{"id":3025,"date":"2022-12-02T12:00:50","date_gmt":"2022-12-02T12:00:50","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=3025"},"modified":"2023-01-31T06:55:55","modified_gmt":"2023-01-31T06:55:55","slug":"ncert-solutions-class-8-maths-chapter-3-understanding-quadrilaterals-ex-3-3","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-3-understanding-quadrilaterals-ex-3-3\/","title":{"rendered":"NCERT Solutions Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.3"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 8 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 3 (Understanding Quadrilaterals)\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 8 Mathematics <strong>Chapter &#8211; 3 Understanding Quadrilaterals <\/strong>Exercise 3.3 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<h4><span style=\"color: #000000;\"><strong>Chapter 3: Understanding Quadrilaterals<\/strong><\/span><\/h4>\n<ul>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-3-understanding-quadrilaterals-ex-3-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 3.1<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-3-understanding-quadrilaterals-ex-3-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 3.2<\/a><\/li>\n<li><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-maths-chapter-3-understanding-quadrilaterals-ex-3-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 8 Maths Ex &#8211; 3.4<\/a><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 3.3\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Given a parallelogram ABCD. Complete each statement along with the definition or property used.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-3051\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-1.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"280\" height=\"148\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-1.png 535w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-1-300x159.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-1-480x254.png 480w\" sizes=\"auto, (max-width: 280px) 100vw, 280px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)<\/strong> AD = ______<br \/>\n<strong>(ii)<\/strong> \u2220DCB = ______<br \/>\n<strong>(iii)<\/strong> OC = ______<br \/>\n<strong>(iv)<\/strong> m \u2220DAB + m \u2220CDA = ______<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(i)<\/strong> AD = <strong><span style=\"text-decoration: underline;\">BC<\/span><\/strong> (Opposite sides of a parallelogram are equal)<br \/>\n<strong>(ii)<\/strong> \u2220DCB = <span style=\"text-decoration: underline;\"><strong>\u2220DAB<\/strong><\/span> (Opposite angles of a parallelogram are equal)<br \/>\n<strong>(iii)<\/strong> OC = <span style=\"text-decoration: underline;\"><strong>OA<\/strong><\/span> (Diagonals of a parallelogram are equal)<br \/>\n<strong>(iv)<\/strong> m \u2220DAB + m \u2220CDA = <span style=\"text-decoration: underline;\"><strong>180\u00b0<\/strong><\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Consider the following parallelograms. Find the values of the unknown x, y, z<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3052\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-2.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"578\" height=\"276\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-2.png 578w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-2-300x143.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-2-480x229.png 480w\" sizes=\"auto, (max-width: 578px) 100vw, 578px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i)\u00a0 <\/strong>y = 100\u00b0 (opposite angles of a parallelogram)<br \/>\nx + 100\u00b0 = 180\u00b0 (adjacent angles of a parallelogram)<br \/>\n\u21d2 x = 180\u00b0 \u2013 100\u00b0 = 80\u00b0<br \/>\nx = z = 80\u00b0 (opposite angles of a parallelogram)<br \/>\n\u2234 x = 80\u00b0, y = 100\u00b0 and z = 80\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) <\/strong>50\u00b0 + x = 180\u00b0<br \/>\n\u21d2 x = 180\u00b0 \u2013 50\u00b0 = 130\u00b0 (adjacent angles of a parallelogram)<br \/>\nx = y = 130\u00b0 (opposite angles of a parallelogram)<br \/>\nx = z = 130\u00b0 (corresponding angle)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) <\/strong>x = 90\u00b0 (vertical opposite angles)<br \/>\nx + y + 30\u00b0 = 180\u00b0 (angle sum property of a triangle)<br \/>\n\u21d2 90\u00b0 + y + 30\u00b0 = 180\u00b0<br \/>\n\u21d2 y = 180\u00b0 \u2013 120\u00b0 = 60\u00b0<br \/>\nalso, y = z = 60\u00b0 (alternate angles)<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv)\u00a0<\/strong>z = 80\u00b0 (corresponding angle)<br \/>\nz = y = 80\u00b0 (alternate angles)<br \/>\nx + y = 180\u00b0 (adjacent angles)<br \/>\n\u21d2 x + 80\u00b0 = 180\u00b0<br \/>\n\u21d2 x = 180\u00b0 \u2013 80\u00b0 = 100\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) <\/strong>y = 112\u00b0 {opposite angles of a parallelogram}<\/span><br \/>\n<span style=\"color: #000000;\">x = 180\u00b0 \u2013 (y + 40\u00b0) {angle sum property of a triangle}<\/span><br \/>\n<span style=\"color: #000000;\">x = 180\u00b0 \u2013 (112\u00b0+ 40\u00b0) = 180\u00b0 \u2013 162\u00b0 = 28\u00b0 <\/span><br \/>\n<span style=\"color: #000000;\">z = 28\u00b0 {alternate angles}<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Can a quadrilateral ABCD be a parallelogram if<br \/>\n(i) <\/strong>\u2220D + \u2220B = 180\u00b0?