{"id":8359,"date":"2024-08-18T09:15:58","date_gmt":"2024-08-18T03:45:58","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=8359"},"modified":"2024-08-22T10:14:40","modified_gmt":"2024-08-22T04:44:40","slug":"ncert-solutions-class-11-maths-chapter-1-set-ex-1-6","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths-chapter-1-set-ex-1-6\/","title":{"rendered":"NCERT Solutions Class 11 Maths Chapter 1 Set \u2013 Ex 1.6"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">NCERT Solutions Class 11 Maths\u00a0<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 11 Mathematics <strong>Chapter &#8211; 1 Sets <\/strong>Exercise 1.6 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Chapter 1 (Sets)\u00a0<\/span><\/strong><\/span><\/h2>\n<p><span style=\"color: #000000;\"><strong>Chapter : 1 Sets<\/strong><\/span><\/p>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths-chapter-1-set-ex-1-1\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #0000ff;\">NCERT Class 11 Maths Solution Ex &#8211; 1.1<\/span><\/a><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths-chapter-1-set-ex-1-2\/\" target=\"_blank\" rel=\"noopener\">NCERT Class 11 Maths Solution Ex &#8211; 1.2<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths-chapter-1-set-ex-1-3\/\" target=\"_blank\" rel=\"noopener\">NCERT Class 11 Maths Solution Ex &#8211; 1.3<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths-chapter-1-set-ex-1-4\/\" target=\"_blank\" rel=\"noopener\">NCERT Class 11 Maths Solution Ex &#8211; 1.4<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths-chapter-1-set-ex-1-5\/\" target=\"_blank\" rel=\"noopener\">NCERT Class 11 Maths Solution Ex &#8211; 1.5<\/a><\/span><\/li>\n<\/ul>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; border-style: solid; border-color: #000000; background-color: #bddeab; text-align: center; height: 28px;\"><span style=\"font-family: georgia, palatino, serif; color: #ff0000; font-size: 14pt;\"><strong><span style=\"color: #000000;\">Exercise &#8211; 1.6<\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>1. If X and Y are two sets such that\u00a0<em>n<\/em>(X) = 17,\u00a0<em>n<\/em>(Y) = 23 and\u00a0<em>n<\/em>(X\u00a0\u222a\u00a0Y) = 38, find\u00a0<em>n<\/em>(X \u2229 Y).<br \/>\n<\/strong><strong>Solution &#8211;<br \/>\n<\/strong>n (X) = 17 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (Y) = 23 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X U Y) = 38 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we will write this as : <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X U Y) = n (X) + n (Y) \u2013 n (X \u2229 Y) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Putting values, <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">38 = 17 + 23 \u2013 n (X \u2229 Y) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So, <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X \u2229 Y) = 40 \u2013 38 = 2 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">\u2234 n (X \u2229 Y) = 2<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>2. If X and Y are two sets such that X \u222aY has 18 elements, X has 8 elements and Y has 15 elements; how many elements does X \u2229 Y have?<br \/>\n<\/strong><strong>Solution &#8211;\u00a0<\/strong>Given <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X U Y) = 18<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X) = 8 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (Y) = 15 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">We can write it as <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X U Y) = n (X) + n (Y) \u2013 n (X \u2229 Y) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">18 = 8 + 15 \u2013 n (X \u2229 Y) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X \u2229 Y) = 23 \u2013 18 = 5 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we get <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">n (X \u2229 Y) = 5<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>3. In a group of 400 people, 250 can speak Hindi and 200 can speak English. How many people can speak both Hindi and English? <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>Solution &#8211; <\/strong>Consider H as the set of people who speak Hindi <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">E as the set of people who speak English <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">We know that <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(H \u222a E) = 400\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(H) = 250 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(E) = 200 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">It can be written as <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(H\u00a0\u222a\u00a0E) =\u00a0<em>n<\/em>(H) +\u00a0<em>n<\/em>(E) \u2013\u00a0<em>n<\/em>(H \u2229 E) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">400 = 250 + 200 \u2013\u00a0<em>n<\/em>(H \u2229 E) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">400 = 450 \u2013\u00a0<em>n<\/em>(H \u2229 E) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we get <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(H \u2229 E) = 450 \u2013 400\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(H \u2229 E) = 50 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Therefore, 50 people can speak both Hindi and English. <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>4. If S and T are two sets such that S has 21 elements, T has 32 elements, and S \u2229 T has 11 elements, how many elements does S \u222a T have?<br \/>\n<\/strong><strong>Solution &#8211;\u00a0<\/strong>We know that <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S) = 21 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(T) = 32 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S \u2229 T) = 11 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">It can be written as <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>\u00a0(S\u00a0\u222a\u00a0T) =\u00a0<em>n<\/em>\u00a0(S) +\u00a0<em>n<\/em>\u00a0(T) \u2013\u00a0<em>n<\/em> (S\u00a0\u2229\u00a0T) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em> (S\u00a0\u222a\u00a0T) = 21 + 32 \u2013 11 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we get <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em> (S\u00a0\u222a\u00a0T)= 42 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Therefore, the set (S \u222a T) has 42 elements.\u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>5. If X and Y are two sets such that X has 40 elements, X \u222aY has 60 elements and X \u2229Y has 10 elements, how many elements does Y have?