{"id":3127,"date":"2022-12-06T07:36:25","date_gmt":"2022-12-06T07:36:25","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=3127"},"modified":"2023-01-31T06:54:03","modified_gmt":"2023-01-31T06:54:03","slug":"ncert-solutions-class-8-maths-chapter-6-squares-and-square-roots-ex-6-1","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-6-squares-and-square-roots-ex-6-1\/","title":{"rendered":"NCERT Solutions Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.1"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 8 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 6 (Squares and Square)\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 8 Mathematics <strong>Chapter &#8211; 6 Squares and Square <\/strong>Exercise 6.1 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Chapter 6: Squares and Square Roots<\/strong><\/span><\/h4>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-6-squares-and-square-roots-ex-6-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 6.2<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-6-squares-and-square-roots-ex-6-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 6.3<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-6-squares-and-square-roots-ex-6-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 6.4<\/a><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 6.1\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. What will be the unit digit of the squares of the following numbers?<br \/>\n(<\/strong><strong>i) <\/strong>81\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(ii) <\/strong>272\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(iii) <\/strong>799\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(iv) <\/strong>3853<strong><br \/>\n<\/strong><strong>(v) <\/strong>1234\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(<\/strong><strong>vi) <\/strong>26387\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0<strong>(<\/strong><strong>vii) <\/strong>52698\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(<\/strong><strong>viii) <\/strong>99880<strong><br \/>\n(<\/strong><strong>ix) <\/strong>12796\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(<\/strong><strong>x) <\/strong>55555<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>The unit digit of square of a number having \u2018a\u2019 at its unit place ends with a\u00d7a.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) <\/strong>If a number has 1 or 9 in its unit digit, then its\u00a0square\u00a0ends with 1.<\/span><br \/>\n<span style=\"color: #000000;\">Since 81 has 1 as its unit digit, 1 will be the\u00a0unit digit\u00a0of its square. (1 \u00d7 1 = 1)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong> If a number has either 2 or 8 as its unit digit, then its square ends with 4.<\/span><br \/>\n<span style=\"color: #000000;\">Since 272 has 2 as its unit digit, 4 will be the unit digit of its square. (2 \u00d7 2 = 4)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) <\/strong>If a number has 1 or 9 in its unit digit, then its square ends with 1.<\/span><br \/>\n<span style=\"color: #000000;\">Since 799 has 9 as its unit digit, 1 will be the unit digit of its square. (9 \u00d7 9 = 81)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) <\/strong>If a number has either 3 or 7 as its unit digit, then its square number ends with 9.<\/span><br \/>\n<span style=\"color: #000000;\">Since 3853 has 3 as its unit digit, 9 will be the unit digit of its square. (3 \u00d7 3 = 9)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) <\/strong>If a number has either 4 or 6 as its unit digit, then its square ends with 6.<\/span><br \/>\n<span style=\"color: #000000;\">Since 1234 has 4 as its unit digit, 6 will be the unit digit of its square. (4 \u00d7 4 = 16)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vi) <\/strong>If a number has either 3 or 7 as its unit digit, then its square number ends with 9.<\/span><br \/>\n<span style=\"color: #000000;\">Since 26387 has 7 as its unit digit, 9 will be the unit digit of its square. (7 \u00d7 7 = 49)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vii) <\/strong>If a number has either 2 or 8 as its unit digit, then its square ends with 4.