<strong><br \/>\n<\/strong><strong>(ii) <\/strong>AB = DC = 8 cm, AD = 4 cm and BC = 4.4 cm?<strong><br \/>\n<\/strong><strong>(iii) <\/strong>\u2220A = 70\u00b0 and \u2220C = 65\u00b0?<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(i)<\/strong> Yes,<br \/>\nThe quadrilateral ABCD be a parallelogram if \u2220D + \u2220B = 180\u00b0, it should also fulfilled some conditions which are: <\/span><br \/>\n<span style=\"color: #000000;\">(a) The sum of the adjacent angles should be 180\u00b0.<\/span><br \/>\n<span style=\"color: #000000;\">(b) Opposite angles must be equal.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong> No, opposite sides should be of the same length. Here, AD \u2260 BC<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii)<\/strong> No, opposite angles should be of the same measures. \u2220A \u2260 \u2220C<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles of equal measure.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-3053\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-4.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"206\" height=\"241\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-4.png 304w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-4-257x300.png 257w\" sizes=\"auto, (max-width: 206px) 100vw, 206px\" \/><br \/>\n<\/strong>ABCD is a figure of quadrilateral that is not a parallelogram but has exactly two opposite\u00a0angles, that is, \u2220B = \u2220D of equal measure. It is not a parallelogram because \u2220A \u2260 \u2220C.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. The measures of two adjacent angles of a parallelogram are in the ratio 3 : 2. Find the measure of each of the angles of the parallelogram.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Let the measures of two adjacent angles \u2220A and \u2220B be 3x and 2x, respectively in\u00a0parallelogram ABCD.<br \/>\n\u2220A + \u2220B = 180\u00b0<br \/>\n\u21d2 3x + 2x = 180\u00b0<br \/>\n\u21d2 5x = 180\u00b0<br \/>\n\u21d2 x = 36\u00b0<br \/>\nWe know that opposite sides of a parallelogram are equal.<br \/>\n\u2220A = \u2220C = 3x = 3 \u00d7 36\u00b0 = 108\u00b0<br \/>\n\u2220B = \u2220D = 2x = 2 \u00d7 36\u00b0 = 72\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. Two adjacent angles of a parallelogram have equal measure. Find the measure of each of the angles of the parallelogram.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Let ABCD be a parallelogram.<br \/>\nSum of adjacent angles of a parallelogram = 180\u00b0<br \/>\n\u2220A + \u2220B = 180\u00b0<br \/>\n\u21d2 2\u2220A = 180\u00b0<br \/>\n\u21d2 \u2220A = 90\u00b0<br \/>\nalso, 90\u00b0 + \u2220B = 180\u00b0<br \/>\n\u21d2 \u2220B = 180\u00b0 \u2013 90\u00b0 = 90\u00b0<br \/>\n\u2220A = \u2220C = 90\u00b0<br \/>\n\u2220B = \u2220D = 90\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. The adjacent figure HOPE is a parallelogram. Find the angle measures x, y and z. State the properties you use to find them.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3054\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-7.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"247\" height=\"224\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>y = 40\u00b0 (alternate interior angle)<br \/>\n\u2220P = 70\u00b0 (alternate interior angle)<br \/>\n\u2220P = \u2220H = 70\u00b0 (opposite angles of a parallelogram)<br \/>\nz = \u2220H \u2013 40\u00b0= 70\u00b0 \u2013 40\u00b0 = 30\u00b0<br \/>\n\u2220H + x = 180\u00b0<br \/>\n\u21d2 70\u00b0 + x = 180\u00b0<br \/>\n\u21d2 x = 180\u00b0 \u2013 70\u00b0 = 110\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8. The following figures GUNS and RUNS are parallelograms. Find x and y. (Lengths are in cm)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3055\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-8.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"657\" height=\"202\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-8.png 657w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-8-300x92.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-8-480x148.png 480w\" sizes=\"auto, (max-width: 657px) 100vw, 657px\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(i) <\/strong>SG = NU and SN = GU (opposite sides of a parallelogram are equal)<br \/>\n3x = 18<br \/>\n\u21d2 x =6<br \/>\n3y \u2013 1 = 26<br \/>\n\u21d2 3y = 26 + 1<br \/>\n\u21d2 y = 9<br \/>\nx = 6 and y = 9<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii)<\/strong> 20 = y + 7 and 16 = x + y (diagonals of a parallelogram bisect each other)<br \/>\ny + 7 = 20<br \/>\n\u21d2 y = 20 \u2013 7 = 13 and,<br \/>\nx + y = 16<br \/>\n\u21d2 x + 13 = 16<br \/>\n\u21d2 x = 16 \u2013 13 = 3<br \/>\nx = 3 and y = 13<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>9. In the above figure both RISK and CLUE are parallelograms. Find the value of x.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3056\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-9.