{"id":6886,"date":"2023-12-22T05:41:08","date_gmt":"2023-12-22T05:41:08","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=6886"},"modified":"2023-12-22T05:41:51","modified_gmt":"2023-12-22T05:41:51","slug":"ncert-solutions-class-10-science-chapter-2-acids-bases-and-salts","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-science-chapter-2-acids-bases-and-salts\/","title":{"rendered":"NCERT Solutions Class 10 (Science) Chapter 2 (Acids Bases and Salts)"},"content":{"rendered":"<h2 style=\"text-align: center;\"><strong><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 10 Science\u00a0<\/span><\/strong><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 10 Science <strong>Chapter &#8211; 2 (Acids Bases and Salts) <\/strong>has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h2 style=\"text-align: center;\"><strong><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 2 (Acids Bases and Salts)\u00a0<\/span><\/strong><\/h2>\n<p style=\"text-align: center;\"><span style=\"color: #ff0000; font-family: georgia, palatino, serif; font-size: 14pt;\"><strong>Questions<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>1. You have been provided with three test tubes. One of them contains distilled water and the other two contain an acidic solution and a basic solution respectively. If you are given only red litmus paper, how will you identify the contents of each test tube ?<\/strong><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer &#8211; <\/strong>A few drops of red litmus solution is added to each test tube. Red colour will become light in the test tube containing water. Colour will turn blue in test tube containing basic solution. Red colour will become dark in the test tube containing acidic solution.<br \/>\n<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center;\"><span style=\"color: #ff0000; font-family: georgia, palatino, serif; font-size: 14pt;\"><strong>Questions<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>1. Why should not curd and sour substances be kept in containers made up of brass or copper ?<br \/>\n<\/strong><strong>Answer &#8211; <\/strong>Both curd and sour substances contain some acids in them. They react with copper or brass vessels to form certain salts which are of poisonous nature. Therefore, it is not advisable to keep them in these containers.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">2.<strong>Which gas is usually liberated when an acid reacts with a metal ? Illustrate with an example. How will you test the presence of this gas ?<\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>Metals are mostly reactive in nature. They react with dilute acids (HCl and H<sub>2<\/sub>SO<sub>4<\/sub>) to evolve hydrogen gas. For example,<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/104.199.181.145\/wp-content\/uploads\/2022\/05\/ncert-solutions-for-class-10-science-chapter-2-aci.png\" sizes=\"auto, (max-width: 373px) 100vw, 373px\" srcset=\"https:\/\/rajboardexam.in\/wp-content\/uploads\/2022\/05\/ncert-solutions-for-class-10-science-chapter-2-aci.png 373w, https:\/\/rajboardexam.in\/wp-content\/uploads\/2022\/05\/ncert-solutions-for-class-10-science-chapter-2-aci-300x22.png 300w\" alt=\"NCERT Solutions for Class 10 Science Chapter 2 Acids Bases and Salts image - 2\" width=\"373\" height=\"27\" \/><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">The gas burns with a pop sound when a burning candle is brought near it.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><strong>3.<\/strong><strong> Metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced chemical equation for the reaction if one of the compounds formed is calcium chloride.<br \/>\n<\/strong><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced chemical equation for the reaction if one of the compounds formed is calcium chloride.<br \/>\n<\/span><span style=\"color: #000000;\"><span id=\"MathJax-Element-1-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;O&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;3&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mi&gt;s&lt;\/mi&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;mo&gt;+&lt;\/mo&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;H&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;l&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;q&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-1\" aria-hidden=\"true\"><span id=\"MJXc-Node-2\"><span id=\"MJXc-Node-3\"><span id=\"MJXc-Node-4\"><span id=\"MJXc-Node-5\"><span id=\"MJXc-Node-6\">C<\/span><span id=\"MJXc-Node-7\">a<\/span><span id=\"MJXc-Node-8\">C<\/span><span id=\"MJXc-Node-9\">O<\/span><\/span><\/span><span id=\"MJXc-Node-10\"><span id=\"MJXc-Node-11\"><sub><span id=\"MJXc-Node-12\">3<\/span><\/sub><span id=\"MJXc-Node-13\">(<\/span><em><span id=\"MJXc-Node-14\">s<\/span><\/em><\/span><\/span><\/span><\/span><\/span><\/span><span