{"id":527,"date":"2022-08-14T13:12:39","date_gmt":"2022-08-14T13:12:39","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=527"},"modified":"2024-02-21T06:26:35","modified_gmt":"2024-02-21T06:26:35","slug":"ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-1","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-1\/","title":{"rendered":"NCERT Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.1"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">NCERT Solutions Class 6 Maths<\/span><\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Chapter &#8211; 10 (Mensuration)<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 6 Mathematics <strong>Chapter &#8211; 10 Mensuration <\/strong>Exercise 10.1 has been provided here to help the students in solving the questions from this exercise.<\/span><\/p>\n<h4 id=\"chapter-10\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span id=\"Chapter_10_Mensuration\" style=\"color: #000000;\">Chapter 10: Mensuration<\/span><\/strong><\/span><\/h4>\n<ul>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 10.2<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 10.3<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Exercise &#8211; 10.1<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>1. Find the perimeter of each of the following figures:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-537\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q1.png\" alt=\"NCERT Class 6 Math Solution\" width=\"489\" height=\"414\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q1.png 489w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q1-300x254.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q1-480x406.png 480w\" sizes=\"auto, (max-width: 489px) 100vw, 489px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)\u00a0<\/strong>Perimeter = Sum of all the sides<br \/>\n= 4 cm + 2 cm + 1 cm + 5 cm<br \/>\n= 12 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong> Perimeter = Sum of all the sides<br \/>\n= 40 cm + 35 cm + 23 cm + 35 cm<br \/>\n= 133 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong> Perimeter = Sum of all the sides<br \/>\n= 15 cm + 15 cm + 15 cm + 15 cm<br \/>\n= 60 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(d)<\/strong> Perimeter = Sum of all the sides<br \/>\n= 4 cm + 4 cm + 4 cm + 4 cm + 4 cm<br \/>\n=20 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(e)<\/strong> Perimeter = Sum of all the sides<br \/>\n= 4 cm + 0.5 cm + 2.5 cm + 2.5 cm + 0.5 cm + 4 cm + 1 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 15 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(f)<\/strong> Perimeter = Sum of all the sides<br \/>\n= 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm + 4 cm + 1 cm + 3 cm + 2 cm + 3 cm<br \/>\n= 52 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>2. The lid of a rectangular box of sides 40 cm by 10 cm is sealed all around with tape. What is the length of the tape required?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of required tape = Perimeter of rectangle<br \/>\n= 2 (Length + Breadth)<br \/>\n= 2 (40 + 10) cm<br \/>\n= 2 (50) cm<br \/>\n= 2 x 50 cm<br \/>\n= 100 cm<br \/>\n\u2234 Required length of tape is 100 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>3. A table top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table top?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length of table top = 2 m 25 cm = 2.25 m<br \/>\nBreadth of table top = 1 m 50 cm = 1.50 m<br \/>\nPerimeter of table top = 2 (Length + Breadth)<br \/>\n= 2 (2.25 + 1.50) m<br \/>\n= 2 (3.75) m<br \/>\n= 2 \u00d7 3.75 m<br \/>\n= 7.5 m<br \/>\n\u2234 The perimeter of the table top is 7.5 m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>4. What is the length of the wooden strip required to frame a photograph of length and breadth 32 cm and 21 cm respectively?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Required length of wooden strip = Perimeter of photograph<br \/>\n= 2 (Length + Breadth)<br \/>\n= 2 (32 + 21) cm<br \/>\n= 2 (53) cm<br \/>\n= 2 \u00d7 53 cm<br \/>\n= 106 cm<br \/>\n\u2234 Required length of the wooden strip is 106 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>5. A rectangular piece of land measures 0.7 km by 0.5 km. Each side is to be fenced with 4 rows of wires. What is the length of the wire needed?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter of the field = 2 (Length + Breadth)<br \/>\n= 2 (0.7 + 0.5) km<br \/>\n= 2 (1.2) km<br \/>\n= 2 \u00d7 1.2 km<br \/>\n= 2.4 km<br \/>\nEach side is to be fenced with 4 rows = 4 \u00d7 2.4<br \/>\n= 9.6 km<br \/>\n\u2234 Total length of the required wire is 9.6 km<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>6. Find the perimeter of each of the following shapes:<br \/>\n<\/strong>(a) A triangle of sides 3 cm, 4 cm and 5 cm<br \/>\n(b) An equilateral triangle of side 9 cm<br \/>\n(c) An isosceles triangle with equal sides 8 cm each and third side 6 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong> We know that the perimeter of the given triangle = The sum of all sides of the triangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Perimeter of the triangle = 3 cm + 4 cm + 5 cm = 12 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong> We know that the perimeter of the given triangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= Sum of all the sides of the triangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= (9 + 9 + 9) = 27 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong> Perimeter of the given isosceles triangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= Sum of all the sides of the triangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= (8 + 8 + 6) cm = 22 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>7. Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter of a triangle = Sum of all the sides of the triangle<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 10 cm + 14 cm + 15 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 39 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 The perimeter of triangle is 39 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>8. Find the perimeter of a regular hexagon with each side measuring 8 m.