ÷ 5
=
=
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
Then, = 0.16
2. Find:
(i) 4.8 ÷ 10 (ii) 52.5 ÷ 10 (iii) 0.7 ÷ 10 (iv) 33.1 ÷ 10
(v) 272.23 ÷ 10 (vi) 0.56 ÷ 10 (vii) 3.97 ÷10
Solution –
(i) 4.8 ÷ 10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 0.48
(ii) 52.5 ÷ 10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 5.25
(iii) 0.7 ÷ 10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 0.07
(iv) 33.1 ÷ 10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 3.31
(v) 272.23 ÷ 10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 27.223
(vi) 0.56 ÷ 10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 0.056
(vii) 3.97 ÷10
On dividing a decimal by 10, the decimal point is shifted to the left by one place.
= 0.397
3. Find:
(i) 2.7 ÷ 100 (ii) 0.3 ÷ 100 (iii) 0.78 ÷ 100
(iv) 432.6 ÷ 100 (v) 23.6 ÷ 100 (vi) 98.53 ÷ 100
Solution –
(i) 2.7 ÷ 100
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
= 0.027
(ii) 0.3 ÷ 100
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
= 0.003
(iii) 0.78 ÷ 100
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
= 0.0078
(iv) 432.6 ÷ 100
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
= 4.326
(v) 23.6 ÷100
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
= 0.236
(vi) 98.53 ÷ 100
On dividing a decimal by 100, the decimal point is shifted to the left by two places.
= 0.9853
4. Find:
(i) 7.9 ÷ 1000 (ii) 26.3 ÷ 1000 (iii) 38.53 ÷ 1000
(iv) 128.9 ÷ 1000 (v) 0.5 ÷ 1000
Solution –
(i) 7.9 ÷ 1000
On dividing a decimal by 1000, the decimal point is shifted to the left by three places.
= 0.0079
(ii) 26.3 ÷ 1000
On dividing a decimal by 1000, the decimal point is shifted to the left by three places.
= 0.0263
(iii) 38.53 ÷ 1000
On dividing a decimal by 1000, the decimal point is shifted to the left by three places.
= 0.03853
(iv) 128.9 ÷ 1000
On dividing a decimal by 1000, the decimal point is shifted to the left by three places.
= 0.1289
(v) 0.5 ÷ 1000
On dividing a decimal by 1000, the decimal point is shifted to the left by three places.
= 0.0005
5. Find:
(i) 7 ÷ 3.5 (ii) 36 ÷ 0.2 (iii) 3.25 ÷ 0.5 (iv) 30.94 ÷ 0.7
(v) 0.5 ÷ 0.25 (vi) 7.75 ÷ 0.25 (vii) 76.5 ÷ 0.15 (viii) 37.8 ÷ 1.4
(ix) 2.73 ÷ 1.3
Solution –
(i) 7 ÷ 3.5
= 7 ÷
= 7 ×
(ii) 36 ÷ 0.2
= 36 ÷
= 36 ×
(iii) 3.25 ÷ 0.5
=
=
=
(iv) 30.94 ÷ 0.7
=
=
=
(v) 0.5 ÷ 0.25
=
=
(vi) 7.75 ÷ 0.25
=
=
(vii) 76.5 ÷ 0.15
=
=
(viii) 37.8 ÷ 1.4
=
=
(ix) 2.73 ÷ 1.3
=
=
6. A vehicle covers a distance of 43.2 km in 2.4 liters of petrol. How much distance will it cover in one liter of petrol?
Solution –
Total distance covered by vehicle in 2.4 liters of petrol = 43.2 km
∴ Distance covered in 1 liter of petrol = 43.2 ÷ 2.4
=
=
=
∴ Total distance covered in 1 liter of petrol is 18 km.