{"id":6062,"date":"2023-08-19T07:54:56","date_gmt":"2023-08-19T07:54:56","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=6062"},"modified":"2023-08-19T07:54:56","modified_gmt":"2023-08-19T07:54:56","slug":"ncert-solutions-class-10-maths-chapter-7-coordinate-geometry-ex-7-2","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-maths-chapter-7-coordinate-geometry-ex-7-2\/","title":{"rendered":"NCERT Solutions Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2"},"content":{"rendered":"<h2 style=\"text-align: center;\"><strong><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 10 Maths\u00a0<\/span><\/strong><br \/>\n<strong><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 7 (Coordinate Geometry)\u00a0<\/span><\/strong><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 10 Mathematics <strong>Chapter &#8211; 7 Coordinate Geometry <\/strong>Exercise 7.2 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #ff0000;\"><strong>Chapter : 7 Coordinate Geometry<\/strong> <\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-maths-chapter-7-coordinate-geometry-ex-7-1\" target=\"_blank\" rel=\"noopener\">NCERT Class 10 Maths Solution Ex &#8211; 7.1<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-maths-chapter-7-coordinate-geometry-ex-7-3\" target=\"_blank\" rel=\"noopener\">NCERT Class 10 Maths Solution Ex &#8211; 7.3<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-maths-chapter-7-coordinate-geometry-ex-7-4\" target=\"_blank\" rel=\"noopener\">NCERT Class 10 Maths Solution Ex &#8211; 7.4<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><strong><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 7.2<\/span><\/strong><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Find the coordinates of the point which divides the join of (- 1, 7) and (4, \u2013 3) in the ratio 2:3.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>Let P(x, y) be the required point. Using the section formula, we get<br \/>\nx = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(2&amp;space;\\times&amp;space;4&amp;space;+&amp;space;3&amp;space;\\times&amp;space;(-1))}{(2&amp;space;+&amp;space;3)}\" alt=\"\\frac{(2 \\times 4 + 3 \\times (-1))}{(2 + 3)}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{8-3}{5}\" alt=\"\\frac{8-3}{5}\" align=\"absmiddle\" \/> = 1<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">y = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(2&amp;space;\\times&amp;space;-3&amp;space;+&amp;space;3&amp;space;\\times&amp;space;7)}{(2&amp;space;+&amp;space;3)}\" alt=\"\\frac{(2 \\times -3 + 3 \\times 7)}{(2 + 3)}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-6+21}{5}\" alt=\"\\frac{-6+21}{5}\" align=\"absmiddle\" \/> = 3<br \/>\nTherefore, the point is (1, 3).<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3).<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;\u00a0<\/strong>Let P (x<sub>1<\/sub>, y<sub>1<\/sub>) and Q (x<sub>2<\/sub>, y2) be the points of trisection of the line segment joining the given points,<br \/>\ni.e. AP = PQ = QB<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6445\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans2.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"265\" height=\"62\" \/><br \/>\nTherefore, point P divides AB internally in the ratio 1 : 2.<br \/>\nx<sub>1\u00a0<\/sub>= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(1&amp;space;\\times&amp;space;(-2)&amp;space;+&amp;space;2&amp;space;\\times4)}{3}\" alt=\"\\frac{(1 \\times (-2) + 2 \\times4)}{3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-2&amp;space;+8}{3}\" alt=\"\\frac{-2 +8}{3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{6}{3}\" alt=\"\\frac{6}{3}\" align=\"absmiddle\" \/> = 2<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">y<sub>1<\/sub> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(1\\times(-3)+2\\times(-1))}{1+2}\" alt=\"\\frac{(1\\times(-3)+2\\times(-1))}{1+2}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-3-2}{3}\" alt=\"\\frac{-3-2}{3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-5}{3}\" alt=\"\\frac{-5}{3}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Therefore : P (x<sub>1<\/sub>, y<sub>1<\/sub>) = P(2, <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-5}{3}\" alt=\"\\frac{-5}{3}\" align=\"absmiddle\" \/>)<br \/>\nPoint Q divides AB internally in the ratio 2 : 1.<br \/>\nx<sub>2<\/sub> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(2\\times&amp;space;(-2)&amp;space;+1\\times&amp;space;4)}{2+1}\" alt=\"\\frac{(2\\times (-2) +1\\times 4)}{2+1}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-4+4}{3}\" alt=\"\\frac{-4+4}{3}\" align=\"absmiddle\" \/> = 0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">y<sub>2<\/sub> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(2\\times&amp;space;(-3)+1\\times(-1))}{2+1}\" alt=\"\\frac{(2\\times (-3)+1\\times(-1))}{2+1}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-6-1}{3}\" alt=\"\\frac{-6-1}{3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-7}{3}\" alt=\"\\frac{-7}{3}\" align=\"absmiddle\" \/><br \/>\nThe coordinates of the point Q are (0, <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-7}{3}\" alt=\"\\frac{-7}{3}\" align=\"absmiddle\" \/>)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. To conduct sports day activities in your rectangular-shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1 m each. 100 flower pots have been placed at a distance of 1 m from each other along AD, as shown in the following figure. Niharika runs 1\/4<sup>th<\/sup> the distance AD on the 2nd line and posts a green flag. Preet runs 1\/5<sup>th<\/sup> the distance AD on the eighth line and posts a red flag. What is the distance between both flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6446\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Que3.