<\/span><br \/>\n<span style=\"color: #000000;\">Since 52698 has 8 as its unit digit, 4 will be the unit digit of its square. (8 \u00d7 8 = 64)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(viii) <\/strong>If a number has 0 as its unit digit, then its square ends with 0.<\/span><br \/>\n<span style=\"color: #000000;\">Since 99880 has 0 as its unit digit, 0 will be the unit digit of its square.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ix) <\/strong>If a number has either 4 or 6 as its unit digit, then its square ends with 6.<\/span><br \/>\n<span style=\"color: #000000;\">Since 12796 has 6 as its unit digit, 6 will be the unit digit of its square. (6 \u00d7 6 = 36)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(x) <\/strong>If a number has 5 as its unit digit, then its square ends with 5.<\/span><br \/>\n<span style=\"color: #000000;\">Since 55555 has 5 as its unit digit, 5 will be the unit digit of its square.\u00a0(5 \u00d7 5 = 25)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. The following numbers are obviously not perfect squares. Give reason.<br \/>\n<\/strong><strong>(i)<\/strong> 1057\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(ii)<\/strong> 23453\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(iii)<\/strong>\u00a07928<br \/>\n<strong>(iv)<\/strong> 222222\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(v)<\/strong> 64000\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(vi)<\/strong>\u00a089722<br \/>\n<strong>(vii)<\/strong> 222000\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <strong>(viii)<\/strong> 505050<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>We know that natural numbers ending in the digits 0, 2, 3, 7 and 8 are not perfect squares.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)<\/strong>\u00a01057<br \/>\nThe number 1057 is not a perfect square because it ends with 7 at unit\u2019s place whereas the square numbers end with 0, 1, 4, 5, 6 or 9 at unit\u2019s place.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong>\u00a023453<br \/>\nThe number 23453\u00a0is not a perfect square because it ends with 7 at unit\u2019s place whereas the square numbers end with 0, 1, 4, 5, 6 or 9 at unit\u2019s place.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii)<\/strong>\u00a07928<br \/>\nThe number 7928 is not a perfect square because it ends with 8 at unit\u2019s place whereas the square numbers end with 0, 1, 4, 5, 6 or 9 at unit\u2019s place.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv)<\/strong>\u00a0222222<br \/>\nThe number 222222 is not a perfect square because it ends with 2 at unit\u2019s place whereas the Square numbers end with 0, 1, 4, 5, 6 or 9 at unit\u2019s place.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v)<\/strong>\u00a064000<br \/>\nThe number 64000 is not a square number because it has 3 (an odd number of) zeros at the end whereas the number of zeros at the end of a square number ending with zeros is always even.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vi)<\/strong>\u00a089722<br \/>\nThe number 89722 is not a square number because it ends in 2 at unit\u2019s place whereas the square numbers end with 0, 1, 4, 5, 6 or 9 at unit\u2019s place.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(vii)<\/strong>\u00a0222000<br \/>\nThe number 222000 is not a square number because it has 3 (an odd number of) zeros at the end whereas the number of zeros at the end of a square number ending with zeros is always even.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(viii)<\/strong> 505050<br \/>\nThe number 505050 is not a square number because it has 1 (an odd number of) zeros at the end whereas the number of zeros at the end of a square number ending with zeros is always even.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. The squares of which of the following would be odd numbers?<br \/>\n<\/strong><strong>(i)<\/strong>\u00a0431<br \/>\n<strong>(ii)<\/strong>\u00a02826<br \/>\n<strong>(iii)<\/strong>\u00a07779<br \/>\n<strong>(v)<\/strong> 82004<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>We know that the square of an odd number is odd and the square of an even number is even.