id=\"MathJax-Element-1-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;O&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;3&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mi&gt;s&lt;\/mi&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;mo&gt;+&lt;\/mo&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;H&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;l&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;q&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-1\" aria-hidden=\"true\"><span id=\"MJXc-Node-2\"><span id=\"MJXc-Node-3\"><span id=\"MJXc-Node-10\"><span id=\"MJXc-Node-11\"><span id=\"MJXc-Node-15\">) <\/span><\/span><\/span><\/span><\/span><\/span><\/span><span id=\"MathJax-Element-1-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;O&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;3&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mi&gt;s&lt;\/mi&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;mo&gt;+&lt;\/mo&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;H&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;l&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;q&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-1\" aria-hidden=\"true\"><span id=\"MJXc-Node-2\"><span id=\"MJXc-Node-16\">+ <\/span><span id=\"MJXc-Node-17\">2<\/span><span id=\"MJXc-Node-18\"><span id=\"MJXc-Node-19\"><span id=\"MJXc-Node-20\"><span id=\"MJXc-Node-21\">H<\/span><span id=\"MJXc-Node-22\">C<\/span><span id=\"MJXc-Node-23\">l<\/span><\/span><\/span><span id=\"MJXc-Node-24\"><span id=\"MJXc-Node-25\"><span id=\"MJXc-Node-26\">(<\/span><em><span id=\"MJXc-Node-27\"><span id=\"MJXc-Node-28\"><span id=\"MJXc-Node-29\">a<\/span><span id=\"MJXc-Node-30\">q<\/span><\/span><\/span><\/em><span id=\"MJXc-Node-31\">)\u00a0<\/span><\/span><\/span><\/span><\/span><\/span><\/span><span id=\"MathJax-Element-1-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;O&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;3&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mi&gt;s&lt;\/mi&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;mo&gt;+&lt;\/mo&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;H&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;l&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;q&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-1\" aria-hidden=\"true\"><span id=\"MJXc-Node-2\"><span id=\"MJXc-Node-18\"><span id=\"MJXc-Node-24\"><span id=\"MJXc-Node-25\"><span id=\"MJXc-Node-31\">\u2192 <\/span><\/span><\/span><\/span><\/span><\/span><\/span><span id=\"MathJax-Element-2-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;l&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;q&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-32\" aria-hidden=\"true\"><span id=\"MJXc-Node-33\"><span id=\"MJXc-Node-34\"><span id=\"MJXc-Node-35\"><span id=\"MJXc-Node-36\"><span id=\"MJXc-Node-37\">\u00a0C<\/span><span id=\"MJXc-Node-38\">a<\/span><span id=\"MJXc-Node-39\">C<\/span><span id=\"MJXc-Node-40\">l<\/span><\/span><\/span><span id=\"MJXc-Node-41\"><span id=\"MJXc-Node-42\"><sub><span id=\"MJXc-Node-43\">2<\/span><\/sub><span id=\"MJXc-Node-44\">(<\/span><em><span id=\"MJXc-Node-45\"><span id=\"MJXc-Node-46\"><span id=\"MJXc-Node-47\">a<\/span><span id=\"MJXc-Node-48\">q<\/span><\/span><\/span><\/em><span id=\"MJXc-Node-49\">)<\/span><\/span><\/span><\/span><\/span><\/span><\/span><span id=\"MathJax-Element-2-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;l&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;a&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;q&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-32\" aria-hidden=\"true\"><span id=\"MJXc-Node-33\"><span id=\"MJXc-Node-34\"><span id=\"MJXc-Node-41\"><span id=\"MJXc-Node-42\"><span id=\"MJXc-Node-49\"><\/span><\/span><\/span><\/span><\/span><\/span><\/span>\u00a0+ <span id=\"MathJax-Element-3-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;C&lt;\/mi&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;O&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mi&gt;g&lt;\/mi&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-50\" aria-hidden=\"true\"><span id=\"MJXc-Node-51\"><span id=\"MJXc-Node-52\"><span id=\"MJXc-Node-53\"><span id=\"MJXc-Node-54\"><span id=\"MJXc-Node-55\">C<\/span><span id=\"MJXc-Node-56\">O<\/span><\/span><\/span><span id=\"MJXc-Node-57\"><span id=\"MJXc-Node-58\"><sub><span id=\"MJXc-Node-59\">2<\/span><\/sub><span id=\"MJXc-Node-60\">(<\/span><em><span id=\"MJXc-Node-61\">g<\/span><\/em><span id=\"MJXc-Node-62\">) <\/span><\/span><\/span><\/span><\/span><\/span><\/span>+ <span id=\"MathJax-Element-4-Frame\" tabindex=\"0\" role=\"presentation\" data-mathml=\"&lt;math xmlns=&quot;http:\/\/www.w3.org\/1998\/Math\/MathML&quot;&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;H&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mn&gt;2&lt;\/mn&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;msub&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mi