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"427\" height=\"157\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-9.png 427w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-9-300x110.png 300w\" sizes=\"auto, (max-width: 427px) 100vw, 427px\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>\u2220K + \u2220R = 180\u00b0 (adjacent angles of a parallelogram are supplementary)<br \/>\n\u21d2 120\u00b0 + \u2220R = 180\u00b0<br \/>\n\u21d2 \u2220R = 180\u00b0 \u2013 120\u00b0 = 60\u00b0<br \/>\nalso, \u2220R = \u2220SIL (corresponding angles)<br \/>\n\u21d2 \u2220SIL = 60\u00b0<br \/>\nalso, \u2220ECR = \u2220L = 70\u00b0 (corresponding angles)<br \/>\nx + 60\u00b0 + 70\u00b0 = 180\u00b0 (angle sum of a triangle)<br \/>\n\u21d2 x + 130\u00b0 = 180\u00b0<br \/>\n\u21d2 x = 180\u00b0 \u2013 130\u00b0 = 50\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>10. Explain how this figure is a trapezium. Which of its two sides are parallel? (Fig 3.32)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3057\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-10.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"269\" height=\"191\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">In the given figure KLMN<br \/>\nSince two pair of adjacent angles which form pairs of consecutive interior angles are supplementary,<br \/>\ni.e., \u2220L + \u2220M = 180\u00b0<br \/>\nThus, 80\u00b0 + 100\u00b0 = 180\u00b0<br \/>\nTherefore, NM is parallel to KL<br \/>\nHence, KLMN is a trapezium as it has a pair of parallel sides KL and NM.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>11. Find m\u2220C in Fig 3.33 if AB || DC.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3058\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-11.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"279\" height=\"187\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Given figure ABCD is a Trapezium, in which AB is parallel to DC .<\/span><br \/>\n<span style=\"color: #000000;\">Here,<\/span><br \/>\n<span style=\"color: #000000;\">\u2220B + \u2220C = 180\u00b0 (pair of adjacent angles are\u00a0supplementary)<\/span><br \/>\n<span style=\"color: #000000;\">120\u00b0 + \u2220C = 180\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220C = 180\u00b0 &#8211; 120\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220C = 60\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">Therefore, m\u2220C = 60\u00b0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>12. Find the measure of \u2220P and \u2220S if SP || RQ ? in Fig 3.34. (If you find m\u2220R, is there more than one\u00a0<\/strong><strong>method to find m\u2220P?)<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3059\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/11\/NCERT-Solutions-Class-8-Maths-Ex-3.3-Q-12.png\" alt=\"NCERT Maths Solutions Class 8\" width=\"187\" height=\"259\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;\u00a0<\/strong>Given SP is parallel to RQ and SR is the traversal drawn to these lines. Hence, SPQR is a\u00a0trapezium.<\/span><br \/>\n<span style=\"color: #000000;\">\u2220S + \u2220R = 180\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220S + 90\u00b0 = 180\u00b0 [Since,\u00a0\u2220R =\u00a090\u00b0 in the given figure]<\/span><br \/>\n<span style=\"color: #000000;\">\u2220S = 180\u00b0 &#8211; 90\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220S = 90\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">Using the angle sum property of a quadrilateral,<\/span><br \/>\n<span style=\"color: #000000;\">\u2220S + \u2220P + \u2220Q + \u2220R = 360\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">90\u00b0 + \u2220P + 130\u00b0 + 90\u00b0 = 360\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220P + 310\u00b0 = 360\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220P = 360\u00b0 &#8211; 310\u00b0<\/span><br \/>\n<span style=\"color: #000000;\">\u2220P = 50\u00b0<\/span><\/p>\n<p>&nbsp;<\/p>\n<table style=\"width: 100%; border-collapse: collapse;\" border=\"1\">\n<tbody>\n<tr style=\"height: 32px;\">\n<td style=\"width: 100%; background-color: #f2e079; text-align: center; height: 32px;\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong>NCERT Class 8<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 8 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a 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style=\"font-family: georgia, palatino, serif; font-size: 12pt;\">NCERT Solutions Class 8 Sanskrit<\/span><\/strong><\/span><\/a><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 28px;\">\n<td style=\"width: 100%; text-align: left; height: 28px;\"><span style=\"font-size: 14pt;\"><strong><span style=\"font-family: georgia, palatino, serif; font-size: 12pt;\"><a class=\"row-title\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-8-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 8 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 8 Mathematics\u00a0 Chapter &#8211; 3 (Understanding Quadrilaterals)\u00a0 The NCERT Solutions in English Language for Class 8 Mathematics Chapter &#8211; 3 Understanding Quadrilaterals Exercise 3.3 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter 3: Understanding Quadrilaterals NCERT Solution Class 8 Maths Ex &#8211; 3.1 NCERT [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[442],"tags":[448,449,445,5],"class_list":["post-3025","post","type-post","status-publish","format-standard","hentry","category-class-8-maths","tag-ncert-class-8-maths-chapter-3-understanding-quadrilaterals-in-english","tag-ncert-solutions-class-8-maths-chapter-3-in-english","tag-ncert-solutions-class-8-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.3 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 8 Mathematics\u00a0Chapter - 3 (Understanding Quadrilaterals)\u00a0The NCERT Solutions in English 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