{"id":2139,"date":"2022-11-09T05:24:59","date_gmt":"2022-11-09T05:24:59","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=2139"},"modified":"2022-11-09T05:24:59","modified_gmt":"2022-11-09T05:24:59","slug":"ncert-solutions-class-7-maths-chapter-12-algebraic-expressions-ex-12-3","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-12-algebraic-expressions-ex-12-3\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.3"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 12 (Algebraic Expressions)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 12 Algebraic Expressions\u00a0 <\/strong>Exercise 12.3 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Chapter : 12 Algebraic Expressions<\/strong><\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-12-algebraic-expressions-ex-12-1\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 12.1<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-12-algebraic-expressions-ex-12-2\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 12.2<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-12-algebraic-expressions-ex-12-4\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 12.4<\/span><\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 12.3\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. If m = 2, find the value of:<br \/>\n<\/strong><strong>(i) m \u2013 2<br \/>\n(ii) 3m \u2013 5<br \/>\n(iii) 9 \u2013 5m<br \/>\n(iv) 3m<sup>2<\/sup>\u00a0\u2013 2m \u2013 7<br \/>\n(v) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mathbf{\\frac{5m}{2}}\" alt=\"\\mathbf{\\frac{5m}{2}}\" align=\"absmiddle\" \/> <span id=\"MathJax-Element-1-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-1\" class=\"math\"><span id=\"MathJax-Span-2\" class=\"mrow\"><span id=\"MathJax-Span-8\" class=\"mo\">\u2212 <\/span><span id=\"MathJax-Span-9\" class=\"mn\">4<\/span><\/span><\/span><\/span><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(i) m \u2013 2<br \/>\n<\/strong>Putting m = 2, we get <\/span><br \/>\n<span style=\"color: #000000;\">2 \u2013 2 <\/span><br \/>\n<span style=\"color: #000000;\">= 0<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(ii) 3m \u2013 5<br \/>\n<\/strong>Putting m = 2, we get <\/span><br \/>\n<span style=\"color: #000000;\">3 \u00d7 2 \u2013 5 <\/span><br \/>\n<span style=\"color: #000000;\">= 6 \u2013 5 <\/span><br \/>\n<span style=\"color: #000000;\">= 1<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(iii) 9 \u2013 5m<\/strong><\/span><br \/>\n<span style=\"color: #000000;\">Putting m = 2, we get<\/span><br \/>\n<span style=\"color: #000000;\">9 \u2013 5 \u00d7 2 <\/span><br \/>\n<span style=\"color: #000000;\">= 9 \u2013 10 <\/span><br \/>\n<span style=\"color: #000000;\">= -1<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(iv) 3m<sup>2<\/sup>\u00a0\u2013 2m \u2013 7<\/strong> <\/span><br \/>\n<span style=\"color: #000000;\">Putting m = 2, we get <\/span><br \/>\n<span style=\"color: #000000;\">3(2)<sup>2<\/sup>\u00a0\u2013 2(2) \u2013 7 <\/span><br \/>\n<span style=\"color: #000000;\">= 3 \u00d7 4 \u2013 4 \u2013 7<\/span><br \/>\n<span style=\"color: #000000;\">= 12 \u2013 4 \u2013 7 <\/span><br \/>\n<span style=\"color: #000000;\">= 12 \u2013 11 <\/span><br \/>\n<span style=\"color: #000000;\">= 1<\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>(v) <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mathbf{\\frac{5m}{2}}\" alt=\"\\mathbf{\\frac{5m}{2}}\" align=\"absmiddle\" \/> <span id=\"MathJax-Element-2-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-10\" class=\"math\"><span id=\"MathJax-Span-11\" class=\"mrow\"><span id=\"MathJax-Span-17\" class=\"mo\">\u2212 <\/span><span id=\"MathJax-Span-18\" class=\"mn\">4<br \/>\n<\/span><\/span><\/span><\/span><\/strong>Putting m = 2, we get<\/span><br \/>\n<span id=\"MathJax-Element-3-Frame\" class=\"MathJax\" style=\"color: #000000;\" tabindex=\"0\"><span id=\"MathJax-Span-19\" class=\"math\"><span id=\"MathJax-Span-20\" class=\"mrow\"><span id=\"MathJax-Span-29\" class=\"mo\"><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5\\times&amp;space;2}{2}\" alt=\"\\frac{5\\times 2}{2}\" align=\"absmiddle\" \/> &#8211; 4<br \/>\n= <\/span><span id=\"MathJax-Span-30\" class=\"mn\">5 <\/span><span id=\"MathJax-Span-31\" class=\"mo\">\u2212 <\/span><span id=\"MathJax-Span-32\" class=\"mn\">4<br \/>\n<\/span><span id=\"MathJax-Span-33\" class=\"mo\">= <\/span><span id=\"MathJax-Span-34\" class=\"mn\">1<\/span><\/span><\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. If p = \u2013 2, find the value of:<br \/>\n<\/strong><strong>(i) 4p + 7<br \/>\n(ii) -3p<sup>2<\/sup>\u00a0+ 4p + 7<br \/>\n(iii) -2p<sup>3<\/sup>\u00a0\u2013 3p<sup>2<\/sup>\u00a0+ 4p + 7<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) 4p + 7<br \/>\n<\/strong>Putting p = -2, we get<br \/>\n= (4 \u00d7 (-2)) + 7<br \/>\n= -8 + 7<br \/>\n= -1<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) \u2013 3p<sup>2<\/sup>\u00a0+ 4p + 7<br \/>\n<\/strong>Putting p = -2, we get<br \/>\n= (-3 \u00d7 (-2)<sup>2<\/sup>) + (4 \u00d7 (-2)) + 7<br \/>\n= (-3 \u00d7 4) + (-8) + 7<br \/>\n= -12 \u2013 8 + 7<br \/>\n= -20 + 7<br \/>\n= -13<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) \u2013 2p<sup>3<\/sup>\u00a0\u2013 3p<sup>2<\/sup>\u00a0+ 4p + 7<br \/>\n<\/strong>Putting p = -2, we get<br \/>\n= (-2 \u00d7 (-2)<sup>3<\/sup>) \u2013 (3 \u00d7 (-2)<sup>2<\/sup>) + (4 \u00d7 (-2)) + 7<br \/>\n= (-2 \u00d7 -8) \u2013 (3 \u00d7 4) + (-8) + 7<br \/>\n= 16 \u2013 12 \u2013 8 + 7<br \/>\n= 23 \u2013 20<br \/>\n= 3<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Find the value of the following expressions, when x = \u20131:<br \/>\n<\/strong><strong>(i) 2x \u2013 7<br \/>\n(ii) \u2013 x + 2<br \/>\n<\/strong><strong>(iii) x<sup>2<\/sup>\u00a0+ 2x + 1<br \/>\n(iv) 2x<sup>2<\/sup>\u00a0\u2013 x \u2013 2<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) 2x \u2013 7<br \/>\n<\/strong>Putting x = -1, we get<br \/>\n= (2 \u00d7 -1) \u2013 7<br \/>\n= \u2013 2 \u2013 7<br \/>\n= \u2013 9<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) \u2013 x + 2<br \/>\n<\/strong>Putting x = -1, we get<br \/>\n= \u2013 (-1) + 2<br \/>\n= 1 + 2<br \/>\n= 3<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) x<sup>2<\/sup>\u00a0+ 2x + 1<br \/>\n<\/strong>Putting x = -1, we get<br \/>\n= (-1)<sup>2<\/sup>\u00a0+ (2 \u00d7 -1) + 1<br \/>\n= 1 \u2013 2 + 1<br \/>\n= 2 \u2013 2<br \/>\n= 0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) 2x<sup>2<\/sup>\u00a0\u2013 x \u2013 2<br \/>\n<\/strong>Putting x = -1, we get<br \/>\n= (2 \u00d7 (-1)<sup>2<\/sup>) \u2013 (-1) \u2013 2<br \/>\n= (2 \u00d7 1) + 1 \u2013 2<br \/>\n= 2 + 1 \u2013 2<br \/>\n= 3 \u2013 2<br \/>\n= 1<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. If a = 2, b = \u2013 2, find the value of:<br \/>\n<\/strong><strong>(i) a<sup>2<\/sup>\u00a0+ b<sup>2<br \/>\n<\/sup><\/strong><strong>(ii) a<sup>2<\/sup>\u00a0+ ab + b<sup>2<\/sup><br \/>\n(iii) a<sup>2<\/sup>\u00a0\u2013 b<sup>2<\/sup><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup><\/strong><br \/>\nPutting a = 2 and b = -2, we get<br \/>\n= (2)<sup>2<\/sup>\u00a0+ (-2)<sup>2<br \/>\n<\/sup>= 4 + 4<br \/>\n= 8<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) a<sup>2<\/sup>\u00a0+ ab + b<sup>2<br \/>\n<\/sup><\/strong>Putting