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"380\" height=\"496\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Que3.png 380w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Que3-230x300.png 230w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Que3-300x392.png 300w\" sizes=\"auto, (max-width: 380px) 100vw, 380px\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>From the given instruction, we observed that Niharika posted the green flag at 1\/4<sup>th<\/sup> of the distance AD, i.e. (1\/4 \u00d7 100) m = 25 m from the starting point of the 2nd line. Therefore, the coordinates of this point are (2, 25).<br \/>\nSimilarly, Preet posted a red flag at 1\/5 of the distance AD, i.e. (1\/5 \u00d7 100) m = 20 m from the starting point of the 8th line. Therefore, the coordinates of this point are (8, 20).<br \/>\nDistance between these flags can be calculated by using the distance formula,<br \/>\n= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\sqrt{(8-2)^2&amp;space;+(20-25)^2}\" alt=\"\\sqrt{(8-2)^2 +(20-25)^2}\" align=\"absmiddle\" \/><br \/>\n= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\sqrt{36+25}\" alt=\"\\sqrt{36+25}\" align=\"absmiddle\" \/><br \/>\n= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\sqrt{61}\" alt=\"\\sqrt{61}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">The point at which Rashmi should post her blue flag is the mid-point of the line joining these points. Let\u2019s say this point is P(x, y).<br \/>\nx = (2 + 8)\/2 = 10\/2 = 5<br \/>\ny = (20 + 25)\/2 = 45\/2<br \/>\nHence, P(\u00a0<em>x<\/em>,\u00a0<em>y<\/em>) = (5, 45\/2)<br \/>\nTherefore, Rashmi should post her blue flag at 45\/2 = 22.5m on the 5th line.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Find the ratio in which the line segment joining the points (-3, 10) and (6, \u2013 8) is divided by (-1, 6). <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>Let the ratio in which the line segment joining ( -3, 10) and (6, -8) is divided by point ( -1, 6) be k : 1.<br \/>\nTherefore, -1 = 6<i>k<\/i>-3\/<i>k<\/i>+1<br \/>\n&#8211;<i>k<\/i>\u00a0&#8211; 1 = 6<i>k<\/i>\u00a0-3<br \/>\n7<i>k<\/i>\u00a0= 2<br \/>\n<i>k<\/i>\u00a0= 2\/7<br \/>\nTherefore, the required ratio is 2:7.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. Find the ratio in which the line segment joining A (1, \u2013 5) and B (- 4, 5) is divided by the x-axis. Also, find the coordinates of the point of division.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>Let the ratio in which the line segment joining A (1, &#8211; 5) and B ( &#8211; 4, 5) is divided by x-axis be k : 1.<br \/>\nTherefore, the coordinates of the point of division is (-4<i>k<\/i>+1\/<i>k<\/i>+1, 5<i>k<\/i>-5\/<i>k<\/i>+1).<br \/>\nWe know that y-coordinate of any point on x-axis is 0. <\/span><br \/>\n<span style=\"color: #000000;\">\u2234 5<i>k<\/i>-5\/<i>k<\/i>+1 = 0<br \/>\nTherefore,\u00a0<i>x<\/i>-axis divides it in the ratio 1 : 1.<\/span><br \/>\n<span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6447\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans5.png\" alt=\"\" width=\"472\" height=\"49\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans5.png 472w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans5-300x31.png 300w\" sizes=\"auto, (max-width: 472px) 100vw, 472px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. If (1, 2), (4,\u00a0<em>y<\/em>), (<em>x<\/em>, 6) and (3, 5) are the vertices of a parallelogram taken in order, find\u00a0<em>x\u00a0<\/em>and\u00a0<em>y<\/em>.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6448\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans6.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"320\" height=\"157\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans6.png 320w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans6-300x147.png 300w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><br \/>\nLet A,B,C and D be the points (1,2) (4,<i>y<\/i>), (<i>x<\/i>,6) and (3,5) respectively.<br \/>\nMid point of diagonal AC is O =\u00a0 ((1 + x)\/2 , (2 + 6)\/2) = ((1 + x)\/2 , 4)<br \/>\nMidpoint of diagonal BD is O = ((4 + 3)\/2 , (5 + y)\/2 ) = (7\/2 , (5 + y)\/2)<br \/>\nSince the diagonals of a parallelogram bisect each other, the mid point of AC and BD are same. <\/span><br \/>\n<span style=\"color: #000000;\">\u2234 (<i>x <\/i>+ 1)\/2 = 7\/2 and 4 = (5 + <i>y)<\/i>\/2<\/span><br \/>\n<span style=\"color: #000000;\">\u21d2\u00a0<i>x<\/i>\u00a0+ 1 = 7 and 5\u00a0+\u00a0<i>y<\/i>\u00a0= 8<br \/>\n\u21d2\u00a0<i>x<\/i>\u00a0= 6 and\u00a0<i>y<\/i>\u00a0= 3<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. Find the coordinates of point A, where AB is the diameter of a circle whose centre is (2, \u2013 3) and B is (1, 4). <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>Let the coordinates of point A be (<em>x<\/em>,\u00a0<em>y<\/em>).