{"id":4960,"date":"2023-03-14T13:16:20","date_gmt":"2023-03-14T13:16:20","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=4960"},"modified":"2023-03-28T06:12:57","modified_gmt":"2023-03-28T06:12:57","slug":"ncert-solutions-class-9-science-chapter-2-is-matter-around-us-pure","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-9-science-chapter-2-is-matter-around-us-pure\/","title":{"rendered":"NCERT Solutions Class 9 Science Chapter 2 Is Matter around Us Pure"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 9 Science\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 9 Science <strong>Chapter &#8211; 2 (Is Matter around Us Pure) <\/strong>has been provided here to help the students in solving the questions from this exercise.<\/span><\/p>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 2 (Is Matter around Us Pure)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #ff0000;\"><strong>Question<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. What is meant by a substance?<br \/>\n<\/strong><strong>Answer &#8211;\u00a0<\/strong>It is a pure single form of matter. A substance has definite properties and compositions. Example &#8211; Iron<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. List the points of difference between homogeneous and heterogeneous mixtures.<br \/>\n<\/strong><strong>Answer &#8211;<\/strong><\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>Homogeneous mixture<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Heterogeneous mixture<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Particles are uniformly distributed throughout the mixture<\/span><\/td>\n<td><span style=\"color: #000000;\">All the particles are completely mixed and can be distinguished with the bare eyes or under a microscope<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Has a uniform composition<\/span><\/td>\n<td><span style=\"color: #000000;\">Irregular composition<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">No apparent boundaries of division<\/span><\/td>\n<td><span style=\"color: #000000;\">Noticeable boundaries of division<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong><span style=\"color: #ff0000;\">Question<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Differentiate between homogenous and heterogeneous mixtures with examples.<br \/>\n<\/strong><strong>Answer &#8211; <\/strong>The following are the differences between heterogeneous and homogenous mixtures.<\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>Heterogeneous mixture<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Homogeneous mixture<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">All the particles are completely mixed and can be distinguished with the bare eyes or under a microscope<\/span><\/td>\n<td><span style=\"color: #000000;\">Particles are uniformly distributed throughout the mixture<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Irregular composition<\/span><\/td>\n<td><span style=\"color: #000000;\">Has a uniform composition<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Noticeable boundaries of division<\/span><\/td>\n<td><span style=\"color: #000000;\">No apparent boundaries of division<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Examples: Seawater, blood, etc.<\/span><\/td>\n<td><span style=\"color: #000000;\">Examples: Rainwater, vinegar, etc.<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. How are sol, solution and suspension different from each other?<br \/>\n<\/strong><strong>Answer &#8211;<\/strong><\/span><\/p>\n<table>\n<thead>\n<tr>\n<th align=\"center\"><span style=\"color: #000000;\">Attributes<\/span><\/th>\n<th align=\"center\"><span style=\"color: #000000;\">Sol<\/span><\/th>\n<th align=\"center\"><span style=\"color: #000000;\">Solution<\/span><\/th>\n<th align=\"center\"><span style=\"color: #000000;\">Suspension<\/span><\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Type of Mixture<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Heterogeneous<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Homogeneous<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Heterogeneous<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Size of particles<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">10<sup>-7<\/sup> \u2013 10<sup>-5 <\/sup>cm<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Less than 1 nm<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">More than 100 nm<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Tyndall effect<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Exhibited<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Not exhibited<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">May or may not be exhibited<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Appearance<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Usually glassy and clear<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Unclouded and clear<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Cloudy