{"id":3411,"date":"2022-12-14T14:43:46","date_gmt":"2022-12-14T14:43:46","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=3411"},"modified":"2023-01-31T06:50:28","modified_gmt":"2023-01-31T06:50:28","slug":"ncert-solutions-class-8-maths-chapter-14-factorisation-ex-14-2","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-14-factorisation-ex-14-2\/","title":{"rendered":"NCERT Solutions Class 8 Maths Chapter 14 Factorisation Ex 14.2"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 8 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 14 (Factorisation)\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 8 Mathematics <strong>Chapter &#8211; 14 Factorisation\u00a0 <\/strong>Exercise 14.2 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Chapter 14: Factorisation<\/strong><\/span><\/h4>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-14-factorisation-ex-14-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 14.1<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-14-factorisation-ex-14-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 14.3<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-14-factorisation-ex-14-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 14.4<\/a><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 14.2<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Factorise the following expressions.<br \/>\n<\/strong><strong>(i)\u00a0<\/strong>a<sup>2<\/sup>+8a+16<br \/>\n<strong>(ii)<\/strong> p<sup>2<\/sup>\u201310p+25<br \/>\n<strong>(iii)<\/strong> 25m<sup>2<\/sup>+30m+9<br \/>\n<strong>(iv)<\/strong> 49y<sup>2<\/sup>+84yz+36z<sup>2<br \/>\n<\/sup><strong>(v)<\/strong> 4x<sup>2<\/sup>\u20138x+4<br \/>\n<strong>(vi)<\/strong> 121b<sup>2<\/sup>\u201388bc+16c<sup>2<br \/>\n<\/sup><strong>(vii)<\/strong> (l + m)<sup>2 <\/sup>\u2013 4lm (<strong>Hint:<\/strong> Expand (l+m)<sup>2<\/sup>\u00a0first)<br \/>\n<strong>(viii)<\/strong> a<sup>4<\/sup>+2a<sup>2<\/sup>b<sup>2<\/sup>+b<sup>4<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) a<sup>2<\/sup>+8a+16<br \/>\n<\/strong>= a<sup>2<\/sup>+2\u00d74\u00d7a+4<sup>2<br \/>\n<\/sup>= (a+4)<sup>2<br \/>\n<\/sup>Using the identity (x+y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>+2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) p<sup>2<\/sup>\u201310p+25<br \/>\n<\/strong>= p<sup>2<\/sup>-2\u00d75\u00d7p+5<sup>2<br \/>\n<\/sup>= (p-5)<sup>2<br \/>\n<\/sup>Using the identity (x-y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>-2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) 25m<sup>2<\/sup>+30m+9<br \/>\n<\/strong>= (5m)<sup>2<\/sup>+2\u00d75m\u00d73+3<sup>2<br \/>\n<\/sup>= (5m+3)<sup>2<br \/>\n<\/sup>Using the identity (x+y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>+2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) 49y<sup>2<\/sup>+84yz+36z<sup>2<br \/>\n<\/sup><\/strong>= (7y)<sup>2<\/sup>+2\u00d77y\u00d76z+(6z)<sup>2<br \/>\n<\/sup>= (7y+6z)<sup>2<br \/>\n<\/sup>Using the identity (x+y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>+2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) 4x<sup>2<\/sup>\u20138x+4<br \/>\n<\/strong>= (2x)<sup>2<\/sup>-2\u00d74x+2<sup>2<br \/>\n<\/sup>= (2x-2)<sup>2<br \/>\n<\/sup>Using the identity (x-y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>-2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vi) 121b<sup>2<\/sup>-88bc+16c<sup>2<br \/>\n<\/sup><\/strong>= (11b)<sup>2<\/sup>-2\u00d711b\u00d74c+(4c)<sup>2<br \/>\n<\/sup>= (11b-4c)<sup>2<br \/>\n<\/sup>Using