{"id":3098,"date":"2022-12-04T14:16:28","date_gmt":"2022-12-04T14:16:28","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=3098"},"modified":"2023-01-31T06:54:09","modified_gmt":"2023-01-31T06:54:09","slug":"ncert-solutions-class-8-maths-chapter-5-data-handling-ex-5-3","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-5-data-handling-ex-5-3\/","title":{"rendered":"NCERT Solutions Class 8 Maths Chapter 5 Data Handling Ex 5.3"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 8 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 5 (Data Handling)\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 8 Mathematics <strong>Chapter &#8211; 5 Data Handling <\/strong>Exercise 5.3 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Chapter 5: Data Handling<\/strong><\/span><\/h4>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-5-data-handling-ex-5-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 5.1<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-5-data-handling-ex-5-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 5.2<\/a><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 5.3\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. List the outcomes you can see in these experiments.<br \/>\n<\/strong><strong>(a) <\/strong>Spinning a wheel<strong><br \/>\n(b) <\/strong>Tossing two coins together<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3123\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-5.3-Q-1.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"158\" height=\"133\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong><br \/>\n<strong>(a)<\/strong> There are four letters A, B, C and D in a spinning wheel. So, there are 4 outcomes.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> When two coins are tossed together. There are four possible outcomes HH, HT, TH, and TT. (where, Head &#8211; H and Tail &#8211; T). Hence, there are 4 outcomes.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. When a die is thrown, list the outcomes of an event of getting<br \/>\n<\/strong><strong>(i) (a) <\/strong>a prime number <strong>(b) <\/strong>not a prime number<br \/>\n<strong>(ii) (a) <\/strong>a number greater than 5 <strong>(b) <\/strong>a number not greater than 5<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;\u00a0<\/strong>When a die is thrown, there are six possible outcomes 1, 2, 3, 4, 5 and 6<br \/>\n<strong>(i) (a)<\/strong> Outcomes of the event of getting a prime number are 2, 3 and 5.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> Outcomes of the event of not getting a prime number are 1, 4 and 6.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) (a)<\/strong> Outcomes of the event of getting a number greater than 5 is 6.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> Outcomes of the event of not getting a number greater than 5 are 1, 2, 3, 4 and 5.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Find the.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a) <\/strong>Probability of the pointer stopping on D in (Question 1-(a)).<br \/>\n<strong>(b) <\/strong>Probability of getting an ace from a well-shuffled deck of 52 playing cards.<br \/>\n<strong>(c) <\/strong>Probability of getting a red apple. (See figure below)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3123\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-5.3-Q-1.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"158\" height=\"133\" \/> <img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-3124\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-5.3-Q-3.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"149\" height=\"141\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(a)<\/strong> In a spinning wheel, there are five pointers A, A, B, C, D. So, there are five outcomes. The pointer stops at D, which is one outcome.<br \/>\nSo, the probability of the pointer stopping on D = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{5}\" alt=\"\\frac{1}{5}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> There are 4 aces in a deck of 52 playing cards. So, there are four events for getting an ace.<br \/>\nSo, the probability of getting an ace = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{4}{52}&amp;space;=&amp;space;\\frac{1}{13}\" alt=\"\\frac{4}{52} = \\frac{1}{13}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c)<\/strong> Total number of apples = 7<br \/>\nNumber of red apples = 4<br \/>\nProbability of getting a red apple = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{4}{7}\" alt=\"\\frac{4}{7}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of<br \/>\n<\/strong><strong>(i) <\/strong>getting a number 6?<br \/>\n<strong>(ii) <\/strong>getting a number less than 6?<br \/>\n<strong>(iii)<\/strong> getting a number greater than 6?<br \/>\n<strong>(iv) <\/strong>getting a 1-digit number?<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)<\/strong> Outcome of getting a number 6 from ten separate slips is one.