{"id":530,"date":"2022-08-14T13:12:51","date_gmt":"2022-08-14T13:12:51","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=530"},"modified":"2024-02-21T06:31:44","modified_gmt":"2024-02-21T06:31:44","slug":"ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-3","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-3\/","title":{"rendered":"NCERT Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.3"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">NCERT Solutions Class 6 Maths<\/span><\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Chapter &#8211; 10 (Mensuration)<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 6 Mathematics <strong>Chapter &#8211; 10 Mensuration <\/strong>Exercise 10.3 has been provided here to help the students in solving the questions from this exercise.<\/span><\/p>\n<h4 id=\"chapter-10\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span id=\"Chapter_10_Mensuration\" style=\"color: #000000;\">Chapter 10: Mensuration<\/span><\/strong><\/span><\/h4>\n<ul>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 10.1<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 10.2<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Exercise &#8211; 10.3<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>1. Find the area of the rectangles whose sides are:<br \/>\n<\/strong>(a) 3 cm and 4 cm<br \/>\n(b) 12 m and 21 m<br \/>\n(c) 2 km and 3 km<br \/>\n(d) 2 m and 70 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong>\u00a0Area of the rectangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= Length \u00d7 Breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 3 \u00d7 4 sq cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 12 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong>\u00a0Area of the rectangle <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= Length \u00d7 Breadth<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 12 m \u00d7 21 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 252 sq m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong>\u00a0Area of the rectangle <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= Length \u00d7 Breadth<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 km \u00d7 3 km <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 6 sq km<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(d)<\/strong>\u00a02 m = 2 \u00d7 100 cm = 200 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangle <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= Length \u00d7 Breadth<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 200 cm \u00d7 70 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 14000 sq cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>2. Find the areas of the squares whose sides are:<br \/>\n<\/strong><strong>(a) 10 cm<br \/>\n<\/strong><strong>(b) 14 cm<br \/>\n<\/strong><strong>(c) 5 m<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong> Area of the square = Side \u00d7 Side<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 10 cm \u00d7 10 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 100 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong> Area of the square = Side \u00d7 Side<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 14 cm \u00d7 14 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 196 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong> Area of the square = Side \u00d7 Side<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 5 m \u00d7 5 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 25 sq m.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>3. The length and breadth of three rectangles are as given below:<br \/>\n<\/strong>(a) 9 m and 6 m<br \/>\n(b) 17 m and 3 m<br \/>\n(c) 4 m and 14 m<br \/>\nWhich one has the largest area and which one has the smallest?<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong>\u00a0Area of the rectangle = Length \u00d7 Breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 9 m \u00d7 6 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 54 sq m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong>\u00a0Length of the rectangle = Length \u00d7 Breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 3 m \u00d7 17 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 51 sq m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong>\u00a0Length of the rectangle = Length \u00d7 Breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 4m \u00d7 14m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 56 sq m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of rectangle 56 sq m i.e <strong>(c)<\/strong> is the largest area and area of rectangle 51 sq m i.e <strong>(b)<\/strong> is the smallest area<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>4. The area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangular garden = 300 sq m<br \/>\nLength of the rectangular garden = 50 m<br \/>\nArea of rectangle = length \u00d7 width<br \/>\n300 = 50 \u00d7 width<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">width = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{300}{50}\" alt=\"\\frac{300}{50}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">width = 6 m<br \/>\n\u2234 The width of the garden is 6 m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>5. What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of \u20b9 8 per hundred sq m.?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of the rectangular piece of land = 500 m<br \/>\nBreadth of the rectangular piece of land = 200 m<br \/>\n\u2234 Area of the rectangular piece of land = Length \u00d7 Breadth<br \/>\n= 500 m \u00d7 200 m<br \/>\n= 100000 sq m<br \/>\nCost of tiling 100 sq m = \u20b9 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{8}{100}\" alt=\"\\frac{8}{100}\" align=\"absmiddle\" \/><\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Cost of tiling 100000 sq m = \u20b9 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{8}{100}\" alt=\"\\frac{8}{100}\" align=\"absmiddle\" \/> x 100000 \u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= \u20b9 8000<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>6. A table top measures 2 m by 1 m 50 cm. What is its area in square metres?