the identity (x-y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>-2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vii) (l+m)<sup>2<\/sup>-4lm<br \/>\n<\/strong>Expand (l+m)<sup>2\u00a0<\/sup>using the identity (x+y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>+2xy+y<sup>2<br \/>\n<\/sup>(l+m)<sup>2<\/sup>-4lm = l<sup>2<\/sup>+m<sup>2<\/sup>+2lm-4lm<br \/>\n= l<sup>2<\/sup>+m<sup>2<\/sup>-2lm<br \/>\n= (l-m)<sup>2<br \/>\n<\/sup>Using the identity (x-y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>-2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(viii) a<sup>4<\/sup>+2a<sup>2<\/sup>b<sup>2<\/sup>+b<sup>4<br \/>\n<\/sup><\/strong>= (a<sup>2<\/sup>)<sup>2<\/sup>+2\u00d7a<sup>2\u00d7<\/sup>b<sup>2<\/sup>+(b<sup>2<\/sup>)<sup>2<br \/>\n<\/sup>= (a<sup>2<\/sup>+b<sup>2<\/sup>)<sup>2<br \/>\n<\/sup>Using the identity (x+y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>+2xy+y<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Factorise.<br \/>\n<\/strong><strong>(i)<\/strong> 4p<sup>2<\/sup>\u20139q<sup>2<br \/>\n<\/sup><strong>(ii)<\/strong> 63a<sup>2<\/sup>\u2013112b<sup>2<br \/>\n<\/sup><strong>(iii)<\/strong> 49x<sup>2<\/sup>\u201336<br \/>\n<strong>(iv)<\/strong> 16x<sup>5<\/sup>\u2013144x<sup>3<\/sup>\u00a0differ<br \/>\n<strong>(v)<\/strong> (l+m)<sup>2<\/sup>-(l-m)<sup>\u00a02<br \/>\n<\/sup><strong>(vi)<\/strong> 9x<sup>2<\/sup>y<sup>2<\/sup>\u201316<br \/>\n<strong>(vii)<\/strong> (x<sup>2<\/sup>\u20132xy+y<sup>2<\/sup>)\u2013z<sup>2<br \/>\n<\/sup><strong>(viii)<\/strong> 25a<sup>2<\/sup>\u20134b<sup>2<\/sup>+28bc\u201349c<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) 4p<sup>2<\/sup>\u20139q<sup>2<br \/>\n<\/sup><\/strong>= (2p)<sup>2<\/sup>-(3q)<sup>2<br \/>\n<\/sup>= (2p-3q)(2p+3q)<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) 63a<sup>2<\/sup>\u2013112b<sup>2<br \/>\n<\/sup><\/strong>= 7(9a<sup>2<\/sup>\u00a0\u201316b<sup>2<\/sup>)<br \/>\n= 7((3a)<sup>2<\/sup>\u2013(4b)<sup>2<\/sup>)<br \/>\n= 7(3a+4b)(3a-4b)<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) 49x<sup>2<\/sup>\u201336<br \/>\n<\/strong>= (7x)<sup>2<\/sup>\u00a0-6<sup>2<br \/>\n<\/sup>= (7x+6)(7x\u20136)<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) 16x<sup>5<\/sup>\u2013144x<sup>3<br \/>\n<\/sup><\/strong>= 16x<sup>3<\/sup>(x<sup>2<\/sup>\u20139)<br \/>\n= 16x<sup>3<\/sup>(x<sup>2<\/sup>\u20139)<br \/>\n= 16x<sup>3<\/sup>(x\u20133)(x+3)<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) (l+m)<sup>\u00a02<\/sup>-(l-m)<sup>\u00a02<br \/>\n<\/sup><\/strong>= {(l+m)-(l\u2013m)}{(l +m)+(l\u2013m)}<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup> = (x+y)(x-y)<br \/>\n= (l+m\u2013l+m)(l+m+l\u2013m)<br \/>\n= (2m)(2l)<br \/>\n= 4ml<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vi) 9x<sup>2<\/sup>y<sup>2<\/sup>\u201316<br \/>\n<\/strong>= (3xy)<sup>2<\/sup>-4<sup>2<br \/>\n<\/sup>= (3xy\u20134)(3xy+4)<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vii) (x<sup>2<\/sup>\u20132xy+y<sup>2<\/sup>)\u2013z<sup>2<br \/>\n<\/sup><\/strong>= (x\u2013y)<sup>2<\/sup>\u2013z<sup>2<br \/>\n<\/sup>Using the identity (x-y)<sup>2<\/sup>\u00a0= x<sup>2<\/sup>-2xy+y<sup>2<br \/>\n<\/sup>= {(x\u2013y)\u2013z}{(x\u2013y)+z}<br \/>\n= (x\u2013y\u2013z)(x\u2013y+z)<br \/>\nUsing the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(viii) 25a<sup>2<\/sup>\u20134b<sup>2<\/sup>+28bc\u201349c<sup>2<br \/>\n<\/sup><\/strong>= 25a<sup>2<\/sup>\u2013(4b<sup>2<\/sup>-28bc+49c<sup>2<\/sup>\u00a0)<br \/>\n= (5a)<sup>2<\/sup>-{(2b)<sup>2<\/sup>-2(2b)(7c)+(7c)<sup>2<\/sup>}<br \/>\n= (5a)<sup>2<\/sup>-(2b-7c)<sup>2<br \/>\n<\/sup>Using the identity x<sup>2<\/sup>-y<sup>2<\/sup>\u00a0= (x+y)(x-y) , we have<br \/>\n= (5a+2b-7c)(5a-2b+7c)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Factorise the expressions.