mathvariant=&quot;normal&quot;&gt;O&lt;\/mi&gt;&lt;\/mrow&gt;&lt;mrow class=&quot;MJX-TeXAtom-ORD&quot;&gt;&lt;mo stretchy=&quot;false&quot;&gt;(&lt;\/mo&gt;&lt;mi&gt;l&lt;\/mi&gt;&lt;mo stretchy=&quot;false&quot;&gt;)&lt;\/mo&gt;&lt;\/mrow&gt;&lt;\/msub&gt;&lt;\/math&gt;\"><span id=\"MJXc-Node-63\" aria-hidden=\"true\"><span id=\"MJXc-Node-64\"><span id=\"MJXc-Node-65\"><span id=\"MJXc-Node-66\"><span id=\"MJXc-Node-67\"><span id=\"MJXc-Node-68\">H<\/span><\/span><\/span><sub><span id=\"MJXc-Node-69\"><span id=\"MJXc-Node-70\"><span id=\"MJXc-Node-71\">2<\/span><\/span><\/span><\/sub><\/span><span id=\"MJXc-Node-72\"><span id=\"MJXc-Node-73\"><span id=\"MJXc-Node-74\"><span id=\"MJXc-Node-75\">O<\/span><\/span><\/span><span id=\"MJXc-Node-76\"><span id=\"MJXc-Node-77\"><span id=\"MJXc-Node-78\">(<\/span><em><span id=\"MJXc-Node-79\">l<\/span><\/em><span id=\"MJXc-Node-80\">)<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"color: #ff0000; font-family: georgia, palatino, serif; font-size: 14pt;\"><strong>Questions<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>1.<\/strong><b> Why do HCl, HNO<sub>3\u00a0<\/sub>, etc., show acidic characters in aqueous solutions while solutions of compounds like alcohol and glucose do not show acidic character?<br \/>\n<\/b><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>The dissociation of HCI or\u00a0 HNO<sub>3<\/sub>\u00a0to form hydrogen ions always occurs in the presence of water. Hydrogen ions (H<sup>+<\/sup>) combine with H<sub>2<\/sub>O to form hydronium ions 3O<sup>+<\/sup><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">The reaction is as follows:<br \/>\n<\/span><span style=\"color: #000000;\">HCl(<em>aq<\/em>) \u27f6 H<sup>+ <\/sup>+ Cl<sup>\u2212<br \/>\n<\/sup><\/span><span style=\"color: #000000;\">H<sup>+ <\/sup>+ H<sub>2<\/sub>O \u27f6 H<sub>3<\/sub>O<sup>+<\/sup><\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>2. Why does an aqueous solution of an acid conduct electricity?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Acids dissociate in aqueous solutions to form ions. These ions are responsible for conduction of electricity.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>3. Why does dry HCl gas not change the colour of the dry litmus paper?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Colour of the litmus paper is changed by the hydrogen ions. Dry HCI gas does not contain H<sup>+<\/sup> ions. It is only in the aqueous solution that an acid dissociates to give ions. Since in this case, neither HCI is in the aqueous form nor the litmus paper is wet, therefore, the colour of the litmus paper does not change.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>4. While diluting an acid, why is it recommended that the acid should be added to water and not water to the acid?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Since the process of dissolving an acid in water is exothermic, it is always recommended that acid should be added to water. If it is done the other way, then it is possible that because of the large amount of heat generated, the mixture splashes out and causes burns.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>5. How is the concentration of hydronium ions H<sub>3<\/sub>O<sup>+<\/sup>\u00a0affected when a solution of an acid is diluted?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>When an acid is diluted, the concentration of hydronium ions H<sub>3<\/sub>O<sup>+<\/sup>\u00a0 per unit volume decreases. This means that the strength of the acid decreases.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>6. How is the concentration of hydroxide ions OH<sup>\u2212<\/sup>\u00a0 affected when excess base is dissolved in a solution of sodium hydroxide?<br \/>\n<\/b><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>The concentration of hydroxide ions OH<sup>\u2212<\/sup>\u00a0would increase when excess base is dissolved in a solution of sodium hydroxide.<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"color: #ff0000; font-family: georgia, palatino, serif; font-size: 14pt;\"><strong>Questions<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>1. You have two solutions, A and B. The pH of solution A is 6 and pH of solution B is 8. Which solution has more hydrogen ion concentration? Which of this is acidic and which one is basic?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>A pH value of less than 7 indicates an acidic solution, while greater than 7 indicates a basic solution. Therefore, the solution with pH = 6 is acidic and has more hydrogen ion concentration than the solution of pH = 8 which is basic.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>2. What effect does the concentration of H<sup>+<\/sup>\u00a0(aq) ions have on the nature of the solution?