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of the table-top = 2 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Breadth of the table-top = 1 m 50 cm = 1.50 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the table-top = Length \u00d7 Breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 m \u00d7 1.50 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 3.0 sq m.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>7. A room is 4 m long and 3 m 50 cm wide. Howe many square metres of carpet is needed to cover the floor of the room?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of the room = 4 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Breadth of the room = 3 m 50 cm = 3.50 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the room = Length \u00d7 Breadth<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 4 \u00d7 3.5 sq. m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 14.0 sq m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Hence, 14.0 square meters of carpet is needed to cover the floor of the room.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>8. A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of the floor = 5 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Breadth of the floor = 4 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the floor = Length \u00d7 Breadth<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 5m \u00d7 4m = 20sqm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the square carpet = Side \u00d7 Side <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 3m \u00d7 3m = 9sqm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the floor that is not carpeted = Area of the floor &#8211; Area of the square carpet<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 20 sq m \u2013 9 sq m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 11sq m.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>9. Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of square flower bed = Side \u00d7 Side <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 1 m \u00d7 1 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 1 sq m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of 5 square flower beds <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 5 \u00d7 1 sq m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 5 sq m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of the piece of land = 5 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Breadth of the piece of land = 4 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the piece of land = Length \u00d7 Breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 5 m \u00d7 4 m <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 20 sq m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the remaining part of the land <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 20 sq m \u2013 5 sq m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 15 sqm.<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Remaining part of the land is 15 m<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>10. By splitting the following figures into rectangles, find their areas (The measures are given in centimetres).<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-547\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10.png\" alt=\"NCERT Class 6 Math Solution\" width=\"405\" height=\"157\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10.png 405w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10-300x116.png 300w\" sizes=\"auto, (max-width: 405px) 100vw, 405px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)\u00a0<\/strong>Splitting the given figure into the rectangles I, II, III and IV, we have<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-548\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10AAns.png\" alt=\"NCERT Class 6 Math Solution\" width=\"238\" height=\"209\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10AAns.png 355w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10AAns-300x264.png 300w\" sizes=\"auto, (max-width: 238px) 100vw, 238px\" \/><br \/>\nArea of the rectangle I = length x breadth<br \/>\n= 3 cm x 3 cm<br \/>\n= 9 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangle II = length x breadth<br \/>\n= 1 cm x 2 cm<br \/>\n= 2 sq cm.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangle III = length x breadth<br \/>\n= 3 cm x 3 cm<br \/>\n= 9 sq cm<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangle IV = length x breadth<br \/>\n= 4 cm x 2 cm<br \/>\n= 8 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Total area of the whole figure<br \/>\n= 9 sq cm + 2 sq cm + 9 sq cm + 8 sq cm<br \/>\n= 28 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b) <\/strong>Splitting the given figure into the rectangles I, II and III, we get<strong><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-549\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q10BAns.png\" alt=\"NCERT Class 6 Math Solution\" width=\"192\" height=\"145\" \/><\/strong><\/span><\/p>\n<p><span style=\"font-family: georgia, palatino, serif;\">Area of the rectangle I = 12 cm x 2 cm<br \/>\n= 24 sq cm<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangle II = 8 cm x 2 cm<br \/>\n= 16 sq cm <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of rectangle III = 3 cm x 1 cm<br \/>\n= 3 sq cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Total area of the given figure = 3 sq cm + 3 sq cm + 3 sq cm = 9 sq cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>11. Split the following shapes into rectangles and find their areas. (The measures are given in centimetres)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-550 size-full\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11.png\" alt=\"NCERT Class 6 Math Solution\" width=\"433\" height=\"160\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11.png 433w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11-300x111.png 300w\" sizes=\"auto, (max-width: 433px) 100vw, 433px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)\u00a0<\/strong>Splitting the given figure into the rectangles I and II, we get.