<br \/>\n<\/strong><strong>Solution &#8211;\u00a0<\/strong>We know that<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(X) = 40<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(X\u00a0\u222a\u00a0Y) = 60<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(X \u2229 Y) = 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">It can be written as <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(X\u00a0\u222a\u00a0Y) =\u00a0<em>n<\/em>(X) +\u00a0<em>n<\/em>(Y) \u2013\u00a0<em>n<\/em>(X \u2229 Y) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">60 = 40 +\u00a0<em>n<\/em>(Y) \u2013 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">On further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(Y) = 60 \u2013 (40 \u2013 10) = 30 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Therefore, the set Y has 30 elements. <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>6. In a group of 70 people, 37 like coffee, 52 like tea, and each person likes at least one of the two drinks. How many people like both coffee and tea?<br \/>\n<\/strong><strong>Solution &#8211;\u00a0<\/strong>Consider C as the set of people who like coffee <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">T as the set of people who like tea <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C \u222a T) = 70\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C) = 37 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(T) = 52 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">It is given that <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C\u00a0\u222a\u00a0T) =\u00a0<em>n<\/em>(C) +\u00a0<em>n<\/em>(T) \u2013\u00a0<em>n<\/em>(C \u2229 T) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">70 = 37 + 52 \u2013\u00a0<em>n<\/em>(C \u2229 T) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">70 = 89 \u2013\u00a0<em>n<\/em>(C \u2229 T) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we get <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C \u2229 T) = 89 \u2013 70 = 19 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Therefore, 19 people like both coffee and tea.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>7. In a group of 65 people, 40 like cricket, 10 like both cricket and tennis. How many like tennis only and not cricket? How many like tennis?<br \/>\n<\/strong><strong>Solution &#8211;\u00a0<\/strong>Consider C as the set of people who like cricket <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">T as the set of people who like tennis <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C \u222a T) = 65\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C) = 40 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C \u2229 T) = 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">It can be written as <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(C\u00a0\u222a\u00a0T) =\u00a0<em>n<\/em>(C) +<em>\u00a0n<\/em>(T) \u2013\u00a0<em>n<\/em>(C \u2229 T) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">65 = 40 +\u00a0<em>n<\/em>(T) \u2013 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">65 = 30 +\u00a0<em>n<\/em>(T) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we get <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(T) = 65 \u2013 30 = 35 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Hence, 35 people like tennis. <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">We know that, <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">(T \u2013 C) \u222a (T \u2229 C) = T <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">So we get, <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">(T \u2013 C) \u2229 (T \u2229 C) = \u03a6 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Here <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>\u00a0(T) =\u00a0<em>n<\/em>\u00a0(T \u2013 C) +\u00a0<em>n<\/em> (T\u00a0\u2229\u00a0C) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">35 =\u00a0<em>n<\/em> (T \u2013 C) + 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em> (T \u2013 C) = 35 \u2013 10 = 25 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Therefore, 25 people like only tennis.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><strong>8. In a committee, 50 people speak French, 20 speak Spanish and 10 speak both Spanish and French. How many speak at least one of these two languages?<br \/>\n<\/strong><strong>Solution &#8211;\u00a0<\/strong>Consider F as the set of people in the committee who speak French <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">S as the set of people in the committee who speak Spanish<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(F) = 50<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S) = 20<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S \u2229 F) = 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">It can be written as <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S\u00a0\u222a\u00a0F) =\u00a0<em>n<\/em>(S) +\u00a0<em>n<\/em>(F) \u2013\u00a0<em>n<\/em>(S \u2229 F) <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By substituting the values <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S \u222a F) = 20 + 50 \u2013 10 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">By further calculation <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S \u222a F) = 70 \u2013 10\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\"><em>n<\/em>(S \u222a F) = 60 <\/span><br \/>\n<span style=\"color: #000000; font-size: 12pt; font-family: georgia, palatino, serif;\">Therefore, 60 people in the committee speak at least one of the two languages.<\/span><\/p>\n<p><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-11-maths\/\" target=\"_blank\" rel=\"noopener\"><b><i>Go Back To Chapters<\/i><\/b><\/a><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 11 Maths\u00a0 The NCERT Solutions in English Language for Class 11 Mathematics Chapter &#8211; 1 Sets Exercise 1.6 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 1 (Sets)\u00a0 Chapter : 1 Sets NCERT Class 11 Maths Solution Ex &#8211; 1.1 NCERT Class 11 Maths [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1674],"tags":[1675,1679,1676,1686,1678,1680,1681],"class_list":["post-8359","post","type-post","status-publish","format-standard","hentry","category-class-11-maths","tag-class-11-ncert-mathematics-solutions","tag-class-11-ncert-solutions","tag-ncert-class-11-mathematics-chapter-1-sets-solutions","tag-ncert-class-11-mathematics-exercise-1-6-solutions","tag-ncert-class-11-mathematics-solutions","tag-ncert-solutions-class-11-mathematics","tag-ncert-solutions-class-11-maths"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - 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