{"id":3068,"date":"2022-12-03T05:37:27","date_gmt":"2022-12-03T05:37:27","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=3068"},"modified":"2023-01-31T06:54:28","modified_gmt":"2023-01-31T06:54:28","slug":"ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-5","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-5\/","title":{"rendered":"NCERT Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.5"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 8 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 4 (Practical Geometry)\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 8 Mathematics <strong>Chapter &#8211; 4 Practical Geometry <\/strong>Exercise 4.5 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Chapter 4: Practical Geometry<\/strong><\/span><\/h4>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.1<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.2<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.3<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.4<\/a><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 4.5\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Draw the following:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. The square READ with RE = 5.1 cm<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3091\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.5-Q-1.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"203\" height=\"191\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Construction :<\/strong><br \/>\n<strong>Step I \u2013<\/strong> Draw RE = 5.1 cm.<br \/>\n<strong>Step II \u2013 <\/strong>Draw an angle of 90\u00b0 at E and cut EA = 5.1 cm.<br \/>\n<strong>Step III \u2013 <\/strong>Draw two arcs from A and R with radius 5.1 cm to cut each other at D.<br \/>\n<strong>Step IV \u2013 <\/strong>Join RD and AD.<br \/>\nThus, READ is the required square.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. A rhombus whose diagonals are 5.2 cm and 6.4 cm long. <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3092\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.5-Q-2.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"198\" height=\"197\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.5-Q-2.png 198w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.5-Q-2-150x150.png 150w\" sizes=\"auto, (max-width: 198px) 100vw, 198px\" \/><\/span><\/p>\n<p><strong>Construction :<br \/>\n<\/strong><strong>Step I \u2013 <\/strong>Draw AC = 6.4 cm.<br \/>\n<strong>Step II \u2013 <\/strong>Draw the right bisector of AC at E.<br \/>\n<span style=\"color: #000000;\"><strong>Step III \u2013 <\/strong>Draw two arcs with centre E and radius = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5.2}{2}\" alt=\"\\frac{5.2}{2}\" align=\"absmiddle\" \/> = 2.6 cm to cut the previous diagonal at B and D.<br \/>\n<strong>Step IV \u2013 <\/strong>Join AD, AB, BC and DC. <\/span><br \/>\n<span style=\"color: #000000;\">Thus ABCD is the required rhombus.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. A rectangle with adjacent sides of length 5 cm and 4 cm. <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3093\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.5-Q-3.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"196\" height=\"164\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Construction :<\/strong> Let the two adjacent sides of a rectangle PQRS be PQ = 5 cm and QR = 4 cm.<br \/>\n<strong>Step I \u2013 <\/strong>Draw PQ = 5 cm.<br \/>\n<strong>Step II \u2013 <\/strong>Draw an angle of 90\u00b0 at Q and cut QR = 4 cm.<br \/>\n<strong>Step III \u2013 <\/strong>Draw an arc with centre R and radius 5 cm.<br \/>\n<strong>Step IV \u2013 <\/strong>Draw another arc with centre P and radius 4 cm to meet the previous arc at S.<br \/>\n<strong>Step V \u2013 <\/strong>Join RS and PS.<br \/>\nThus, PQRS is the required rectangle.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm.\u00a0<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3094\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.5-Q-4.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"219\" height=\"175\" \/><\/strong><\/span><\/p>\n<p><strong>Construction :<\/strong><br \/>\n<strong>Step I \u2013 <\/strong>Draw OK = 5.5 cm.<br \/>\n<strong>Step II \u2013 <\/strong>Draw an angle of any measure (say 60\u00b0) at K and cut KA = 4.2 cm .<br \/>\n<strong>Step III \u2013 <\/strong>Draw an arc with centre A and radius of 5.5 cm.<br \/>\n<strong>Step IV \u2013 <\/strong>Draw another arc with centre O and radius 4.2 cm to cut the previous arc at Y.<br \/>\n<strong>Step V \u2013 <\/strong>Join AY and OY.<br \/>\nThus, OKAY is the required parallelogram.<br \/>\nNo, it is not a unique parallelogram. The angle at K can be of measure other than 60\u00b0.<\/p>\n<p>&nbsp;<\/p>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 32px;\">\n<td style=\"width: 100%; background-color: #f2e079; text-align: center; height: 32px;\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong>NCERT Class 8<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 8 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-hindi\/\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 8 Hindi<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 8 Mathematics<\/a>\u00a0<\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-sanskrit-ruchira\/\" target=\"_blank\" rel=\"noopener\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\">NCERT Solutions Class 8 Sanskrit<\/span><\/strong><\/span><\/a><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 8 Mathematics\u00a0 Chapter &#8211; 4 (Practical Geometry)\u00a0 The NCERT Solutions in English Language for Class 8 Mathematics Chapter &#8211; 4 Practical Geometry Exercise 4.5 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 4: Practical Geometry NCERT Solution Class 8 Maths Ex &#8211; 4.1 NCERT [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[442],"tags":[450,451,445,5],"class_list":["post-3068","post","type-post","status-publish","format-standard","hentry","category-class-8-maths","tag-ncert-class-8-maths-chapter-4-practical-geometry-in-english","tag-ncert-solutions-class-8-maths-chapter-4-in-english","tag-ncert-solutions-class-8-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - 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