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-551\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11AAns.png\" alt=\"NCERT Class 6 Math Solution\" width=\"168\" height=\"156\" \/><br \/>\nArea of the rectangle I = 12 cm x 2 cm<br \/>\n= 24 sq cm<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the rectangle II = 8 cm x 2 cm<br \/>\n= 16 sq cm<br \/>\n<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Total area of the whole figure = 24 sq cm + 16 sq cm = 40 sq cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-552\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11BAns.png\" alt=\"NCERT Class 6 Math Solution\" width=\"160\" height=\"160\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11BAns.png 336w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11BAns-300x300.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11BAns-150x150.png 150w\" sizes=\"auto, (max-width: 160px) 100vw, 160px\" \/><br \/>\n<\/strong>There are 5 squares. Each side is 7 cm<br \/>\nArea of 5 squares = 5\u00a0 (7 cm x 7 cm)<br \/>\n= 5 x 49 sq cm<br \/>\n= 245 sq cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-553\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.3Q11CAns.png\" alt=\"NCERT Class 6 Math Solution\" width=\"175\" height=\"133\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Area of the shape = ( 5 \u00d7 1 + 4 \u00d7 1) sq cm<br \/>\n= (5 + 4) sq cm<br \/>\n= 9 sq cm.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>12. How many tiles whose length and breadth are 12 cm and 5 cm, respectively will be needed to fit in a rectangular region whose length and breadth are respectively?<br \/>\n<\/strong>(a) 100 cm and 144 cm<br \/>\n(b) 70 cm and 36 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of one tile = 12 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Breadth of the tile = 5 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of 1 tile = length x breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 12 cm x 5 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 60 sq cm<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong> Length of the rectangular region = 144 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Breadth of the region = 100 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Area of the rectangular region = length x breadth <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 144 cm x 100 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 14400 sq cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Number of tiles needed to cover the whole rectangular region <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 14400 sq cm \u00f7 60 sq cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 240 tiles<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Hence, 240 tiles are needed<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong><br \/>\nLength of the rectangular region = 70 cm<br \/>\nBreadth of the region = 36 cm<br \/>\n\u2234 Area of the rectangular region = length x breadth<br \/>\n= 70 cm x 36 cm<br \/>\n= 2520 sq cm<br \/>\n\u2234 Number of tiles needed to cover the whole rectangular region<br \/>\n= 2520 sq cm \u00f7 60 sq cm<br \/>\n= 42 tiles.<br \/>\nHence, 42 tiles are needed.<\/span><\/p>\n<p>&nbsp;<\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 100%; background-color: #f2e079; text-align: center;\"><span style=\"color: #000000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong>NCERT Class 6<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 6 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-hindi\/\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Hindi<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Maths<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-sanskrit\/\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\">NCERT Solutions Class 6 Sanskrit<\/span><\/strong><\/span><\/a><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 6 Maths Chapter &#8211; 10 (Mensuration) The NCERT Solutions in English Language for Class 6 Mathematics Chapter &#8211; 10 Mensuration Exercise 10.3 has been provided here to help the students in solving the questions from this exercise. Chapter 10: Mensuration NCERT Solution Class 6 Maths Exercise &#8211; 10.1 NCERT Solution Class 6 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[23,24,4,5],"class_list":["post-530","post","type-post","status-publish","format-standard","hentry","category-class-6-maths","tag-chapter-10-mensuration-in-english","tag-ncert-solutions-class-6-maths-chapter-10-in-english","tag-ncert-solutions-class-6-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.5) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.3 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 10 Mensuration Exercise 10.3 has been provided here to help the students in solving the questions from this exercise.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.3\" \/>\n<meta property=\"og:description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 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