and opaque<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Visibility<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Visible with an ultra microscope<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Not visible<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Visible with naked eye<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Diffusion<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Diffuses very slowly<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Diffuses rapidly<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Do not diffuse<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Stability<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Pretty stable<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Highly stable<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">unstable<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Settling<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Get settled in centrifugation<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Do not settle<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Settle on their own<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Example<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Milk, blood, smoke<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Salt solution, Sugar solution<\/span><\/td>\n<td style=\"text-align: justify;\" align=\"center\"><span style=\"color: #000000;\">Sand in water, dusty air<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. To make a saturated solution, 36g of sodium chloride is dissolved in 100 g of water at 293 K. Find its concentration at this temperature.<\/strong><br \/>\n<strong>Answer &#8211;<br \/>\n<\/strong>Mass of solute (NaCl) = 36 g<br \/>\nMass of solvent (H<sub>2<\/sub>O) = 100 g<br \/>\nMass of solution (NaCl + H<sub>2<\/sub>O) = 136 g<br \/>\nConcentration = Mass of solute\/Mass of solution x 100<br \/>\nConcentration = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{36}{136}\\times&amp;space;100\" alt=\"\\frac{36}{136}\\times 100\" align=\"absmiddle\" \/> = 26.47%<br \/>\nHence, the concentration of the solution is 26.47%<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong><span style=\"color: #ff0000;\">Question<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. How will you separate a mixture containing kerosene and petrol (the difference in their boiling points is more than 25\u00b0C), which are miscible with each other?<br \/>\n<\/strong><strong>Answer &#8211; <\/strong>The mixture of two miscible liquids such as kerosene and petrol whose boiling points differ by more than 25\u00b0C can be easily separated by the technique of simple distillation.<\/span><br \/>\n<span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-4973\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/02\/NCERT-Solutions-Class-9-Science-Ch-2-Que-1.png\" alt=\"NCERT Class 9 Solutions Maths\" width=\"633\" height=\"426\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/02\/NCERT-Solutions-Class-9-Science-Ch-2-Que-1.png 633w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/02\/NCERT-Solutions-Class-9-Science-Ch-2-Que-1-300x202.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2023\/02\/NCERT-Solutions-Class-9-Science-Ch-2-Que-1-480x323.png 480w\" sizes=\"auto, (max-width: 633px) 100vw, 633px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">The separation is based upon the principle that the boiling point of more volatile (low building liquid of the mixture. The vapour almost exclusively consists of the more volatile liquid Likewise at the boiling of the less volatile (high boiling) liquid, vapours almost entirely consists \u00a0of the less volatile liquid since the more volatile liquid has already distilled over. \u00a0 \u00a0\u00a0\u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Name the techniques used to separate the following:<br \/>\n<\/strong><strong>(i) Butter from curd<br \/>\n<\/strong><strong>(ii) Salt from seawater<br \/>\n<\/strong><strong>(iii) Camphor from salt<br \/>\n<\/strong><strong>Answer &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)<\/strong> Butter from curd can be separated by the technique of centrifugation.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong> Salt from sea water can be separated by the technique of crystallization or by the evaporation.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii)<\/strong> Camphor is sublimable but salt is not. So, camphor can be separated from salt sublimation technique.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. What types of mixtures are separated by the technique of crystallisation?<br \/>\n<\/strong><strong>Answer &#8211; <\/strong>Homogeneous mixtures such as common salt solution and copper sulphate solution separated by technique of crystallization.