{"id":2093,"date":"2022-11-09T05:19:19","date_gmt":"2022-11-09T05:19:19","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=2093"},"modified":"2022-11-09T05:19:19","modified_gmt":"2022-11-09T05:19:19","slug":"ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 11 (Perimeter and Area)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 11 Perimeter and Area <\/strong>Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Chapter : 11 Perimeter and Area<\/strong><\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-1\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 11.1<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 11.3<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-1\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 11.4<\/span><\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 11.2\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Find the area of each of the following parallelograms:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2103\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"876\" height=\"438\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png 876w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1-300x150.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1-768x384.png 768w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1-480x240.png 480w\" sizes=\"auto, (max-width: 876px) 100vw, 876px\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">From the figure,<br \/>\n<strong>(a)<\/strong><br \/>\nHeight of parallelogram = 4 cm<br \/>\nBase of parallelogram = 7 cm<br \/>\nThen,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n= 7 cm \u00d7 4 cm<br \/>\n= 28 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<br \/>\n<\/strong>Height of parallelogram = 3 cm<br \/>\nBase of parallelogram = 5 cm<br \/>\nThen,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n= 5 cm \u00d7 3 cm<br \/>\n= 15 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c)<br \/>\n<\/strong>Height of parallelogram = 3.5 cm<br \/>\nBase of parallelogram = 2.5 cm<br \/>\nThen,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n= 2.5 cm \u00d7 3.5 cm<br \/>\n= 8.75 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d)<br \/>\n<\/strong>Height of parallelogram = 4.8 cm<br \/>\nBase of parallelogram = 5 cm<br \/>\nThen,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n= 5 \u00d7 4.8<br \/>\n= 24 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(e)<br \/>\n<\/strong>Height of parallelogram = 4.4 cm<br \/>\nBase of parallelogram = 2 cm<br \/>\nThen,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n= 2 cm \u00d7 4.4 cm<br \/>\n= 8.8 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Find the area of each of the following triangles:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2102\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q2.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"1287\" height=\"299\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q2.png 1287w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q2-300x70.png 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q2-1024x238.png 1024w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q2-768x178.png 768w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q2-480x112.png 480w\" sizes=\"auto, (max-width: 1287px) 100vw, 1287px\" \/><br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>From the figure, <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a)<br \/>\n<\/strong>Base of triangle = 4 cm<br \/>\nHeight of height = 3 cm<br \/>\nThen,<br \/>\nArea of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n= \u00bd \u00d7 4 cm \u00d7 3 cm<br \/>\n= 1 \u00d7 2 cm \u00d7 3 cm<br \/>\n= 6 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<br \/>\n<\/strong>Base of triangle = 3.2 cm<br \/>\nHeight of height = 5 cm<br \/>\nThen,<br \/>\nArea of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n= \u00bd \u00d7 3.2 cm \u00d7 5 cm<br \/>\n= 1 \u00d7 1.6 cm \u00d7 5 cm<br \/>\n= 8 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c)<br \/>\n<\/strong>Base of triangle = 3 cm<br \/>\nHeight of height = 4 cm<br \/>\nThen,<br \/>\nArea of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n= \u00bd \u00d7 3 cm \u00d7 4 cm<br \/>\n= 1 \u00d7 3 cm \u00d7 2 cm<br \/>\n= 6 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d)<br \/>\n<\/strong>Base of triangle = 3 cm<br \/>\nHeight of height = 2 cm<br \/>\nThen, Area of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n= \u00bd \u00d7 3 cm \u00d7 2 cm<br \/>\n= 1 \u00d7 3 cm \u00d7 1 cm<br \/>\n= 3 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Find the missing values:<\/strong><\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\" style=\"width: 70%; height: 132px;\">\n<tbody>\n<tr style=\"height: 24px;\">\n<td style=\"height: 24px;\"><span style=\"color: #000000;\"><strong>S.No.