{"id":2061,"date":"2022-11-08T07:38:15","date_gmt":"2022-11-08T07:38:15","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=2061"},"modified":"2022-11-08T07:41:30","modified_gmt":"2022-11-08T07:41:30","slug":"ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-4","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-4\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.4"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 10 (Practical Geometry)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 10 Practical Geometry\u00a0 <\/strong>Exercise 10.4 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Chapter : 10 Practical Geometry<\/strong><\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-1\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 10.1<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 10.2<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 10.3<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-5\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 10.5<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 10.4\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Construct \u0394ABC, given m \u2220A =60<sup>o<\/sup>, m \u2220B = 30<sup>o<\/sup>\u00a0and AB = 5.8 cm.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2082\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-10.4-Q1.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"269\" height=\"162\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Steps of construction:<br \/>\n1. Draw a line segment AB = 5.8 cm.<br \/>\n2. Draw \u2220A = 60\u00b0 and \u2220B = 30\u00b0 to meet each other at C.<br \/>\nThen, \u0394ABC is the required triangle.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Construct \u0394PQR if PQ = 5 cm, m\u2220PQR = 105<sup>o<\/sup>\u00a0and m\u2220QRP = 40<sup>o<\/sup>. <\/strong><strong>(Hint: Recall angle-sum property of a triangle).<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\">We know that the sum of the angles of a triangle is 180<sup>o<\/sup>.<br \/>\n\u2234 \u2220PQR + \u2220QRP + \u2220RPQ = 180<sup>o<br \/>\n<\/sup>\u21d2 40<sup>o<\/sup>+ 105<sup>o<\/sup>+ \u2220RPQ = 180<sup>o<br \/>\n<\/sup>\u21d2 145<sup>o<\/sup>\u00a0+ \u2220RPQ = 180<sup>o<br \/>\n<\/sup>\u21d2 \u2220RPQ = 180<sup>o<\/sup>\u2013 145<sup>0<br \/>\n<\/sup>\u21d2 \u2220RPQ = 35<sup>o<br \/>\n<\/sup>Hence, the measures of \u2220RPQ is 35<sup>o<\/sup>.<\/span><\/p>\n<p><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2083\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-10.4-Q2.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"237\" height=\"140\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\">Steps of construction:<br \/>\n1. Draw a line segment PQ = 5 cm.<br \/>\n2. Draw \u2220QPR = 35\u00b0 and \u2220PQR = 40\u00b0 to meet each other at R.<br \/>\nThen, \u0394PQR is the required triangle.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Examine whether you can construct \u0394DEF such that EF = 7.2 cm, m\u2220E = 110\u00b0 and <\/strong><strong>m\u2220F = 80\u00b0. Justify your answer.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;\u00a0 <\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">To construct \u2206DEF with the given measurement, is not possible.<br \/>\n\u2235 m\u2220E + m\u2220F = 110\u00b0 + 80\u00b0<br \/>\n= 190\u00b0 &gt; 180\u00b0 [Sum of the angles of a triangle = 180\u00b0]<br \/>\n\u2234 \u0394DEF is not possible to construct.<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\">\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Mathematics\u00a0 Chapter &#8211; 10 (Practical Geometry) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 10 Practical Geometry\u00a0 Exercise 10.4 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 10 Practical Geometry NCERT Solution Class 7 Maths Exercise &#8211; 10.1 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[338,339,283,5],"class_list":["post-2061","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-10-practical-geometry-in-english","tag-ncert-solutions-class-7-maths-chapter-10-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - 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