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>concentration of H<sup>+<\/sup>\u00a0(aq) can have a varied effect on the nature of the solution.With an increase in ion concentration, the solution becomes more acidic, while a decrease of H<sup>+<\/sup> ion causes an increase in the basicity of the solution.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>3. Do basic solutions also have H<sup>+<\/sup>(aq) ions? If yes, then why are these basic?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Yes, basic solution also has H<sup>+<\/sup>(aq) ions. However, their concentration is less as compared to the concentration of OH<sup>\u2212<\/sup> ions that makes the solution basic.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>4. Under what soil condition do you think a farmer would treat the soil of his fields with quick lime (calcium oxide) or slaked lime (calcium hydroxide) or chalk (calcium carbonate)?<br \/>\n<\/b><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>If the soil is acidic and improper for cultivation, then to increase the basicity of soil, the farmer would treat the soil with quicklime or slaked lime or chalk <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">2NaHCO<sub>3<\/sub>\u00a0\u27f6\u00a0 Na2CO<sub>3<\/sub>\u00a0+ H<sub>2<\/sub>O + CO<sub>2<\/sub><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"color: #ff0000; font-family: georgia, palatino, serif; font-size: 14pt;\"><strong>Questions<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>1. What is the common name of the compound CaOCl<sub>2<\/sub>?<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Bleaching powder.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>2. Name the substance which on treatment with chlorine yields bleaching powder.<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Slaked lime or calcium hydroxide.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>3. Name the sodium compound which is used for softening hard water.<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>Sodium carbonate is used for softening hard water.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>4. What will happen if a solution of sodium hydrocarbonate is heated? Give the equation of the reaction involved.<br \/>\n<\/b><strong>Answer<\/strong><strong> &#8211;\u00a0<\/strong>When a solution of sodium hydrocarbonate (sodium hydrogen carbonate) is heated, sodium carbonate and water are formed with the evolution of carbon dioxide gas.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><b>5. Write an equation to show the reaction between Plaster of Paris and water.<\/b><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Answer &#8211; <\/strong>The chemical equation for the reaction of Plaster of Paris and water is<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">CaSO<sub>4<\/sub>.1\/2H<sub>2<\/sub>O + 3\/2H<sub>2<\/sub>O\u00a0\u2192\u00a0CaSO<sub>4<\/sub>.2H<sub>2<\/sub>O<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"color: #ff0000; font-family: georgia, palatino, serif;\"><strong><span style=\"font-size: 14pt;\">Exercise<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>1. A solution turns red litmus blue, its pH is likely to be<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(a) 1<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(b) 4<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(c) 5<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(d) 10<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>(d) <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>2. A solution reacts with crushed egg-shells to give a gas that turns lime-water milky. The solution contains<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(a) NaCl<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(b) HCl<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(c) LiCl<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(d) KCl<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>(b)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>3. 10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(a) 4 mL<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(b) 8 mL<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(c) 12 mL<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(d) 16 mL<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>(d) <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>4. Which one of the following types of medicines is used for treating indigestion?<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(a) Antibiotic<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(b) Analgesic<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(c) Antacid<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">(d) Antiseptic<br \/>\n<\/span><span style=\"color: #000000;\"><strong>Answer &#8211; <\/strong>(c) Antacid is used for treating indigestion.<\/span><\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>5. Write word equations and then balanced equations for the reaction taking place when &#8211;<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>(a)<\/strong> dilute sulphuric acid reacts with zinc granules.