<\/strong><\/span><\/td>\n<td style=\"height: 24px;\"><span style=\"color: #000000;\"><strong>Base<\/strong><\/span><\/td>\n<td style=\"height: 24px;\"><span style=\"color: #000000;\"><strong>Height<\/strong><\/span><\/td>\n<td style=\"height: 24px;\"><span style=\"color: #000000;\"><strong>Area of the Parallelogram<\/strong><\/span><\/td>\n<\/tr>\n<tr style=\"height: 27px;\">\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">a.<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">20 cm<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">________<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">246 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr style=\"height: 27px;\">\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">b.<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">________<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">15 cm<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">154.5 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr style=\"height: 27px;\">\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">c.<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">________<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">8.4 cm<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">48.72 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr style=\"height: 27px;\">\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">d.<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">15.6 cm<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">________<\/span><\/td>\n<td style=\"text-align: center; height: 27px;\"><span style=\"color: #000000;\">16.38 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211; <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a)<br \/>\n<\/strong>Base of parallelogram = 20 cm<br \/>\nHeight of parallelogram =?<br \/>\nArea of the parallelogram = 246 cm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n246 = 20 \u00d7 height<br \/>\nHeight = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{246}{20}\" alt=\"\\frac{246}{20}\" align=\"absmiddle\" \/><br \/>\nHeight = 12.3 cm<br \/>\n\u2234 Height of the parallelogram is 12.3 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<br \/>\n<\/strong>Base of parallelogram =?<br \/>\nHeight of parallelogram =15 cm<br \/>\nArea of the parallelogram = 154.5 cm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n154.5 = base \u00d7 15<br \/>\nBase = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{154.5}{15}\" alt=\"\\frac{154.5}{15}\" align=\"absmiddle\" \/> cm<br \/>\nBase = 10.3 cm<br \/>\n\u2234 Base of the parallelogram is 10.3 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c)<br \/>\n<\/strong>Base of parallelogram =?<br \/>\nHeight of parallelogram =8.4 cm<br \/>\nArea of the parallelogram = 48.72 cm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n48.72 = base \u00d7 8.4<br \/>\nBase = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{48.72}{8.4}\" alt=\"\\frac{48.72}{8.4}\" align=\"absmiddle\" \/>cm<br \/>\nBase = 5.8 cm<br \/>\n\u2234 Base of the parallelogram is 5.8 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d)<br \/>\n<\/strong>Base of parallelogram = 15.6 cm<br \/>\nHeight of parallelogram =?<br \/>\nArea of the parallelogram = 16.38 cm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of parallelogram = base \u00d7 height<br \/>\n16.38 = 15.6 \u00d7 height<br \/>\nHeight = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{16.38}{15.6}\" alt=\"\\frac{16.38}{15.6}\" align=\"absmiddle\" \/><br \/>\nHeight = 1.05 cm<br \/>\n\u2234 Height of the parallelogram is 1.05 cm.<\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\" style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>S.No.<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Base<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Height<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Area of the Parallelogram<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">a.<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">20 cm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"text-decoration: underline; color: #000000;\"><strong>12.3 cm<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">246 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">b.<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"text-decoration: underline; color: #000000;\"><strong>10.3 cm<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">15 cm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">154.5 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">c.<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"text-decoration: underline; color: #000000;\"><strong>5.8 cm<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">8.4 cm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">48.72 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">d.