\u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong><span style=\"color: #ff0000;\">Question<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Classify the following as physical or chemical changes:<\/strong><\/span><\/p>\n<ul style=\"text-align: justify;\">\n<li><span style=\"color: #000000;\"><strong>Cutting of trees<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Melting of butter in a pan<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Rusting of almirah<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Boiling of water to form steam<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Passing of electric current through water and water breaking into hydrogen and oxygen gases.<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Dissolving common salt in water<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Making a fruit salad with raw fruits, and<\/strong><\/span><\/li>\n<li><span style=\"color: #000000;\"><strong>Burning of paper and wood<\/strong><\/span><\/li>\n<\/ul>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Answer &#8211; <\/strong>The following is the classification into physical and chemical change:<\/span><\/p>\n<table style=\"border-collapse: collapse; width: 100%; height: 120px;\">\n<tbody>\n<tr style=\"height: 24px;\">\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\"><strong>Physical change<\/strong><\/span><\/td>\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\"><strong>Chemical change<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 24px;\">\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Cutting the trees<\/span><\/td>\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Rusting of almirah<\/span><\/td>\n<\/tr>\n<tr style=\"height: 24px;\">\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Boiling of water to form steam<br \/>\n<\/span><\/td>\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Passing of electric current through water, and water breaking into hydrogen and oxygen gases<\/span><\/td>\n<\/tr>\n<tr style=\"height: 24px;\">\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Melting of butter in a pan<\/span><\/td>\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Burning of paper and wood<\/span><\/td>\n<\/tr>\n<tr style=\"height: 24px;\">\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\">Making a fruit salad with raw fruits<\/span><\/td>\n<td style=\"width: 50%; height: 24px;\"><span style=\"color: #000000;\"><strong>\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\"><span style=\"color: #000000;\">Dissolving common salt in water<\/span><\/td>\n<td style=\"width: 50%;\"><span style=\"color: #000000;\"><strong>\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Try segregating the things around you as pure substances and mixtures.<br \/>\n<\/strong><strong>Answer &#8211; <\/strong>Listed below are the classifications based on pure substances and mixtures:<\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>Pure substance<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Mixture<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Water<\/span><\/td>\n<td><span style=\"color: #000000;\">Soil<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Salt<\/span><\/td>\n<td><span style=\"color: #000000;\">Salad<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Iron<\/span><\/td>\n<td><span style=\"color: #000000;\">Air<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Diamond<\/span><\/td>\n<td><span style=\"color: #000000;\">Steel<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: center;\"><span style=\"text-decoration: underline; color: #ff0000;\"><span style=\"font-size: 14pt;\"><strong>Exercise\u00a0<\/strong><\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Which separation techniques will you apply for the separation of the following?<br \/>\n<\/strong><strong>(a) <\/strong>Sodium chloride from its solution in water.<strong><br \/>\n<\/strong><strong>(b) <\/strong>Ammonium chloride from a mixture containing sodium chloride and ammonium chloride.<strong><br \/>\n<\/strong><strong>(c)<\/strong> Small pieces of metal in the engine oil of a car.<strong><br \/>\n<\/strong><strong>(d)<\/strong> Different pigments from an extract of flower petals.<strong><br \/>\n<\/strong><strong>(e)<\/strong> Butter from curd.<strong><br \/>\n<\/strong><strong>(f) <\/strong>Oil from water.<strong><br \/>\n<\/strong><strong>(g) <\/strong>Tea leaves from tea.<strong><br \/>\n<\/strong><strong>(h)<\/strong> Iron pins from sand.<strong><br \/>\n<\/strong><strong>(i) <\/strong>Wheat grains from husk.<strong><br \/>\n<\/strong><strong>(j) <\/strong>Fine mud particles suspended in water.<br \/>\n<strong>Answer &#8211;<br \/>\n<\/strong><strong>(a)<\/strong> <strong>Evaporation :\u00a0<\/strong>Water will evaporate leaving behind sodium chloride.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(b) Sublimation :\u00a0<\/strong>Ammonium chloride will be collected as sublime.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(c) Filtration :\u00a0<\/strong>Pieces of metal can be separated by filtration.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(d) Chromatography:\u00a0<\/strong>Pigments (coloured components) from the extract of flower plants can be separated by chromatography.