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211;\u00a0<\/strong>Zinc + Sulphuric acid\u00a0 Zinc sulphate + Hydrogen<br \/>\nH<sub>2<\/sub>SO4(aq) + Zn(s)\u00a0 \u27f6 ZnSO<sub>4<\/sub>(aq) + H<sub>2<\/sub>\u00a0(g)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>(b)<\/strong> dilute hydrochloric acid reacts with magnesium ribbon.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211;\u00a0<\/strong>Magnesium +\u00a0 Sulphuric acid\u00a0 magnesium chloride +Hydrogen gas<br \/>\nMg <em>(s)<\/em> + 2HCl <em>(aq)<\/em> \u2192 MgCl<sub>2 <\/sub><em>(aq)<\/em> + H<sub>2 <\/sub><em>(g)<\/em><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>(c)<\/strong> dilute sulphuric acid reacts with aluminium powder.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211;\u00a0<\/strong>Aluminum + Sulphuric acid\u00a0 Aluminum sulphate +Hydrogen gas<br \/>\n3H<sub>2<\/sub>SO<sub>4<\/sub>\u00a0+ 2Al \u2192 Al<sub>2 <\/sub>(SO<sub>4<\/sub>)<sub>3<\/sub>\u00a0+ 3H2<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>(d)<\/strong> dilute hydrochloric acid reacts with iron filings.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><strong>Answer &#8211; <\/strong><\/span><span style=\"color: #000000;\">Iron + Hydrochloric acid\u00a0 Iron chloride + Hydrogen<\/span><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">6HCl <em>(aq)<\/em> + 3Fe<em>(s)<\/em> \u2192 3FeCl<sub>2 <\/sub><em>(aq)<\/em> + 3H<sub>2 <\/sub><em>(g)<\/em><\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>6. Compounds such as alcohols and glucose also contain hydrogen but are not categorised as acids. Describe an Activity to prove it.<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><strong>Answer &#8211; <\/strong>A<\/span><span style=\"color: #000000;\">lcohol and glucose both contain hydrogen but not categorized as acids. This can be proved by following activity.<\/span><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-7264\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/12\/NCERT-Class-10-Science-Solution-Ch-2-Q.6.png\" alt=\"NCERT Class 10 Science Solution\" width=\"229\" height=\"255\" \/><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Material required :-<\/strong>\u00a0Beaker, nails, battery, connecting wires, bulb, switch and alcohols.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Procedure :<\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">1. Set up the experiment as follows<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">2. Take ethyl alcohol in the beaker in the beaker.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">3. When the switch is turned on, the bulb does not glow.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">4. Take glucose solution in place of alcohols but bulb does not glow.<\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>7. Why does distilled water not conduct electricity, whereas rain water does?<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>Distilled water is a pure form of water and is devoid of any ionic species. Therefore, it does not conduct electricity. Rain water, being an impure form of water, contains many ionic species such as acids and therefore it conducts electricity.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>8. Why do acids not show acidic behaviour in the absence of water?<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>Acids do not show acidic behaviour in the absence of water because the dissociation of hydrogen ions from an acid occurs in the presence of water only. It is the hydrogen ions that are responsible for the acidic behaviour.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>9. Five solutions A, B, C, D and E when tested with universal indicator showed pH as 4, 1, 11, 7 and 9, respectively. Which solution is<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(a) neutral?<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(b) strongly alkaline?<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(c) strongly acidic?<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(d) weakly acidic?<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(e) weakly alkaline?<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">Arrange the pH in increasing order of hydrogen-ion concentration<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><strong>Answer &#8211;<br \/>\n<\/strong><\/span><span style=\"color: #000000;\">(a) D<\/span><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(b) C<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(c) B<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(d) A<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(e) E<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>10. Equal lengths of magnesium ribbons are taken in test tubes A and B. Hydrochloric acid (HCl) is added to test tube A, while acetic acid (CH<sub>3<\/sub>COOH) is added to test tube B. Amount and concentration taken for both the acids are same. In which test tube will the fizzing occur more vigorously and why?