<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">15.6 cm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"text-decoration: underline; color: #000000;\"><strong>1.05<\/strong><\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">16.38 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Find the missing values:<\/strong><\/span><\/p>\n<div class=\"table-responsive\" style=\"text-align: justify;\">\n<table class=\"table table-bordered\" style=\"width: 50%;\">\n<tbody>\n<tr>\n<td><span style=\"color: #000000;\"><strong>Base<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Height<\/strong><\/span><\/td>\n<td><span style=\"color: #000000;\"><strong>Area of Triangle<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">15 cm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">______<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">87 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">______<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">31.4 mm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">1256 mm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">22 cm<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">______<\/span><\/td>\n<td style=\"text-align: center;\"><span style=\"color: #000000;\">170.5 cm<sup>2<\/sup><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a)<br \/>\n<\/strong>Height of triangle =?<br \/>\nBase of triangle = 15 cm<br \/>\nArea of the triangle = 16.38 cm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n87 = \u00bd \u00d7 15 \u00d7 height<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Height = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{87\\times&amp;space;2}{15}\" alt=\"\\frac{87\\times 2}{15}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{174}{15}\" alt=\"\\frac{174}{15}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Height = 11.6 cm<br \/>\n\u2234 Height of the triangle is 11.6 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<br \/>\n<\/strong>Height of triangle =31.4 mm<br \/>\nBase of triangle =?<br \/>\nArea of the triangle = 1256 mm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n1256 = \u00bd \u00d7 base \u00d7 31.4<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Base = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1256\\times&amp;space;2}{31.4}\" alt=\"\\frac{1256\\times 2}{31.4}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{2512}{31.4}\" alt=\"\\frac{2512}{31.4}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Base = 80 mm = 8 cm<br \/>\n\u2234 Base of the triangle is 80 mm or 8 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c)<br \/>\n<\/strong>Height of triangle =?<br \/>\nBase of triangle = 22 cm<br \/>\nArea of the triangle = 170.5 cm<sup>2<br \/>\n<\/sup>Then,<br \/>\nArea of triangle = \u00bd \u00d7 base \u00d7 height<br \/>\n170.5 = \u00bd \u00d7 22 \u00d7 height<br \/>\n170.5 = 1 \u00d7 11 \u00d7 height<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Height = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{170.5}{11}\" alt=\"\\frac{170.5}{11}\" align=\"absmiddle\" \/> \u00a0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Height = 15.5 cm<br \/>\n\u2234 Height of the triangle is 15.5 cm.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:<br \/>\n<\/strong><\/span><\/p>\n<figure id=\"attachment_2104\" aria-describedby=\"caption-attachment-2104\" style=\"width: 271px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2104\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q5.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"271\" height=\"153\" \/><figcaption id=\"caption-attachment-2104\" class=\"wp-caption-text\"><span style=\"color: #000000;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Fig 11.23<\/span><\/figcaption><\/figure>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a) The area of the parallelogram PQRS<br \/>\n(b) QN, if PS = 8 cm<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Given that,<br \/>\nSR = 12 cm,<br \/>\nQM = 7.6 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a)<\/strong> Area of the parallelogram = base \u00d7 height<br \/>\n= SR \u00d7 QM<br \/>\n= 12 cm \u00d7 7.6 cm<br \/>\n= 91.2 cm<sup>2<\/sup><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b)<\/strong> Area of the parallelogram = base \u00d7 height<br \/>\n91.2 = PS \u00d7 QN<br \/>\n91.2 = 8 \u00d7 QN<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">QN = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{91.2}{8}\" alt=\"\\frac{91.2}{8}\" align=\"absmiddle\" \/><br \/>\nQN = 11.4 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 11.24). If the area of the parallelogram is 1470 cm<sup>2<\/sup>, AB = 35 cm and AD = 49 cm, find the length of BM and DL.