<br \/>\n<\/strong><strong>(i)<\/strong> ax<sup>2<\/sup>+bx<br \/>\n<strong>(ii)<\/strong> 7p<sup>2<\/sup>+21q<sup>2<br \/>\n<\/sup><strong>(iii)<\/strong> 2x<sup>3<\/sup>+2xy<sup>2<\/sup>+2xz<sup>2<br \/>\n<\/sup><strong>(iv)<\/strong> am<sup>2<\/sup>+bm<sup>2<\/sup>+bn<sup>2<\/sup>+an<sup>2<br \/>\n<\/sup><strong>(v)<\/strong> (lm+l)+m+1<br \/>\n<strong>(vi)<\/strong> y(y+z)+9(y+z)<br \/>\n<strong>(vii)<\/strong> 5y<sup>2<\/sup>\u201320y\u20138z+2yz<br \/>\n<strong>(viii)<\/strong> 10ab+4a+5b+2<br \/>\n<strong>(ix)<\/strong> 6xy\u20134y+6\u20139x<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) ax<sup>2<\/sup>+bx<\/strong><br \/>\n= x(ax+b)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) 7p<sup>2<\/sup>+21q<sup>2<\/sup><br \/>\n<\/strong>= 7(p<sup>2<\/sup>+3q<sup>2<\/sup>)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) 2x<sup>3<\/sup>+2xy<sup>2<\/sup>+2xz<sup>2<\/sup><br \/>\n<\/strong>= 2x(x<sup>2<\/sup>+y<sup>2<\/sup>+z<sup>2<\/sup>)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) am<sup>2<\/sup>+bm<sup>2<\/sup>+bn<sup>2<\/sup>+an<sup>2<br \/>\n<\/sup><\/strong>= m<sup>2<\/sup>(a+b)+n<sup>2<\/sup>(a+b)<br \/>\n= (a+b)(m<sup>2<\/sup>+n<sup>2<\/sup>)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) (lm+l)+m+1<\/strong><br \/>\n= lm+m+l+1<br \/>\n= m(l+1)+(l+1)<br \/>\n= (m+1)(l+1)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vi) y(y+z)+9(y+z)<\/strong><br \/>\n= (y+9)(y+z)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vii) 5y<sup>2<\/sup>\u201320y\u20138z+2yz<\/strong><br \/>\n= 5y(y\u20134)+2z(y\u20134)<br \/>\n= (y\u20134)(5y+2z)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(viii) 10ab+4a+5b+2<\/strong><br \/>\n= 5b(2a+1)+2(2a+1)<br \/>\n= (2a+1)(5b+2)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ix) 6xy\u20134y+6\u20139x<\/strong><br \/>\n= 6xy\u20139x\u20134y+6<br \/>\n= 3x(2y\u20133)\u20132(2y\u20133)<br \/>\n= (2y\u20133)(3x\u20132)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4.Factorise.<br \/>\n<\/strong><strong>(i) a<sup>4<\/sup>\u2013b<sup>4<br \/>\n<\/sup><\/strong><strong>(ii) p<sup>4<\/sup>\u201381<br \/>\n<\/strong><strong>(iii) x<sup>4<\/sup>\u2013(y+z)<sup>\u00a04<br \/>\n<\/sup><\/strong><strong>(iv) x<sup>4<\/sup>\u2013(x\u2013z)<sup>\u00a04<br \/>\n<\/sup><\/strong><strong>(v) a<sup>4<\/sup>\u20132a<sup>2<\/sup>b<sup>2<\/sup>+b<sup>4<\/sup><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(i) a<sup>4<\/sup>\u2013b<sup>4<br \/>\n<\/sup><\/strong>= (a<sup>2<\/sup>)<sup>2<\/sup>-(b<sup>2<\/sup>)<sup>2<br \/>\n<\/sup>= (a<sup>2<\/sup>-b<sup>2<\/sup>) (a<sup>2<\/sup>+b<sup>2<\/sup>)<br \/>\n= (a \u2013 b)(a + b)(a<sup>2<\/sup>+b<sup>2<\/sup>)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) p<sup>4<\/sup>\u201381<br \/>\n<\/strong>= (p<sup>2<\/sup>)<sup>2<\/sup>-(9)<sup>2<br \/>\n<\/sup>= (p<sup>2<\/sup>-9)(p<sup>2<\/sup>+9)<br \/>\n= (p<sup>2<\/sup>-3<sup>2<\/sup>)(p<sup>2<\/sup>+9)<br \/>\n= (p-3)(p+3)(p<sup>2<\/sup>+9)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) x<sup>4<\/sup>\u2013(y+z)<sup>4<\/sup><br \/>\n<\/strong>= (x<sup>2<\/sup>)<sup>2<\/sup>-[(y+z)<sup>2<\/sup>]<sup>2<br \/>\n<\/sup>= {x<sup>2<\/sup>-(y+z)<sup>2<\/sup>}{ x<sup>2<\/sup>+(y+z)<sup>2<\/sup>}<br \/>\n= {(x \u2013(y+z)(x+(y+z)}{x<sup>2<\/sup>+(y+z)<sup>2<\/sup>}<br \/>\n= (x\u2013y\u2013z)(x+y+z) {x<sup>2<\/sup>+(y+z)<sup>2<\/sup>}<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) x<sup>4<\/sup>\u2013(x\u2013z)<sup>\u00a04<\/sup><br \/>\n<\/strong>= (x<sup>2<\/sup>)<sup>2<\/sup>-{(x-z)<sup>2<\/sup>}<sup>2<br \/>\n<\/sup>= {x<sup>2<\/sup>-(x-z)<sup>2<\/sup>}{x<sup>2<\/sup>+(x-z)<sup>2<\/sup>}<br \/>\n= { x-(x-z)}{x+(x-z)} {x<sup>2<\/sup>+(x-z)<sup>2<\/sup>}<br \/>\n= z(2x-z)( x<sup>2<\/sup>+x<sup>2<\/sup>-2xz+z<sup>2<\/sup>)<br \/>\n= z(2x-z)( 2x<sup>2<\/sup>-2xz+z<sup>2<\/sup>)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) a<sup>4<\/sup>\u20132a<sup>2<\/sup>b<sup>2<\/sup>+b<sup>4<\/sup><br \/>\n=<\/strong> (a<sup>2<\/sup>)<sup>2<\/sup>-2a<sup>2<\/sup>b<sup>2<\/sup>+(b<sup>2<\/sup>)<sup>2<br \/>\n<\/sup>= (a<sup>2<\/sup>-b<sup>2<\/sup>)<sup>2<br \/>\n<\/sup>= ((a\u2013b)(a+b))<sup>2<br \/>\n<\/sup>= (a \u2013 b)<sup>2<\/sup>\u00a0(a + b)<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. Factorise the following expressions.<br \/>\n<\/strong><strong>(i)<\/strong> p<sup>2<\/sup>+6p+8<br \/>\n<strong>(ii)<\/strong> q<sup>2<\/sup>\u201310q+21<br \/>\n<strong>(iii)<\/strong> p<sup>2<\/sup>+6p\u201316<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(i) p<sup>2<\/sup>+6p+8<br \/>\n<\/strong>We observed that 8 = 4\u00d72 and 4+2 = 6<br \/>\np<sup>2<\/sup>+6p+8<br \/>\n= p<sup>2<\/sup>+2p+4p+8<br \/>\n= p(p+2)+4(p+2)<br \/>\n= (p+2)(p+4)<br \/>\nThis implies that p<sup>2<\/sup>+6p+8 = (p+2)(p+4)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) q<sup>2<\/sup>\u201310q+21<br \/>\n<\/strong>We observed that 21 = -7\u00d7-3 and -7+(-3) = -10<br \/>\nq<sup>2<\/sup>\u201310q+21<br \/>\n= q<sup>2<\/sup>\u20133q-7q+21<br \/>\n= q(q\u20133)\u20137(q\u20133)<br \/>\n= (q\u20137)(q\u20133)<br \/>\nThis implies that q<sup>2<\/sup>\u201310q+21 = (q\u20137)(q\u20133)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) p<sup>2<\/sup>+6p\u201316<br \/>\n<\/strong>We observed that -16 = -2\u00d78 and 8+(-2) = 6<br \/>\np<sup>2<\/sup>+6p\u201316<br \/>\n= p<sup>2<\/sup>\u20132p+8p\u201316<br \/>\n= p(p\u20132)+8(p\u20132)<br \/>\n= (p+8)(p\u20132)<br \/>\nThis implies that p<sup>2<\/sup>+6p\u201316 = (p+8)(p\u20132)<\/span><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 32px;\">\n<td style=\"width: 100%; background-color: #f2e079; text-align: center; height: 32px;\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong>NCERT Class 8<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 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rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 8 Mathematics\u00a0 Chapter &#8211; 14 (Factorisation)\u00a0 The NCERT Solutions in English Language for Class 8 Mathematics Chapter &#8211; 14 Factorisation\u00a0 Exercise 14.2 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 14: Factorisation NCERT Solution Class 8 Maths Ex &#8211; 14.1 NCERT Solution Class 8 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[442],"tags":[470,471,445,5],"class_list":["post-3411","post","type-post","status-publish","format-standard","hentry","category-class-8-maths","tag-ncert-class-8-maths-chapter-14-factorisation-in-english","tag-ncert-solutions-class-8-maths-chapter-14-in-english","tag-ncert-solutions-class-8-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 8 Maths Chapter 14 Factorisation Ex 14.2 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 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