a = 2 and b = -2, we get<br \/>\n= 2<sup>2<\/sup>\u00a0+ (2 \u00d7 -2) + (-2)<sup>2<br \/>\n<\/sup>= 4 + (-4) + (4)<br \/>\n= 4 \u2013 4 + 4<br \/>\n= 4<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) a<sup>2<\/sup>\u00a0\u2013 b<sup>2<br \/>\n<\/sup><\/strong>Putting a = 2 and b = -2, we get<br \/>\n= 2<sup>2<\/sup>\u00a0\u2013 (-2)<sup>2<br \/>\n<\/sup>= 4 \u2013 (4)<br \/>\n= 4 \u2013 4<br \/>\n= 0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. When a = 0, b = \u2013 1, find the value of the given expressions:<br \/>\n<\/strong><strong>(i) 2a + 2b<br \/>\n(ii) 2a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ 1<br \/>\n(iii) 2a<sup>2<\/sup>b + 2ab<sup>2<\/sup>\u00a0+ ab<br \/>\n(iv) a<sup>2<\/sup>\u00a0+ ab + 2<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) 2a + 2b<br \/>\n<\/strong>Putting a = 0 and b = -1, we get<br \/>\n= (2 \u00d7 0) + (2 \u00d7 -1)<br \/>\n= 0 \u2013 2<br \/>\n= -2<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) 2a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ 1<br \/>\n<\/strong>Putting a = 0 and b = -1, we get<br \/>\n= (2 \u00d7 0<sup>2<\/sup>) + (-1)<sup>2<\/sup>\u00a0+ 1<br \/>\n= 0 + 1 + 1<br \/>\n= 2<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) 2a<sup>2<\/sup>b + 2ab<sup>2<\/sup>\u00a0+ ab<br \/>\n<\/strong>Putting a = 0 and b = -1, we get<br \/>\n= (2 \u00d7 0<sup>2<\/sup>\u00a0\u00d7 -1) + (2 \u00d7 0 \u00d7 (-1)<sup>2<\/sup>) + (0 \u00d7 -1)<br \/>\n= 0 + 0 +0<br \/>\n= 0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) a<sup>2<\/sup>\u00a0+ ab + 2<br \/>\n<\/strong>Putting a = 0 and b = -1, we get<br \/>\n= (0<sup>2<\/sup>) + (0 \u00d7 (-1)) + 2<br \/>\n= 0 + 0 + 2<br \/>\n= 2<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. Simplify the expressions and find the value if x is equal to 2<br \/>\n<\/strong><strong>(i) x + 7 + 4 (x \u2013 5)<br \/>\n(ii) 3(x + 2) + 5x \u2013 7<br \/>\n(iii) 6x + 5(x \u2013 2)<br \/>\n(iv) 4(2x \u2013 1) + 3x + 11<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) x + 7 + 4 (x \u2013 5)<br \/>\n<\/strong>= x + 7 + 4x \u2013 20<br \/>\n= 5x + 7 \u2013 20<br \/>\nPutting x = 2, we get<br \/>\n= (5 \u00d7 2) + 7 \u2013 20<br \/>\n= 10 + 7 \u2013 20<br \/>\n= 17 \u2013 20<br \/>\n= \u2013 3<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) 3 (x + 2) + 5x \u2013 7<br \/>\n<\/strong>= 3x + 6 + 5x \u2013 7<br \/>\n= 8x \u2013 1<br \/>\nPutting x = 2, we get<br \/>\n= (8 \u00d7 2) \u2013 1<br \/>\n= 16 \u2013 1<br \/>\n= 15<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) 6x + 5 (x \u2013 2)<br \/>\n<\/strong>= 6x + 5x \u2013 10<br \/>\n= 11x \u2013 10<br \/>\nPutting x = 2, we get<br \/>\n= (11 \u00d7 2) \u2013 10<br \/>\n= 22 \u2013 10<br \/>\n= 12<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) 4(2x \u2013 1) + 3x + 11<br \/>\n<\/strong>= 8x \u2013 4 + 3x + 11<br \/>\n= 11x + 7<br \/>\nPutting x = 2, we get<br \/>\n= (11 \u00d7 2) + 7<br \/>\n= 22 + 7<br \/>\n= 29<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. Simplify these expressions and find their values if x = 3, a = \u2013 1, b = \u2013 2.