<br \/>\n<\/strong><\/span><\/p>\n<figure id=\"attachment_2105\" aria-describedby=\"caption-attachment-2105\" style=\"width: 299px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2105\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q6.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"299\" height=\"151\" \/><figcaption id=\"caption-attachment-2105\" class=\"wp-caption-text\"><span style=\"color: #000000;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Fig 11.24<\/span><\/figcaption><\/figure>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Given that,<br \/>\nArea of the parallelogram = 1470 cm<sup>2<br \/>\n<\/sup>AB = 35 cm<br \/>\nAD = 49 cm<br \/>\nThen,<br \/>\nArea of the parallelogram = base \u00d7 height<br \/>\n1470 = AB \u00d7 BM<br \/>\n1470 = 35 \u00d7 DL<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">DL = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1470}{35}\" alt=\"\\frac{1470}{35}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">DL = 42 cm<br \/>\nAnd,<br \/>\nArea of the parallelogram = base \u00d7 height<br \/>\n1470 = AD \u00d7 BM<br \/>\n1470 = 49 \u00d7 BM<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">BM = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1470}{49}\" alt=\"\\frac{1470}{49}\" align=\"absmiddle\" \/> <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">BM = 30 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. \u0394ABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of \u0394ABC. Also find the length of AD.<br \/>\n<\/strong><\/span><\/p>\n<figure id=\"attachment_2106\" aria-describedby=\"caption-attachment-2106\" style=\"width: 313px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2106\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q7.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"313\" height=\"156\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q7.png 313w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q7-300x150.png 300w\" sizes=\"auto, (max-width: 313px) 100vw, 313px\" \/><figcaption id=\"caption-attachment-2106\" class=\"wp-caption-text\"><span style=\"color: #000000;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Fig 11.25<\/span><\/figcaption><\/figure>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong>Given that,<br \/>\nAB = 5 cm, BC = 13 cm, AC = 12 cm<br \/>\nThen,<br \/>\nArea of the \u0394ABC = \u00bd \u00d7 base \u00d7 height<br \/>\n= \u00bd \u00d7 AB \u00d7 AC<br \/>\n= \u00bd \u00d7 5 cm \u00d7 12 cm<br \/>\n= 1 \u00d7 5 cm \u00d7 6 cm<br \/>\n= 30 cm<sup>2<br \/>\n<\/sup>Now,<br \/>\nArea of \u0394ABC = \u00bd \u00d7 base \u00d7 height<br \/>\n30 = \u00bd \u00d7 AD \u00d7 BC<br \/>\n30 = \u00bd \u00d7 AD \u00d7 13<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{32\\times&amp;space;2}{13}\" alt=\"\\frac{32\\times 2}{13}\" align=\"absmiddle\" \/>\u00a0 = AD<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">AD = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{60}{13}\" alt=\"\\frac{60}{13}\" align=\"absmiddle\" \/>\u00a0 = 4.6 cm<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8. \u0394ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of \u0394ABC. What will be the height from C to AB i.e., CE?<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2107 aligncenter\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q8.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"281\" height=\"246\" \/><\/strong><strong>Solution &#8211;<br \/>\n<\/strong>Given that,<br \/>\nAB = AC = 7.5 cm, BC = 9 cm, AD = 6cm<br \/>\nThen,<br \/>\nArea of \u0394ABC = \u00bd \u00d7 base \u00d7 height<br \/>\n= \u00bd \u00d7 BC \u00d7 AD<br \/>\n= \u00bd \u00d7 9 cm \u00d7 6 cm<br \/>\n= 1 \u00d7 9 cm \u00d7 3 cm<br \/>\n= 27 cm<sup>2<br \/>\n<\/sup>Now,<br \/>\nArea of \u0394ABC = \u00bd \u00d7 base \u00d7 height<br \/>\n27 = \u00bd \u00d7 AB \u00d7 CE<br \/>\n27 = \u00bd \u00d7 7.5 \u00d7 CE<br \/>\n<img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{27\\times&amp;space;2}{7.5}\" alt=\"\\frac{27\\times 2}{7.5}\" align=\"absmiddle\" \/> = CE<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">CE = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{54}{7.5}\" alt=\"\\frac{54}{7.5}\" align=\"absmiddle\" \/> <\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">CE = 7.2 cm<\/span><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Mathematics\u00a0 Chapter &#8211; 11 (Perimeter and Area) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 11 Perimeter and Area NCERT Solution Class 7 Maths [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[341,342,283,5],"class_list":["post-2093","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-11-perimeter-and-area-in-english","tag-ncert-solutions-class-7-maths-chapter-11-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 