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(e) Centrifugation :\u00a0<\/strong>Butter will get separated upon centrifugation.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(f) Separating funnel:\u00a0<\/strong>Oil and water can be separated by the use of separating funnel.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(g) Filtration :\u00a0<\/strong>Upon filtration through a sieve, tea leaves will be collected on the sieve.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(h) Magnetic separation :\u00a0<\/strong>A magnet will attract iron pins and not sand particles.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(i) Sieving :\u00a0<\/strong>Wheat grains from husk can be separated with the help of sieves.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(j) Sedimentation :\u00a0<\/strong>As a result of sedimentation, mud particles will settle as precipitate. It can be separated later on by filtration.\u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Write the steps you would use for making tea. Use the words solution, solvent, solute, dissolve, soluble, insoluble, filtrate, and residue.<br \/>\n<\/strong><strong>Answer &#8211; <\/strong><strong>Steps for making tea &#8211;<\/strong><br \/>\n<strong>(i)<\/strong> Take 100ml of water as solvent and boil it for few minutes.<br \/>\n<strong>(ii)<\/strong> When solvent boil, add solutes, i.e., milk, tea leaves, sugar.<br \/>\n<strong>(iii)<\/strong> Now again boil the solution for few minutes. Sugar is soluble in water thus it will be dissolve.<br \/>\n<strong>(iv)<\/strong> Colour of tea leaves goes into solution as filtrate. The remaining tea leaves being insoluble remains as residue.<br \/>\n<strong>(v)<\/strong> Now filter the solution. Collect the filtrate in cup. The insoluble tea leaves will be left behind as residue.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of a substance dissolved in 100 grams of water to form a saturated solution).<\/strong><\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td rowspan=\"2\"><span style=\"color: #000000;\"><strong>Substance dissolved<\/strong><\/span><\/td>\n<td style=\"text-align: center;\" colspan=\"5\"><span style=\"color: #000000;\"><strong>Temperature in K<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\"><strong>283<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\"><strong>293<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\"><strong>313<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\"><strong>333<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\"><strong>353<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td style=\"text-align: center;\" colspan=\"5\"><span style=\"color: #000000;\"><strong>Solubility<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Potassium nitrate<\/span><\/td>\n<td><span style=\"color: #000000;\">21<\/span><\/td>\n<td><span style=\"color: #000000;\">32<\/span><\/td>\n<td><span style=\"color: #000000;\">62<\/span><\/td>\n<td><span style=\"color: #000000;\">106<\/span><\/td>\n<td><span style=\"color: #000000;\">167<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Sodium chloride<\/span><\/td>\n<td><span style=\"color: #000000;\">36<\/span><\/td>\n<td><span style=\"color: #000000;\">36<\/span><\/td>\n<td><span style=\"color: #000000;\">36<\/span><\/td>\n<td><span style=\"color: #000000;\">37<\/span><\/td>\n<td><span style=\"color: #000000;\">37<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Potassium chloride<\/span><\/td>\n<td><span style=\"color: #000000;\">35<\/span><\/td>\n<td><span style=\"color: #000000;\">35<\/span><\/td>\n<td><span style=\"color: #000000;\">40<\/span><\/td>\n<td><span style=\"color: #000000;\">46<\/span><\/td>\n<td><span style=\"color: #000000;\">54<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Ammonium chloride<\/span><\/td>\n<td><span style=\"color: #000000;\">24<\/span><\/td>\n<td><span style=\"color: #000000;\">37<\/span><\/td>\n<td><span style=\"color: #000000;\">41<\/span><\/td>\n<td><span style=\"color: #000000;\">55<\/span><\/td>\n<td><span style=\"color: #000000;\">66<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a) <\/strong>What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 grams of water at 313K?<br \/>\n<strong>(b) <\/strong>Pragya makes a saturated solution of potassium chloride in water at 353 K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain.<br \/>\n<strong>(c) <\/strong>Find the solubility of each salt at 293 K. Which salt has the highest solubility at this temperature?<br \/>\n<strong>(d) <\/strong>What is the effect of change of temperature on the solubility of a salt?<br \/>\n<strong>Answer &#8211;<br \/>\n<\/strong><strong>(a)<\/strong> Solubility of potassium nitrate at \u00a0313K = 62 g<br \/>\n100 g of water contains potassium nitrate = 62 g<br \/>\n50 g of water contains potassium nitrate = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{62}{100}\" alt=\"\\frac{62}{100}\" align=\"absmiddle\" \/>\u00a0 \u00d7 50 = 31 g<br \/>\nHence, 31 g of potassium nitrate is required.