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter of a regular hexagon = 6 x side = 6 x 8 m = 48 m.<br \/>\n\u2234 Perimeter of regular hexagon is 48 m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>9. Find the side of the square whose perimeter is 20 m.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter of a square = 4 x side<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">20 = 4 x side<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 side = 20 m \u00f7 4 = 5 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 The side of the square is 5 m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>10. The perimeter of a regular pentagon is 100 cm. How long is its each side?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter of the regular pentagon = 100 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Number of sides in regular pentagon = 5<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Length of each side = Perimeter \u00f7 Number of sides<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 100 cm \u00f7 5 = 20 cm.<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Side of the pentagon is 20 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>11. A piece of strings is 30 cm long. What will be the length of each side if the string is used to form:<br \/>\n<\/strong>(a) a square?<br \/>\n(b) an equilateral triangle?<br \/>\n(c) a regular hexagon?<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong> Length of string = 30 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Number of equal sides in a square = 4<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Length of each side of the square = 30 cm \u00f7 4 = 7.50 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong> Length of string = 30 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Number of equal sides in equilateral triangle = 3<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Length of each side of the equilateral triangle = 30 cm \u00f7 3 = 10 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong> Length of string = 30 cm<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Number of equal sides in regular hexagon = 6<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u2234 Length of each side of the regular hexagon = 30 cm \u00f7 6 = 5 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>12. Two sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is its third side?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Let x cm be the third side<br \/>\nPerimeter of triangle = 36 cm<br \/>\n12 + 14 + x = 36<br \/>\n26 + x = 36<br \/>\nx = 36 \u2013 26<br \/>\nx = 10 cm<br \/>\n\u2234 The third side is 10 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>13. Find the cost of fencing a square park of side 250 m at the rate of \u20b9 20 per metre.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Side of square = 250 m<br \/>\nPerimeter of square = 4 \u00d7 side<br \/>\n= 4 \u00d7 250<br \/>\n= 1000 m<br \/>\nCost of fencing = \u20b9 20 per m<br \/>\nCost of fencing for 1000 m = \u20b9 20 \u00d7 1000 = \u20b9 20,000<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>14. Find the cost of fencing a rectangular park of length 175 m and breadth 125 m at the rate of \u20b9 12 per metre.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Length = 175 m<br \/>\nBreadth = 125 m<br \/>\nPerimeter of rectangular park = 2 (Length + Breadth)<br \/>\n= 2 (175 + 125)<br \/>\n= 2 (300)<br \/>\n= 2 \u00d7 300<br \/>\n= 600 m<br \/>\nCost of fencing = 12 \u00d7 600 = 7200<br \/>\n\u2234 Cost of fencing is \u20b9 7,200<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>15. Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter of square = 4 \u00d7 side<br \/>\n= 4 \u00d7 75 m<br \/>\n= 300 m<br \/>\n\u2234 Distance covered by Sweety is 300 m<br \/>\nPerimeter of rectangular park = 2 (Length + Breadth)<br \/>\n= 2 (60 + 45) m<br \/>\n= 2 (105) m<br \/>\n= 2\u00a0<strong>\u00d7\u00a0<\/strong>105 m<br \/>\n= 210 m<br \/>\n\u2234 Distance covered by Bulbul is 210 m<br \/>\nHence, Bulbul covers less distance than Sweety.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>16. What is the perimeter of each of the each of the following figures? What do you infer from the the answers?<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-538\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q16.png\" alt=\"NCERT Class 6 Math Solution\" width=\"444\" height=\"214\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q16.png 444w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q16-300x145.png 300w\" sizes=\"auto, (max-width: 444px) 100vw, 444px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong> Perimeter of the square = 25 cm + 25 cm + 25 cm + 25 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 4 x 25 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 100 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong> Perimeter of the rectangle = 30 cm + 20 cm + 30 cm + 20 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 [30 cm + 20 cm] <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 x 50 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 100 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c)<\/strong> Perimeter of the rectangle = 40 cm + 10 cm + 40 cm + 10 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 [40 cm + 10 cm] <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 x 50 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 100 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(d)<\/strong> Perimeter of the triangle = Sum of all sides <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 30 cm + 30 cm + 40 cm <\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 100 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">All the figures have same perimeter.