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)<\/strong> 431<br \/>\n431 is an odd number<br \/>\n\u2234 Its square will also be an odd number.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong>\u00a02826<br \/>\n2826 is an even number<br \/>\n\u2234 Its square will not be an odd number.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii)<\/strong>\u00a07779<br \/>\n7779 is an odd number<br \/>\n\u2234 Its square will be an odd number.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v)<\/strong> 82004<br \/>\n82004 is an even number<br \/>\n\u2234 Its square will not be an odd number.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Observe the following pattern and find the missing numbers. 11<sup>2<\/sup> = 121<br \/>\n<\/strong>101<sup>2<\/sup>\u00a0= 10201<br \/>\n1001<sup>2<\/sup>\u00a0= 1002001<br \/>\n100001<sup>2<\/sup> = 1____2____1<br \/>\n10000001<sup>2<\/sup> = ________<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>101<sup>2<\/sup>\u00a0= 10201<br \/>\n1001<sup>2<\/sup>\u00a0= 1002001<br \/>\n100001<sup>2<\/sup> = 1<span style=\"text-decoration: underline;\"><strong>0000<\/strong><\/span>2<span style=\"text-decoration: underline;\"><strong>0000<\/strong><\/span>1<br \/>\n10000001<sup>2<\/sup> = <span style=\"text-decoration: underline;\"><strong>100000020000001<\/strong><\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. Observe the following pattern and supply the missing numbers.<br \/>\n<\/strong>112 = 121<br \/>\n1012 = 10201<br \/>\n101012 = 102030201<br \/>\n10101012 = ________<br \/>\n______2 = 10203040504030201<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>112 = 121<br \/>\n1012 = 10201<br \/>\n101012 = 102030201<br \/>\n10101012 = <span style=\"text-decoration: underline;\">1020304030201<\/span><br \/>\n<span style=\"text-decoration: underline;\">101010101<\/span>2 = 10203040504030201<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. Using the given pattern, find the missing numbers.<br \/>\n<\/strong>1<sup>2<\/sup>\u00a0+ 2<sup>2<\/sup>\u00a0+ 2<sup>2<\/sup>\u00a0= 3<sup>2<br \/>\n<\/sup>2<sup>2<\/sup>\u00a0+ 3<sup>2<\/sup>\u00a0+ 6<sup>2<\/sup>\u00a0= 7<sup>2<br \/>\n<\/sup>3<sup>2<\/sup>\u00a0+ 4<sup>2<\/sup>\u00a0+ 12<sup>2<\/sup>\u00a0= 13<sup>2<br \/>\n<\/sup>4<sup>2<\/sup>\u00a0+ 5<sup>2<\/sup>\u00a0+ _2 = 21<sup>2<br \/>\n<\/sup>5 + _\u00a0<sup>2<\/sup>\u00a0+ 30<sup>2<\/sup>\u00a0= 31<sup>2<br \/>\n<\/sup>6 + 7 + _\u00a0<sup>2<\/sup>\u00a0= _\u00a0<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Given, 1<sup>2<\/sup>\u00a0+ 2<sup>2<\/sup>\u00a0+ 2<sup>2<\/sup>\u00a0= 3<sup>2<br \/>\n<\/sup>1<sup>2<\/sup>\u00a0+ 2<sup>2<\/sup>\u00a0+ (1\u00d72 )<sup>2<\/sup>\u00a0= ( 1<sup>2<\/sup>\u00a0+ 2<sup>2<\/sup>\u00a0-1 \u00d7 2 )<sup>2<br \/>\n<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">2<sup>2<\/sup>\u00a0+ 3<sup>2<\/sup>\u00a0+ 6<sup>2<\/sup>\u00a0=7<sup>2<br \/>\n<\/sup>\u2234 2<sup>2<\/sup>\u00a0+ 3<sup>2<\/sup>\u00a0+ (2\u00d73 )<sup>2<\/sup>\u00a0= (2<sup>2<\/sup>\u00a0+ 3<sup>2<\/sup>\u00a0-2 \u00d7 3)<sup>2<br \/>\n<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">3<sup>2\u00a0<\/sup>+ 4<sup>2<\/sup>\u00a0+ 12<sup>2<\/sup>\u00a0= 13<sup>2<br \/>\n<\/sup>\u2234 3<sup>2<\/sup>\u00a0+ 4<sup>2<\/sup>\u00a0+ (3\u00d74 )<sup>2<\/sup>\u00a0= (3<sup>2<\/sup>\u00a0+ 4<sup>2<\/sup>\u00a0\u2013 3 \u00d7 4)<sup>2<br \/>\n<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">4<sup>2<\/sup>\u00a0+ 5<sup>2<\/sup>\u00a0+ (4\u00d75 )<sup>2<\/sup>\u00a0= (4<sup>2<\/sup>\u00a0+ 5<sup>2<\/sup>\u00a0\u2013 4 \u00d7 5)<sup>2<br \/>\n<\/sup>\u2234 4<sup>2<\/sup>\u00a0+ 5<sup>2<\/sup>\u00a0+ 20<sup>2<\/sup>\u00a0= 21<sup>2<br \/>\n<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">5<sup>2<\/sup>\u00a0+ 6<sup>2<\/sup>\u00a0+ (5\u00d76 )<sup>2<\/sup>\u00a0= (5<sup>2<\/sup>+ 6<sup>2<\/sup>\u00a0\u2013 5 \u00d7 6)<sup>2<br \/>\n<\/sup>\u2234 5<sup>2<\/sup>\u00a0+ 6<sup>2<\/sup>\u00a0+ 30<sup>2<\/sup>\u00a0= 31<sup>2<br \/>\n<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">6<sup>2<\/sup>\u00a0+ 7<sup>2<\/sup>\u00a0+ (6\u00d77 )<sup>2<\/sup>\u00a0= (6<sup>2<\/sup>\u00a0+ 7<sup>2<\/sup>\u00a0\u2013 6 \u00d7 7)<sup>2<br \/>\n<\/sup>\u2234 6<sup>2<\/sup>\u00a0+ 7<sup>2<\/sup>\u00a0+ 42<sup>2<\/sup>\u00a0= 43<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. Without adding, find the sum.