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> Pragya would observe crystals of potassium chloride as the solubility of potassium chloride in water decreases when a saturated solution of potassium chloride loses its heat during the cooling process below 353 K.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c)\u00a0<\/strong>Listed below is the solubility of each salt at 293 K<br \/>\nSolubility of Potassium nitrate = 32 g<br \/>\nSolubility of Sodium chloride = 36 g<br \/>\nSolubility of Potassium chloride = 35 g<br \/>\nSolubility of Ammonium chloride = 37 g<br \/>\nWe can observe from this data that ammonium chloride has the highest solubility at 293K.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d)<\/strong> Solubility of a salt is directly proportional to the change of temperature. Solubility of salt will increase when the temperature increases and solubility will decrease when the temperature decreases .<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Explain the following, giving examples.<br \/>\n<\/strong><strong>(a) <\/strong>Saturated solution<br \/>\n<strong>(b) <\/strong>Pure substance<br \/>\n<strong>(c) <\/strong>Colloid<strong><br \/>\n<\/strong><strong>(d) <\/strong>suspension<br \/>\n<strong>Answer &#8211;<br \/>\n<\/strong><strong>(a)<\/strong> <b>Saturated solution:<\/b>\u00a0It is the state of a solution at a specific temperature when a solute is no more soluble in the solvent at that present temperature. Solute will be again soluble in solvent only with an increase in the temperature. Example: Excess carbon leaves off as bubbles from the carbonated water solution which is already saturated with carbon.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><b>(b) Pure substance:<\/b> A substance that comprises of only one kind of molecules, atoms or particles is called as pure substance. Example: Sulphur, diamond etc.\u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><b>(c) Colloid:<\/b> A colloid is a homogenous non-crystalline substance in which the size of solute particles are bigger than that of the true solution. Example: Blood, Ink.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><b>(d) Suspension:<\/b>\u00a0It is a heterogeneous mixture that comprises of solute particles that are large enough to settle down. E.g. paints, etc.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. Classify each of the following as a homogeneous or heterogeneous mixture.<br \/>\n<\/strong><strong>soda water, wood, air, soil, vinegar, filtered tea.<br \/>\n<\/strong><strong>Answer &#8211; <\/strong>The following is the classification of the given substances into homogenous and heterogenous mixtures.<\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>Homogenous mixture<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Heterogeneous mixture<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Soda water<\/span><\/td>\n<td><span style=\"color: #000000;\">wood<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">vinegar<\/span><\/td>\n<td><span style=\"color: #000000;\">soil<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Filtered tea<\/span><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Air<\/span><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. How would you confirm that a colourless liquid given to you is pure water?<br \/>\n<\/strong><strong>Answer &#8211;\u00a0<\/strong>We can confirm if a colourless liquid is pure by setting it to boil. If it boils at 100\u00b0C, it is said to be pure. But if there is a decrease or increase in the boiling point, we infer that water has added impurities, hence not pure.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. Which of the following materials fall into the category of \u201cpure substance\u201d?<br \/>\n<\/strong><strong>(a)<\/strong> Ice<strong><br \/>\n<\/strong><strong>(b)<\/strong> Milk<strong><br \/>\n<\/strong><strong>(c) <\/strong>Iron<strong><br \/>\n<\/strong><strong>(d) <\/strong>Hydrochloric acid<strong><br \/>\n<\/strong><strong>(e)<\/strong> Calcium oxide<strong><br \/>\n<\/strong><strong>(f) <\/strong>Mercury<strong><br \/>\n<\/strong><strong>(g) <\/strong>Brick<strong><br \/>\n<\/strong><strong>(e) <\/strong>Wood<strong><br \/>\n<\/strong><strong>(f) <\/strong>Air.<br \/>\n<strong>Answer &#8211; <\/strong>Following substances from the above-mentioned list are pure substances:<\/span><\/p>\n<ul style=\"text-align: justify;\">\n<li><span style=\"color: #000000;\">Iron<\/span><\/li>\n<li><span style=\"color: #000000;\">Ice<\/span><\/li>\n<li><span style=\"color: #000000;\">Hydrochloric acid<\/span><\/li>\n<li><span style=\"color: #000000;\">Calcium oxide<\/span><\/li>\n<li><span style=\"color: #000000;\">Mercury<\/span><\/li>\n<\/ul>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8. Identify the solutions among the following mixtures.