{"id":559,"date":"2022-08-17T02:49:28","date_gmt":"2022-08-17T02:49:28","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=559"},"modified":"2024-02-21T06:32:15","modified_gmt":"2024-02-21T06:32:15","slug":"ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-2","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-2\/","title":{"rendered":"NCERT Solutions Class 6 Maths Chapter 11 Algebra Ex 11.2"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">NCERT Solutions Class 6 Maths<\/span><\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Chapter &#8211; 11 (Algebra)<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 6 Mathematics <strong>Chapter &#8211; 11 Algebra <\/strong>Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.<\/span><\/p>\n<h4 id=\"chapter-11\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span id=\"Chapter_11_Algebra\" style=\"color: #000000;\">Chapter 11: Algebra<\/span><\/strong><\/span><\/h4>\n<ul>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 11.1<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 11.3<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 11.4<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-5\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 11.5<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Exercise &#8211; 11.2<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>1. The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">Side of equilateral triangle = l<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">Perimeter = l + l + l<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">= 3l<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>2. The side of the regular hexagon (Fig 11.10) is denoted by l. Express the perimeter of the hexagon using l.<br \/>\n<\/strong><strong>(Hint: A regular hexagon has all its six sides equal in length.)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-577\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-11.2Q2.png\" alt=\"NCERT Class 6 Math Solution\" width=\"130\" height=\"160\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">Side of a regular hexagon = l<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">Perimeter = l + l + l + l + l + l<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">= 6l<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>3. A cube is three dimensional figure as shown in Fig 11.11. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-579\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-11.2Q3.png\" alt=\"NCERT Class 6 Math Solution\" width=\"154\" height=\"156\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of an edge of the cube = l<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Number of edges = 12<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Total length of the edges = Number of edges \u00d7 length of an edge<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">=12l<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>4. The diameter of a circle is a line which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure (Fig 11.2) AB is a diameter of a circle; C is its centre.) Express the diameter of the circle (d) in terms of its radius (r).<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-578\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-11.2Q4.png\" alt=\"NCERT Class 6 Math Solution\" width=\"150\" height=\"160\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Diameter = AB<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= AC + CB<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= r + r<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2r<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Hence, the diameter of the circle in terms of its radius is 2r<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>5. To find sum of three numbers 14, 27 and 13 we can have two ways:<br \/>\n<\/strong>(a) We may first add 14 and 27 to get 41and then add 13 to it to get the total sum 54 or<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus, (14 + 27) + 13 = 14 + (27 + 13)<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">This can be done for any three numbers. This property is known as the\u00a0<strong>associativity of the addition of<\/strong><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>numbers<\/strong>. Express this property which we have already studied in the chapter on Whole Numbers, in a general way, by using variables a, b and c.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions :<\/strong><\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Let a, b and c be three variables, each of which can take any numerical value. Then. (a + b) + c = a + (b + c)<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">This property is known as the<strong>\u00a0associativity of the addition of numbers.<\/strong><\/span><\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 100%; background-color: #f2e079; text-align: center;\"><span style=\"color: #000000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong>NCERT Class 6<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 6 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-hindi\/\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Hindi<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Maths<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-sanskrit\/\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\">NCERT Solutions Class 6 Sanskrit<\/span><\/strong><\/span><\/a><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 6 Maths Chapter &#8211; 11 (Algebra) The NCERT Solutions in English Language for Class 6 Mathematics Chapter &#8211; 11 Algebra Exercise 11.2 has been provided here to help the students in solving the questions from this exercise. Chapter 11: Algebra NCERT Solution Class 6 Maths Exercise &#8211; 11.1 NCERT Solution Class 6 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[25,26,4,5],"class_list":["post-559","post","type-post","status-publish","format-standard","hentry","category-class-6-maths","tag-chapter-11-algebra-in-english","tag-ncert-solutions-class-6-maths-chapter-11-in-english","tag-ncert-solutions-class-6-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.5) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 6 Maths Chapter 11 Algebra Ex 11.2 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 11 Algebra Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-11-algebra-ex-11-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions Class 6 Maths Chapter 11 Algebra Ex 11.2\" \/>\n<meta property=\"og:description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 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