<br \/>\nMidpoint of AB is (2, \u2013 3), which is the centre of the circle.<br \/>\nCoordinate of B = (1, 4)<br \/>\n(2, -3) =((x + 1)\/2 , (y + 4)\/2)<br \/>\n(x + 1)\/2 = 2 and (y + 4)\/2 = -3<br \/>\nx + 1 = 4 and y + 4 = -6<br \/>\nx = 3 and y = -10<br \/>\nThe coordinates of A(3, -10).<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8. If A and B are (-2, -2) and (2, -4), respectively, find the coordinates of P such that AP = 3\/7 AB and P lies on the line segment AB. <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6449\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans8.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"320\" height=\"32\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans8.png 320w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans8-300x30.png 300w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><br \/>\n<\/strong>The coordinates of points A and B are (-2,-2) and (2,-4), respectively.<br \/>\nSince AP = 3\/7 AB<br \/>\nTherefore,<br \/>\nAP : PB = 3 : 4<br \/>\nPoint P divides the line segment AB in the ratio 3 : 4.<br \/>\nCoordinate of P = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;(&amp;space;\\frac{3&amp;space;\\times&amp;space;2&amp;space;+4}{3+4},&amp;space;\\frac{3\\times(-4)+4\\times(-2)}{3+4}&amp;space;\\right&amp;space;)\" alt=\"\\left ( \\frac{3 \\times 2 +4}{3+4}, \\frac{3\\times(-4)+4\\times(-2)}{3+4} \\right )\" align=\"absmiddle\" \/><br \/>\n= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;(&amp;space;\\frac{6-8}{7},&amp;space;\\frac{-12-8}{7}&amp;space;\\right&amp;space;)\" alt=\"\\left ( \\frac{6-8}{7}, \\frac{-12-8}{7} \\right )\" align=\"absmiddle\" \/><br \/>\n= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;(&amp;space;\\frac{-2}{7},&amp;space;\\frac{-20}{7}&amp;space;\\right&amp;space;)\" alt=\"\\left ( \\frac{-2}{7}, \\frac{-20}{7} \\right )\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>9. Find the coordinates of the points which divide the line segment joining A (- 2, 2) and B (2, 8) into four equal parts.<br \/>\n<\/strong><strong>Solution &#8211; <\/strong>Draw a figure, line dividing by 4 points.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6450\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans9.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"464\" height=\"38\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans9.png 464w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans9-300x25.png 300w\" sizes=\"auto, (max-width: 464px) 100vw, 464px\" \/><br \/>\nFrom the figure, it can be observed that points X, Y, Z are dividing the line segment in a ratio 1 : 3, 1 : 1, 3 : 1 respectively.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6451\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans9i.png\" alt=\"\" width=\"297\" height=\"194\" \/><br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>10. Find the area of a rhombus if its vertices are (3, 0), (4, 5), (-1, 4), and (-2,-1) taken in order.<br \/>\n<\/strong><strong>[Hint: Area of a rhombus = 1\/2 (product of its diagonals) <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6452\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans10.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"320\" height=\"202\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans10.png 320w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans10-300x189.png 300w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><br \/>\n<\/strong>Let (3, 0), (4, 5), ( &#8211; 1, 4) and ( &#8211; 2, &#8211; 1) are the vertices A, B, C, D of a rhombus ABCD.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-6453\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans10i.png\" alt=\"NCERT Class 10 Maths Solution\" width=\"334\" height=\"147\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans10i.png 334w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/08\/NCERT-Class-10-Maths-Ex7.2-Ans10i-300x132.png 300w\" sizes=\"auto, (max-width: 334px) 100vw, 334px\" \/><br \/>\n<\/span><\/p>\n<p><span style=\"color: #0000ff; font-family: Georgia, Palatino;\"><b><i><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-10-maths\/\">Go Back To Chapters<\/a><\/i><\/b><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 10 Maths\u00a0 Chapter &#8211; 7 (Coordinate Geometry)\u00a0 The NCERT Solutions in English Language for Class 10 Mathematics Chapter &#8211; 7 Coordinate Geometry Exercise 7.2 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 7 Coordinate Geometry NCERT Class 10 Maths Solution Ex &#8211; 7.1 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1043],"tags":[1045,1086,1088,1044,1049,1048],"class_list":["post-6062","post","type-post","status-publish","format-standard","hentry","category-class-10-maths","tag-class-10-ncert-mathematics-solutions","tag-ncert-class-10-mathematics-chapter-7-coordinate-geometry-solutions","tag-ncert-class-10-mathematics-exercise-7-2-solutions","tag-ncert-class-10-mathematics-solutions-class-10-ncert-solutions","tag-ncert-solutions-class-10-mathematics","tag-ncert-solutions-class-10-maths"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - 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