<br \/>\n<\/strong><strong>(a)<\/strong> Soil<strong><br \/>\n<\/strong><strong>(b)<\/strong> Sea water<strong><br \/>\n<\/strong><strong>(c) <\/strong>Air<strong><br \/>\n<\/strong><strong>(d) <\/strong>Coal<strong><br \/>\n<\/strong><strong>(e) <\/strong>Soda water<strong><br \/>\n<\/strong><strong>Answer &#8211; <\/strong>The following are the solutions from the above-mentioned list of mixtures:<\/span><\/p>\n<ul style=\"text-align: justify;\">\n<li><span style=\"color: #000000;\">Sea water<\/span><\/li>\n<li><span style=\"color: #000000;\">Air<\/span><\/li>\n<li><span style=\"color: #000000;\">Soda water<\/span><\/li>\n<\/ul>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>9. Which of the following will show the \u201cTyndall effect\u201d?<br \/>\n<\/strong><strong>(a)<\/strong> Salt solution<strong><br \/>\n<\/strong><strong>(b)<\/strong> Milk<strong><br \/>\n<\/strong><strong>(c) <\/strong>Copper sulphate solution<strong><br \/>\n<\/strong><strong>(d) <\/strong>Starch solution<br \/>\n<strong>Answer &#8211; <\/strong>Tyndall effect is exhibited by only milk and starch solution from the above-mentioned list of solutions.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>10. Classify the following into elements, compounds and mixtures.<br \/>\n<\/strong><strong>(a) <\/strong>Sodium<br \/>\n<strong>(b)<\/strong> Soil<strong><br \/>\n<\/strong><strong>(c) <\/strong>Sugar solution<strong><br \/>\n<\/strong><strong>(d) <\/strong>Silver<strong><br \/>\n<\/strong><strong>(e) <\/strong>Calcium carbonate<br \/>\n<strong>(f) <\/strong>Tin<strong><br \/>\n<\/strong><strong>(g) <\/strong>Silicon<br \/>\n<strong>(h) <\/strong>Coal<strong><br \/>\n<\/strong><strong>(i) <\/strong>Air<strong><br \/>\n<\/strong><strong>(j) <\/strong>Soap<strong><br \/>\n<\/strong><strong>(k)<\/strong> Methane<strong><br \/>\n<\/strong><strong>(l) <\/strong>Carbon dioxide<strong><br \/>\n<\/strong><strong>(m) <\/strong>Blood<br \/>\n<strong>Answer &#8211;<\/strong><\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>Elements<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Compounds<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Mixture<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Sodium<\/span><\/td>\n<td><span style=\"color: #000000;\">Calcium carbonate<\/span><\/td>\n<td><span style=\"color: #000000;\">Soil<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Silver<\/span><\/td>\n<td><span style=\"color: #000000;\">Carbon dioxide<\/span><\/td>\n<td><span style=\"color: #000000;\">Sugar solution<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Tin<\/span><\/td>\n<td><span style=\"color: #000000;\">Methane<\/span><\/td>\n<td><span style=\"color: #000000;\">Coal<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"color: #000000;\">Silicon<\/span><\/td>\n<td><\/td>\n<td><span style=\"color: #000000;\">Air<\/span><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><span style=\"color: #000000;\">Blood<\/span><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><span style=\"color: #000000;\">Soap<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000;\"><strong>11. Which of the following are chemical changes?<br \/>\n<\/strong><strong>(a) <\/strong>Growth of a plant\u00a0<strong><br \/>\n<\/strong><strong>(b) <\/strong>Rusting of iron<strong><br \/>\n<\/strong><strong>(c) <\/strong>Mixing of iron filings and sand\u00a0<strong><br \/>\n<\/strong><strong>(d)<\/strong> Cooking of food<strong><br \/>\n<\/strong><strong>(e)<\/strong> Digestion of food\u00a0<strong><br \/>\n<\/strong><strong>(f) <\/strong>Freezing of water<strong><br \/>\n<\/strong><strong>(g) <\/strong>Burning of candle<strong><br \/>\n<\/strong><strong>Answer &#8211; <\/strong>Out of the given list, the following are chemical changes:<br \/>\nGrowth of a plant, rusting of iron, cooking of food, digestion of food and burning of candle.<\/span><\/p>\n<p><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-9-science\/\" target=\"_blank\" rel=\"noopener\"><b><i>Go Back To Chapters<\/i><\/b><\/a><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 9 Science\u00a0 The NCERT Solutions in English Language for Class 9 Science Chapter &#8211; 2 (Is Matter around Us Pure) has been provided here to help the students in solving the questions from this exercise. Chapter &#8211; 2 (Is Matter around Us Pure) Question 1. What is meant by a substance? Answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[729],"tags":[730,734,735,733,5],"class_list":["post-4960","post","type-post","status-publish","format-standard","hentry","category-class-9-science","tag-class-9-ncert-solutions","tag-ncert-class-9-science-chapter-2-is-matter-around-us-pure","tag-ncert-solutions-class-9-science-chapter-2-in-english","tag-ncert-solutions-class-9-science-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 9 Science Chapter 2 Is Matter around Us Pure | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 9 Science\u00a0The NCERT Solutions in English Language for Class 9 Science Chapter - 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