{"id":3050,"date":"2022-12-03T05:36:46","date_gmt":"2022-12-03T05:36:46","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=3050"},"modified":"2023-01-31T06:55:46","modified_gmt":"2023-01-31T06:55:46","slug":"ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-1","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-1\/","title":{"rendered":"NCERT Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.1"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 8 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 4 (Practical Geometry)\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 8 Mathematics <strong>Chapter &#8211; 4 Practical Geometry <\/strong>Exercise 4.1 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Chapter 4: Practical Geometry<\/strong><\/span><\/h4>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.2<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.3<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.4<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-4-practical-geometry-ex-4-5\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 4.5<\/a><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 4.1\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Construct the following quadrilaterals.<\/strong><br \/>\n<strong>(i) Quadrilateral ABCD<br \/>\n<\/strong>AB = 4.5 cm<br \/>\nBC = 5.5 cm<br \/>\nCD = 4 cm<br \/>\nAD = 6 cm<br \/>\nAC = 7 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3074\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.1-Q-1i.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"128\" height=\"154\" \/><br \/>\n<\/strong><strong>Construction :<\/strong><br \/>\n<strong>Step I \u2013<\/strong> Draw AB = 4.5 cm<br \/>\n<strong>Step II \u2013 <\/strong>Draw an arc with centre B and radius 5.5 cm.<br \/>\n<strong>Step III \u2013 <\/strong>Draw another arc with centre A and radius 7 cm to meet the previous arc at C.<br \/>\n<strong>Step IV \u2013 <\/strong>Draw an arc with centre C and radius 4 cm.<br \/>\n<strong>Step V \u2013 <\/strong>Draw another arc with centre A and radius 6 cm to cut the former arc at D.<br \/>\n<strong>Step VI \u2013<\/strong> Join BC, AC, CD and AD.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) Quadrilateral JUMP<br \/>\n<\/strong>JU = 3.5 cm<br \/>\nUM = 4 cm<br \/>\nMP = 5 cm<br \/>\nPJ = 4.5 cm<br \/>\nPU = 6.5 cm <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3075\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.1-Q-1ii.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"127\" height=\"124\" \/><br \/>\n<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>Construction :<\/strong><\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step I \u2013 <\/strong>Draw JU = 3.5 cm.<\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step II \u2013 <\/strong>Draw an arc with centre J and radius 4.5 cm.<\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step III <\/strong><strong>\u2013 <\/strong>Draw another arc with centre U and radius 6.5 cm to meet the previous arc at P.<\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step IV \u2013 <\/strong>Join JP and UP.<\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step V \u2013 <\/strong>Draw an arc with centre U and radius 4 cm.<\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step VI \u2013 <\/strong>Draw another arc with centre P and radius 5 cm to meet the previous arc at M.<\/span><br \/>\n<span style=\"color: #000000;\"><strong>Step VII \u2013 <\/strong>Join UM and PM.<\/span><br \/>\n<span style=\"color: #000000;\">Thus, JUMP is the required quadrilateral.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) Parallelogram MORE<br \/>\n<\/strong>OR = 6 cm<br \/>\nRE = 4.5 cm,<br \/>\nEO = 7.5 cm<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3076\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.1-Q-1iii.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"141\" height=\"101\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Construction :\u00a0<\/strong><br \/>\n<strong>Step I \u2013 <\/strong>Draw OR = 6 cm.<br \/>\n<strong>Step II \u2013 <\/strong>Draw an arc with centre R and radius 4.5 cm.<br \/>\n<strong>Step III \u2013 <\/strong>Draw another arc with centre O and radius 7.5 cm to meet the previous arc at E.<br \/>\n<strong>Step IV \u2013 <\/strong>Join RE and OE.<br \/>\n<strong>Step V \u2013 <\/strong>Draw an arc with centre E and radius 6 cm.<br \/>\n<strong>Step VI \u2013 <\/strong>Draw another arc with centre O and radius 4.5 cm to meet the former arc at M.<br \/>\n<strong>Step VII \u2013 <\/strong>Join EM and OM.<br \/>\nThus, MORE is the required parallelogram.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) Rhombus BEST<br \/>\n<\/strong>BE = 4.5 cm<br \/>\nET = 6 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3077\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-4.1-Q-1iv.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"125\" height=\"127\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Construction :<\/strong> (All sides of a rhombus are equal)<br \/>\n<strong>Step I \u2013 <\/strong>Draw BE = 4.5 cm<br \/>\n<strong>Step II \u2013 <\/strong> Draw an arc with centre B and radius 4.5 cm.<br \/>\n<strong>Step III \u2013 <\/strong>Draw another arc with centre E and radius 6 cm to meet the previous arc at T.<br \/>\n<strong>Step IV \u2013 <\/strong>Join BT and ET.<br \/>\n<strong>Step V \u2013 <\/strong>Draw two arcs with centres E and T with equal radii 4-5 cm to meet each other at S. .<br \/>\n<strong>Step VI \u2013 <\/strong> Join ES and TS.<br \/>\nThus, BEST is the required rhombus.<\/span><\/p>\n<p>&nbsp;<\/p>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 32px;\">\n<td style=\"width: 100%; background-color: #f2e079; text-align: center; height: 32px;\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong>NCERT Class 8<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span 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class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 8 Mathematics<\/a>\u00a0<\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-sanskrit-ruchira\/\" target=\"_blank\" rel=\"noopener\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\">NCERT Solutions Class 8 Sanskrit<\/span><\/strong><\/span><\/a><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 8 Mathematics\u00a0 Chapter &#8211; 4 (Practical Geometry)\u00a0 The NCERT Solutions in English Language for Class 8 Mathematics Chapter &#8211; 4 Practical Geometry Exercise 4.1 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 4: Practical Geometry NCERT Solution Class 8 Maths Ex &#8211; 4.2 NCERT [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[442],"tags":[450,451,445,5],"class_list":["post-3050","post","type-post","status-publish","format-standard","hentry","category-class-8-maths","tag-ncert-class-8-maths-chapter-4-practical-geometry-in-english","tag-ncert-solutions-class-8-maths-chapter-4-in-english","tag-ncert-solutions-class-8-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.5) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 8 Maths Chapter 4 Practical Geometry Ex 4.1 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT 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