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>17. Avneet buys 9 square paving slabs, each with a side of <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mathbf{\\frac{1}{2}}\" alt=\"\\mathbf{\\frac{1}{2}}\" align=\"absmiddle\" \/> m. He lays them in the form of a square.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-539\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q17.png\" alt=\"NCERT Class 6 Math Solution\" width=\"225\" height=\"140\" \/><br \/>\n<\/strong>(a) What is the perimeter of his arrangement [fig 10.7(i)]?<br \/>\n(b) Shari does not like his arrangement. She gets him to lay them out like a cross. What is the perimeter of her arrangement [(Fig 10.7 (ii)]?<br \/>\n(c) Which has greater perimeter?<br \/>\n(d) Avneet wonders if there is a way of getting an even greater perimeter. Can you find a way of doing this? (The paving slabs must meet along complete edges i.e they cannot be broken.)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a)<\/strong>\u00a0Perimeter of his arrangement = 4 \u00d7 Length of one side<br \/>\n= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?4&amp;space;\\times&amp;space;\\left&amp;space;(&amp;space;\\frac{1}{2}&amp;space;+&amp;space;\\frac{1}{2}&amp;space;+&amp;space;\\frac{1}{2}\\right&amp;space;)\" alt=\"4 \\times \\left ( \\frac{1}{2} + \\frac{1}{2} + \\frac{1}{2}\\right )\" align=\"absmiddle\" \/> m<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?4&amp;space;\\times&amp;space;\\left&amp;space;(&amp;space;\\frac{3}{2}&amp;space;\\right&amp;space;)\" alt=\"4 \\times \\left ( \\frac{3}{2} \\right )\" align=\"absmiddle\" \/> m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 2 x 3 m<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 6 m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b)<\/strong> Perimeter of her arrangement = Sum of the lengths of all the sides.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?=&amp;space;\\frac{1}{2}&amp;space;m&amp;space;+&amp;space;1m&amp;space;+1m+\\frac{1}{2}m+1m+1m+\\frac{1}{2}m+1m+1m+\\frac{1}{2}m+1m+1m\" alt=\"= \\frac{1}{2} m + 1m +1m+\\frac{1}{2}m+1m+1m+\\frac{1}{2}m+1m+1m+\\frac{1}{2}m+1m+1m\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">= 8m + <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{4}{2}m\" alt=\"\\frac{4}{2}m\" align=\"absmiddle\" \/>\u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">= 8m + 2m\u00a0<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">= 10 m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">(c) Since 10 m &gt; 6 m<br \/>\n\u2234 Cross-arrangement has greater perimeter.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">(d) Yes ! there is a way of getting an even greater perimeter. It is shown below:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-540\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-10.1Q17a.png\" alt=\"NCERT Class 6 Math Solution\" width=\"281\" height=\"59\" \/><br \/>\nBecause side of a square = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{2}\" alt=\"\\frac{1}{2}\" align=\"absmiddle\" \/>m<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">Therefore Length = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{9}{2}\" alt=\"\\frac{9}{2}\" align=\"absmiddle\" \/>m and Breadth = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{2}\" alt=\"\\frac{1}{2}\" align=\"absmiddle\" \/>m<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Perimeter = 2 (Length + Breadth)<br \/>\n<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?2&amp;space;\\left&amp;space;(&amp;space;\\frac{9}{2}&amp;space;+&amp;space;\\frac{1}{2}\\right&amp;space;)\" alt=\"2 \\left ( \\frac{9}{2} + \\frac{1}{2}\\right )\" align=\"absmiddle\" \/> m\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?2&amp;space;\\left&amp;space;(&amp;space;\\frac{10}{2}&amp;space;\\right&amp;space;)\" alt=\"2 \\left ( \\frac{10}{2} \\right )\" align=\"absmiddle\" \/> m\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\">= 10 m<\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif; color: #000000;\">The above arrangement will also have the greater perimeter.<\/span><\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 100%; background-color: #f2e079; text-align: center;\"><span style=\"color: #000000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong>NCERT Class 6<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 6 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-hindi\/\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Hindi<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Maths<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-sanskrit\/\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\">NCERT Solutions Class 6 Sanskrit<\/span><\/strong><\/span><\/a><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 6 Maths Chapter &#8211; 10 (Mensuration) The NCERT Solutions in English Language for Class 6 Mathematics Chapter &#8211; 10 Mensuration Exercise 10.1 has been provided here to help the students in solving the questions from this exercise. Chapter 10: Mensuration NCERT Solution Class 6 Maths Exercise &#8211; 10.2 NCERT Solution Class 6 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[23,24,4,5],"class_list":["post-527","post","type-post","status-publish","format-standard","hentry","category-class-6-maths","tag-chapter-10-mensuration-in-english","tag-ncert-solutions-class-6-maths-chapter-10-in-english","tag-ncert-solutions-class-6-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.1 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 10 Mensuration Exercise 10.1 has been provided here to help the students in solving the questions from this exercise.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-10-mensuration-ex-10-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions Class 6 Maths Chapter 10 Mensuration Ex 10.1\" \/>\n<meta property=\"og:description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 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