{"id":2059,"date":"2022-11-08T07:37:53","date_gmt":"2022-11-08T07:37:53","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=2059"},"modified":"2022-11-08T07:41:12","modified_gmt":"2022-11-08T07:41:12","slug":"ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-2","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-2\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 10 Practical Geometry Ex 10.2"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 10 (Practical Geometry)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 10 Practical Geometry\u00a0 <\/strong>Exercise 10.2 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Chapter : 10 Practical Geometry<\/strong><\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-1\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 10.1<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 10.3<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 10.4<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-10-practical-geometry-ex-10-5\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 10.5<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 10.2\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Construct \u0394XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2072\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-10.2-Q1.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"146\" height=\"174\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Steps of construction:<br \/>\n1. Draw a line segment XY = 4.5 cm.<br \/>\n2. With X as a center and radius 6 cm, draw an arc.<br \/>\n3. With Y as a center and radius 5 cm, draw another arc, cutting the previous arc at Z.<br \/>\n4. Join YZ and XZ.<br \/>\nThen, \u0394XYZ is the required triangle.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Construct an equilateral triangle of side 5.5 cm.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2073\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-10.2-Q2.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"164\" height=\"158\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Steps of construction:<br \/>\n1. Draw a line segment BC = 5.5 cm.<br \/>\n2. With B as a center and radius 5.5 cm, draw an arc.<br \/>\n3. With C as a center and radius 5.5 cm, draw another arc, cutting the previous arc at A.<br \/>\n4. Join BA and CA.<br \/>\nThen, \u0394ABC is the required equilateral triangle.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Draw \u0394PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2074\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-10.2-Q3.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"159\" height=\"176\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">Steps of construction:<br \/>\n1. Draw a line segment QR = 3.5 cm.<br \/>\n2. With Q as a center and radius 4 cm, draw an arc.<br \/>\n3. With R as a center and radius 4 cm, draw another arc, cutting the previous arc at P.<br \/>\n4. Join PQ and PR.<br \/>\nThen, \u0394PQR is the required isosceles triangle.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Construct \u0394ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure \u2220B.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><\/span><\/p>\n<p><span style=\"color: #000000;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2075\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/10\/NCERT-Solutions-Class-7-Maths-Ex-10.2-Q4.png\" alt=\"NCERT Class 7 Maths Solution\" width=\"244\" height=\"126\" \/><\/span><\/p>\n<p><span style=\"color: #000000;\">Steps of construction:<br \/>\n1. Draw a line segment BC = 6 cm.<br \/>\n2. With B as a center and radius 2.5 cm, draw an arc.<br \/>\n3. With C as a center and radius 6.5 cm, draw another arc, cutting the previous arc at A.<br \/>\n4. Join AB and AC.<br \/>\nThen, \u0394ABC is the required triangle.<br \/>\n5. When we measure the angle B of triangle by protractor, then angle is equal to \u2220B = 90<sup>o<\/sup><\/span><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Mathematics\u00a0 Chapter &#8211; 10 (Practical Geometry) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 10 Practical Geometry\u00a0 Exercise 10.2 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 10 Practical Geometry NCERT Solution Class 7 Maths Exercise &#8211; 10.1 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[338,339,283,5],"class_list":["post-2059","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-10-practical-geometry-in-english","tag-ncert-solutions-class-7-maths-chapter-10-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - 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