<br \/>\n<\/strong><strong>(i)<\/strong> 1 + 3 + 5 + 7 + 9<br \/>\n<strong>(ii)<\/strong>\u00a01 + 3 + 5 + 7 + 9 + 11 + 13 + 15 +17 + 19<br \/>\n<strong>(iii)<\/strong> 1+3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 +23<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)<\/strong> 1 + 3 + 5 + 7 + 9<br \/>\nSum of first five odd number = (5)<sup>2<\/sup>\u00a0= 25<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong>\u00a01 + 3 + 5 + 7 + 9 + 11 + 13 + 15 +17 + 19<br \/>\nSum of first ten odd number = (10)<sup>2<\/sup>\u00a0= 100<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii)<\/strong> 1+3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 +23<br \/>\nSum of first thirteen odd number = (12)<sup>2<\/sup>\u00a0= 144<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8.<br \/>\n<\/strong><strong>(i)<\/strong>\u00a0Express 49 as the sum of 7 odd numbers.<br \/>\n<strong>(ii)<\/strong>\u00a0Express 121 as the sum of 11 odd numbers.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(i)<\/strong> 49 = (7)<sup>2<br \/>\n<\/sup>Therefore, 49 is the sum of first 7 odd natural numbers<\/span><br \/>\n<span style=\"color: #000000;\">49 = 1 + 3 + 5 + 7 + 9 + 11 + 13<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(ii)<\/strong> 121\u00a0= (11)<sup>2<br \/>\n<\/sup>Therefore, 121 is the sum of first 11 odd natural numbers<\/span><br \/>\n<span style=\"color: #000000;\">121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>9. How many numbers lie between squares of the following numbers?<br \/>\n<\/strong><strong>(i)<\/strong>\u00a012 and 13<br \/>\n<strong>(ii)<\/strong>\u00a025 and 26<br \/>\n<strong>(iii)<\/strong> 99 and 100<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>\u20182n\u2019 numbers lie between the square of two consecutive numbers n and (n+1).<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(i) 12 and 13<\/strong><\/span><br \/>\n<span style=\"color: #000000;\">Here, n = 12. <\/span><br \/>\n<span style=\"color: #000000;\">Thus, 2n = 2 \u00d7 12 = 24,<\/span><br \/>\n<span style=\"color: #000000;\">i.e., 24 numbers\u00a0lie between (12)<sup>2<\/sup>\u00a0and (13)<sup>2<\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(ii) 25 and 26 <\/strong><\/span><br \/>\n<span style=\"color: #000000;\">Here, n = 25 <\/span><br \/>\n<span style=\"color: #000000;\">Thus, 2n = 2 \u00d7 25 = 50, <\/span><br \/>\n<span style=\"color: #000000;\">i.e., 50 numbers\u00a0lie between (25)<sup>2<\/sup>\u00a0and (26)<sup>2<\/sup><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(iii) 99 and 100<\/strong><\/span><br \/>\n<span style=\"color: #000000;\">Here, n = 99 <\/span><br \/>\n<span style=\"color: #000000;\">Thus, 2n = 2 \u00d7 99 = 198, <\/span><br \/>\n<span style=\"color: #000000;\">i.e., 198 numbers between (99)<sup>2<\/sup>\u00a0and (100)<sup>2<\/sup><\/span><\/p>\n<p>&nbsp;<\/p>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 32px;\">\n<td style=\"width: 100%; background-color: #f2e079; text-align: center; height: 32px;\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong>NCERT Class 8<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; 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rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 8 Mathematics\u00a0 Chapter &#8211; 6 (Squares and Square)\u00a0 The NCERT Solutions in English Language for Class 8 Mathematics Chapter &#8211; 6 Squares and Square Exercise 6.1 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 6: Squares and Square Roots NCERT Solution Class 8 Maths [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[442],"tags":[454,455,445,5],"class_list":["post-3127","post","type-post","status-publish","format-standard","hentry","category-class-8-maths","tag-ncert-class-8-maths-chapter-6-squares-and-square-roots-in-english","tag-ncert-solutions-class-8-maths-chapter-6-in-english","tag-ncert-solutions-class-8-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.5) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.1 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 8 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