<br \/>\n\u2234 probability of getting a number 6 = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{10}\" alt=\"\\frac{1}{10}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong> Numbers less than 6 are 1, 2, 3, 4 and 5, which are five. So, there are 5 outcomes.<br \/>\n\u2234 probability of getting a number less 6 = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{10}&amp;space;=&amp;space;\\frac{1}{2}\" alt=\"\\frac{5}{10} = \\frac{1}{2}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii)<\/strong> Number greater than 6 out of ten that are 7, 8, 9, 10. So there are 4 possible outcomes.<br \/>\n\u2234 probability of getting a number greater than 6 = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{4}{10}&amp;space;=&amp;space;\\frac{2}{5}\" alt=\"\\frac{4}{10} = \\frac{2}{5}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv)<\/strong> One-digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9 out of ten.<br \/>\n\u2234 probability of getting a 1-digit number = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{9}{10}\" alt=\"\\frac{9}{10}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>Given that there is a spinning wheel\u00a0with 3 green sectors, 1 blue sector and 1 red sector<br \/>\nTotal number of sectors = 5<\/span><br \/>\n<span style=\"color: #000000;\">Total number of green sectors = 3<\/span><br \/>\n<span style=\"color: #000000;\">Therefore, probability of getting a green sector = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{5}\" alt=\"\\frac{3}{5}\" align=\"absmiddle\" \/> <\/span><br \/>\n<span style=\"color: #000000;\">Total number of blue sectors = 1 <\/span><br \/>\n<span style=\"color: #000000;\">Total number of non-blue sectors = 5 \u2013 1 = 4 <\/span><br \/>\n<span style=\"color: #000000;\">Therefore, the probability of getting a non-blue sector = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{4}{5}\" alt=\"\\frac{4}{5}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. Find the probabilities of the events given in Question 2.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong>When a die is thrown, there is a total of six outcomes, i.e., 1, 2, 3, 4, 5 and 6.<br \/>\n<strong>(i) <\/strong><strong>(a)<\/strong> 2, 3, 5 are the prime numbers. So, there are 3 outcomes out of 6.<br \/>\n\u2234 probability of getting a prime number = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{6}\" alt=\"\\frac{3}{6}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{2}\" alt=\"\\frac{1}{2}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> 1, 4, 6 are not the prime numbers. So, there are 3 outcomes out of 6.<br \/>\n\u2234 probability of getting a prime number = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{6}\" alt=\"\\frac{3}{6}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{2}\" alt=\"\\frac{1}{2}\" align=\"absmiddle\" \/> <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) <\/strong><strong>(a)<\/strong> Only 6 is greater than 5.<br \/>\nSo there is one outcome out of 6.<br \/>\n\u2234 probability of getting a number greater than 5 = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{6}\" alt=\"\\frac{1}{6}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> Numbers not greater than 5 are 1, 2, 3, 4 and 5. So there are 5 outcomes out of 6.<br \/>\n\u2234 probability of not getting a number greater than 5 = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{6}\" alt=\"\\frac{5}{6}\" align=\"absmiddle\" \/><\/span><\/p>\n<p>&nbsp;<\/p>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 32px;\">\n<td style=\"width: 100%; background-color: #f2e079; text-align: center; height: 32px;\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong>NCERT Class 8<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 8 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-hindi\/\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 8 Hindi<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 8 Mathematics<\/a>\u00a0<\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-sanskrit-ruchira\/\" target=\"_blank\" rel=\"noopener\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\">NCERT Solutions Class 8 Sanskrit<\/span><\/strong><\/span><\/a><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 8 Mathematics\u00a0 Chapter &#8211; 5 (Data Handling)\u00a0 The NCERT Solutions in English Language for Class 8 Mathematics Chapter &#8211; 5 Data Handling Exercise 5.3 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 5: Data Handling NCERT Solution Class 8 Maths Ex &#8211; 5.1 NCERT [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[442],"tags":[452,453,445,5],"class_list":["post-3098","post","type-post","status-publish","format-standard","hentry","category-class-8-maths","tag-ncert-class-8-maths-chapter-5-data-handling-in-english","tag-ncert-solutions-class-8-maths-chapter-5-in-english","tag-ncert-solutions-class-8-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - 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