<br \/>\n<\/strong><strong>(i) 3x \u2013 5 \u2013 x + 9<br \/>\n(ii) 2 \u2013 8x + 4x + 4<br \/>\n(iii) 3a + 5 \u2013 8a + 1<br \/>\n(iv) 10 \u2013 3b \u2013 4 \u2013 55<br \/>\n(v) 2a \u2013 2b \u2013 4 \u2013 5 + a<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) 3x \u2013 5 \u2013 x + 9<br \/>\n<\/strong>= 3x \u2013 x \u2013 5 + 9<br \/>\n= 2x + 4<br \/>\nPutting x = 3, we get<br \/>\n= (2 \u00d7 3) + 4<br \/>\n= 6 + 4<br \/>\n= 10<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) 2 \u2013 8x + 4x + 4<br \/>\n<\/strong>= 2 + 4 \u2013 8x + 4x<br \/>\n= 6 \u2013 4x<br \/>\nPutting x = 3, we get<br \/>\n= 6 \u2013 (4 \u00d7 3)<br \/>\n= 6 \u2013 12<br \/>\n= \u2013 6<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) 3a + 5 \u2013 8a + 1<br \/>\n<\/strong>= 3a \u2013 8a + 5 + 1<br \/>\n= \u2013 5a + 6<br \/>\nPutting a = -1, we get<br \/>\n= \u2013 (5 \u00d7 (-1)) + 6<br \/>\n= \u2013 (-5) + 6<br \/>\n= 5 + 6<br \/>\n= 11<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iv) 10 \u2013 3b \u2013 4 \u2013 5b<br \/>\n<\/strong>= 10 \u2013 4 \u2013 3b \u2013 5b<br \/>\n= 6 \u2013 8b<br \/>\nPutting b = -2, we get<br \/>\n= 6 \u2013 (8 \u00d7 (-2))<br \/>\n= 6 \u2013 (-16)<br \/>\n= 6 + 16<br \/>\n= 22<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(v) 2a \u2013 2b \u2013 4 \u2013 5 + a<br \/>\n<\/strong>= 2a + a \u2013 2b \u2013 4 \u2013 5<br \/>\n= 3a \u2013 2b \u2013 9<br \/>\nPutting a = -1 and b = -2, we get<br \/>\n= (3 \u00d7 (-1)) \u2013 (2 \u00d7 (-2)) \u2013 9<br \/>\n= -3 \u2013 (-4) \u2013 9<br \/>\n= \u2013 3 + 4 \u2013 9<br \/>\n= -12 + 4<br \/>\n= -8<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8.<br \/>\n(i) If z = 10, find the value of z<sup>3<\/sup>\u00a0\u2013 3(z \u2013 10).<br \/>\n(ii) If p = -10, find the value of p<sup>2<\/sup>\u00a0-2p \u2013 100.<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) If z = 10, find the value of z<sup>2<\/sup>\u00a0\u2013 3(z \u2013 10).<\/strong><br \/>\n= z<sup>2<\/sup>\u00a0\u2013 3(z \u2013 10)<br \/>\n= z<sup>2<\/sup>\u00a0\u2013 3z + 30<br \/>\nPutting z = 10, we get<br \/>\n= (10)<sup>2<\/sup>\u00a0\u2013 3(10) + 30<br \/>\n= 1000 \u2013 30 + 30<br \/>\n= 1000<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) If p = \u2013 10, find the value of p<sup>2<\/sup>\u00a0\u2013 2p \u2013 100<br \/>\n<\/strong>Putting p = -10, we get<br \/>\n= (-10)<sup>2<\/sup>\u00a0\u2013 2(-10) \u2013 100<br \/>\n= 100 + 20 \u2013 100<br \/>\n= 20<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>9. What should be the value of a if the value of 2x<sup>2<\/sup>\u00a0+ x \u2013 a equals to 5, when x = 0?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>2x<sup>2<\/sup>\u00a0+ x \u2013 a = 5<br \/>\na = 2x<sup>2<\/sup>\u00a0+ x \u2013 5<br \/>\nPutting x = 0, we get<br \/>\na = (2 \u00d7 0<sup>2<\/sup>) + 0 \u2013 5<br \/>\na = 0 + 0 \u2013 5<br \/>\na = -5<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>10. Simplify the expression and find its value when a = 5 and b = \u2013 3.<br \/>\n<\/strong><strong>2(a<sup>2<\/sup>\u00a0+ ab) + 3 \u2013 ab<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>2(a<sup>2<\/sup> + ab) + 3 \u2013 ab<br \/>\n= 2a2 + 2ab + 3 \u2013 ab<br \/>\n= 2a<sup>2<\/sup>\u00a0+ 2ab \u2013 ab + 3<br \/>\n= 2ab + ab + 3<br \/>\nPutting, a = 5 and b = -3, we get<br \/>\n= 2(5)<sup>2<\/sup>\u00a0+ (5)(-3) + 3<br \/>\n= 2 \u00d7 25 \u2013 15 + 3<br \/>\n= 50 \u2013 15 + 3<br \/>\n= 53 \u2013 15<br \/>\n= 38<\/span><\/p>\n<p style=\"text-align: justify;\">\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Mathematics\u00a0 Chapter &#8211; 12 (Algebraic Expressions) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 12 Algebraic Expressions\u00a0 Exercise 12.3 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 12 Algebraic Expressions NCERT Solution Class 7 Maths Exercise &#8211; 12.1 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[343,344,283,5],"class_list":["post-2139","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-12-algebraic-expressions-in-english","tag-ncert-solutions-class-7-maths-chapter-12-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - 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