7 Mathematics\u00a0Chapter - 11 (Perimeter and Area)The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0Exercise - 11.2\u00a0\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2\" \/>\n<meta property=\"og:description\" content=\"NCERT Solutions Class 7 Mathematics\u00a0Chapter - 11 (Perimeter and Area)The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0Exercise - 11.2\u00a0\" \/>\n<meta property=\"og:url\" content=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/\" \/>\n<meta property=\"og:site_name\" content=\"TheExamPillar NCERT\" \/>\n<meta property=\"article:published_time\" content=\"2022-11-09T05:19:19+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png\" \/>\n<meta name=\"author\" content=\"Admin\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@exampillar\" \/>\n<meta name=\"twitter:site\" content=\"@exampillar\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Admin\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"10 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#article\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/\"},\"author\":{\"name\":\"Admin\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/#\\\/schema\\\/person\\\/521fbdbd2eb8621382a3096b5e3ecaf1\"},\"headline\":\"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2\",\"datePublished\":\"2022-11-09T05:19:19+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/\"},\"wordCount\":858,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/#\\\/schema\\\/person\\\/521fbdbd2eb8621382a3096b5e3ecaf1\"},\"image\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/10\\\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png\",\"keywords\":[\"NCERT Class 7 Maths Chapter 11 Perimeter and Area in English\",\"NCERT Solutions Class 7 Maths Chapter 11 in english\",\"NCERT Solutions Class 7 Maths in English\",\"NCERT Solutions in English\"],\"articleSection\":[\"Class 7 Maths\"],\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/\",\"url\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/\",\"name\":\"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 | TheExamPillar NCERT\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#primaryimage\"},\"image\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/10\\\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png\",\"datePublished\":\"2022-11-09T05:19:19+00:00\",\"description\":\"NCERT Solutions Class 7 Mathematics\u00a0Chapter - 11 (Perimeter and Area)The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0Exercise - 11.2\u00a0\",\"breadcrumb\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#primaryimage\",\"url\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/10\\\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png\",\"contentUrl\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/10\\\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png\",\"width\":876,\"height\":438,\"caption\":\"NCERT Class 7 Maths Solution\"},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\\\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/#website\",\"url\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/\",\"name\":\"TheExamPillar NCERT\",\"description\":\"\",\"publisher\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/#\\\/schema\\\/person\\\/521fbdbd2eb8621382a3096b5e3ecaf1\"},\"alternateName\":\"NCERT Solution\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"en-US\"},{\"@type\":[\"Person\",\"Organization\"],\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/#\\\/schema\\\/person\\\/521fbdbd2eb8621382a3096b5e3ecaf1\",\"name\":\"Admin\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/07\\\/cropped-ExamPillar-PNG.png\",\"url\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/07\\\/cropped-ExamPillar-PNG.png\",\"contentUrl\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/07\\\/cropped-ExamPillar-PNG.png\",\"width\":512,\"height\":512,\"caption\":\"Admin\"},\"logo\":{\"@id\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/wp-content\\\/uploads\\\/2022\\\/07\\\/cropped-ExamPillar-PNG.png\"},\"sameAs\":[\"https:\\\/\\\/theexampillar.com\\\/ncert\"],\"url\":\"https:\\\/\\\/theexampillar.com\\\/ncert\\\/author\\\/ncert_eng_vikram\\\/\"}]}<\/script>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 | TheExamPillar NCERT","description":"NCERT Solutions Class 7 Mathematics\u00a0Chapter - 11 (Perimeter and Area)The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0Exercise - 11.2\u00a0","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/","og_locale":"en_US","og_type":"article","og_title":"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2","og_description":"NCERT Solutions Class 7 Mathematics\u00a0Chapter - 11 (Perimeter and