<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>HCl is stronger acid than CH<sub>3<\/sub>COOH. Therefore, H+ ions concentration in test tube A will be more than that in test tube B. hence, reaction will take place faster in test tube A than in test tube B. so, fizzing will occur more vigorously in test tube B.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><b>11. Fresh milk has a pH of 6. How do you think the pH will change as it turns into curd? Explain your answer.<br \/>\n<\/b><\/span><span style=\"color: #000000;\"><strong>Answer &#8211; <\/strong>The pH of milk is 6. As it changes to curd, the pH will reduce because curd is acidic in nature. The acids present in it decrease the PH.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>12. A milkman adds a very small amount of baking soda to fresh milk.<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>(a)<\/strong> Why does he shift the pH of the fresh milk from 6 to slightly alkaline?<br \/>\n<strong>Answer &#8211; <\/strong>The milkman shifts the pH of the fresh milk from 6 to slightly alkaline because in alkaline condition, milk does not set as curd easily.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> Why does this milk take a long time to set as curd?<br \/>\n<\/span><span style=\"color: #000000;\"><strong>Answer &#8211; <\/strong>Since this milk is slightly basic than usual milk, acids produced to set the curd are neutralized by the base. Therefore, it takes a longer time for the curd to set.<\/span><\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>13. Plaster of Paris should be stored in a moisture-proof container. Explain why?<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; <\/strong>Plaster of Paris reacts with moisture to form gypsum and sets to a hard mass. Therefore, it should be stored in moisture-proof container.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>14. What is a neutralisation reaction? Give two examples.<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\"><strong>Answer &#8211;<br \/>\n(i)<\/strong> A reaction in which an acid and base react with each other to give a salt and water is termed as neutralization reaction. In this reaction, energy is evolved in the form of heat.<br \/>\n<\/span><span style=\"color: #000000;\"><strong>For example :-<\/strong> NaOH + HCl \u27f6 NaCl+H<sub>2<\/sub>O<br \/>\n<\/span><span style=\"color: #000000;\"><strong>(ii)<\/strong> During indigestion (caused due to the production of excess of hydrochloric acid in the stomach), we administer an antacid (generally milk of magnesia, Mg(OH)2 which is basic in nature). The antacid neutralizes the excess of acids and thus gives relief from indigestion.<\/span><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">Mg(OH)<sub>2<\/sub>\u00a0+ 2HCl \u2192 MgCl<sub>2<\/sub>+2H<sub>2<\/sub>O<\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><b>15. Give two important uses of washing soda and baking soda.<\/b><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Answer &#8211; Uses of washing soda :<\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(i) As cleansing agent.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(ii) Removing permanent hardness of water.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">(iii) Used in glass, soap and paper industries.<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Uses of baking soda :<\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">(i) For making baking powder<br \/>\n<\/span><span style=\"color: #000000;\">(ii) As ingredient of antacid.<\/span><\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-science\" target=\"_blank\" rel=\"noopener\"><b><i>Go Back To Chapters<\/i><\/b><\/a><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 10 Science\u00a0 The NCERT Solutions in English Language for Class 10 Science Chapter &#8211; 2 (Acids Bases and Salts) has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter &#8211; 2 (Acids Bases and Salts)\u00a0 Questions 1. You have been provided with three test tubes. One [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1125],"tags":[1385,1133,1390,1389,1388,5],"class_list":["post-6886","post","type-post","status-publish","format-standard","hentry","category-class-10-science","tag-class-10-ncert-science-solutions","tag-class-10-ncert-solutions","tag-ncert-class-10-science-chapter-2-acids-bases-and-salts","tag-ncert-class-10-science-chapter-2-solutions","tag-ncert-class-10-science-solutions","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 10 (Science) Chapter 2 (Acids Bases and Salts) | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 10 Science\u00a0The NCERT Solutions in English 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