Area)The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0Exercise - 11.2\u00a0","og_url":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/","og_site_name":"TheExamPillar NCERT","article_published_time":"2022-11-09T05:19:19+00:00","og_image":[{"url":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png","type":"","width":"","height":""}],"author":"Admin","twitter_card":"summary_large_image","twitter_creator":"@exampillar","twitter_site":"@exampillar","twitter_misc":{"Written by":"Admin","Est. reading time":"10 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#article","isPartOf":{"@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/"},"author":{"name":"Admin","@id":"https:\/\/theexampillar.com\/ncert\/#\/schema\/person\/521fbdbd2eb8621382a3096b5e3ecaf1"},"headline":"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2","datePublished":"2022-11-09T05:19:19+00:00","mainEntityOfPage":{"@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/"},"wordCount":858,"commentCount":0,"publisher":{"@id":"https:\/\/theexampillar.com\/ncert\/#\/schema\/person\/521fbdbd2eb8621382a3096b5e3ecaf1"},"image":{"@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#primaryimage"},"thumbnailUrl":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png","keywords":["NCERT Class 7 Maths Chapter 11 Perimeter and Area in English","NCERT Solutions Class 7 Maths Chapter 11 in english","NCERT Solutions Class 7 Maths in English","NCERT Solutions in English"],"articleSection":["Class 7 Maths"],"inLanguage":"en-US","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/","url":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/","name":"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 | TheExamPillar NCERT","isPartOf":{"@id":"https:\/\/theexampillar.com\/ncert\/#website"},"primaryImageOfPage":{"@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#primaryimage"},"image":{"@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#primaryimage"},"thumbnailUrl":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png","datePublished":"2022-11-09T05:19:19+00:00","description":"NCERT Solutions Class 7 Mathematics\u00a0Chapter - 11 (Perimeter and Area)The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 11 Perimeter and Area Exercise 11.2 has been provided here to help the students in solving the questions from this exercise.\u00a0Exercise - 11.2\u00a0","breadcrumb":{"@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#primaryimage","url":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png","contentUrl":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-11.2-Q1.png","width":876,"height":438,"caption":"NCERT Class 7 Maths Solution"},{"@type":"BreadcrumbList","@id":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-2\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/theexampillar.com\/ncert\/"},{"@type":"ListItem","position":2,"name":"NCERT Solutions Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2"}]},{"@type":"WebSite","@id":"https:\/\/theexampillar.com\/ncert\/#website","url":"https:\/\/theexampillar.com\/ncert\/","name":"TheExamPillar NCERT","description":"","publisher":{"@id":"https:\/\/theexampillar.com\/ncert\/#\/schema\/person\/521fbdbd2eb8621382a3096b5e3ecaf1"},"alternateName":"NCERT Solution","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/theexampillar.com\/ncert\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"en-US"},{"@type":["Person","Organization"],"@id":"https:\/\/theexampillar.com\/ncert\/#\/schema\/person\/521fbdbd2eb8621382a3096b5e3ecaf1","name":"Admin","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/cropped-ExamPillar-PNG.png","url":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/cropped-ExamPillar-PNG.png","contentUrl":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/cropped-ExamPillar-PNG.png","width":512,"height":512,"caption":"Admin"},"logo":{"@id":"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/cropped-ExamPillar-PNG.png"},"sameAs":["https:\/\/theexampillar.com\/ncert"],"url":"https:\/\/theexampillar.com\/ncert\/author\/ncert_eng_vikram\/"}]}},"_links":{"self":[{"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/posts\/2093","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/comments?post=2093"}],"version-history":[{"count":3,"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/posts\/2093\/revisions"}],"predecessor-version":[{"id":2508,"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/posts\/2093\/revisions\/2508"}],"wp:attachment":[{"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/media?parent=2093"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/categories?post=2093"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/theexampillar.com\/ncert\/wp-json\/wp\/v2\/tags?post=2093"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}