{"id":2016,"date":"2022-11-07T04:10:52","date_gmt":"2022-11-07T04:10:52","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=2016"},"modified":"2022-11-07T04:10:52","modified_gmt":"2022-11-07T04:10:52","slug":"ncert-solutions-class-7-maths-chapter-8-comparing-quantities-ex-8-1","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-8-comparing-quantities-ex-8-1\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 8 Comparing Quantities Ex 8.1"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 8 (Comparing Quantities)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 8 Comparing Quantities <\/strong>Exercise 8.1 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Chapter : 8 Comparing Quantities<\/strong><\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-8-comparing-quantities-ex-8-2\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 8.2<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-8-comparing-quantities-ex-8-3\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 8.3<\/span><\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 8.1\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Find the ratio of:<br \/>\n<\/strong><\/span><strong>(a) \u20b9 5 to 50 paise<\/strong><br \/>\n<strong>(b) 15 kg to 210 g<\/strong><br \/>\n<strong>(c) 9 m to 27 cm<\/strong><br \/>\n<strong>(d) 30 days to 36 hours<\/strong><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(a) \u20b9 5 to 50 paise<\/strong><br \/>\nWe know that,<br \/>\n<\/span><span style=\"color: #000000;\">\u20b9 1 = 100 paise<br \/>\n<\/span><span style=\"color: #000000;\">Then,<br \/>\n<\/span><span style=\"color: #000000;\">\u20b9 5 = 5 \u00d7 100 = 500 paise<br \/>\n<\/span><span style=\"color: #000000;\">Now we have to find the ratio,<br \/>\n<\/span><span style=\"color: #000000;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{500}{50}\" alt=\"\\frac{500}{50}\" align=\"absmiddle\" \/> <\/span><span style=\"color: #000000;\">= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{10}{1}\" alt=\"\\frac{10}{1}\" align=\"absmiddle\" \/><br \/>\n<\/span><span style=\"color: #000000;\">So, the required ratio is 10 : 1.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) 15 kg to 210 g<br \/>\n<\/strong><\/span><span style=\"color: #000000;\">We know that,<br \/>\n<\/span><span style=\"color: #000000;\">1 kg = 1000 g<br \/>\n<\/span><span style=\"color: #000000;\">Then,<br \/>\n<\/span><span style=\"color: #000000;\">15 kg = 15 \u00d7 1000 = 15000 g<br \/>\n<\/span><span style=\"color: #000000;\">Now we have to find the ratio,<br \/>\n<\/span><span style=\"color: #000000;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{15000}{210}\" alt=\"\\frac{15000}{210}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1500}{21}\" alt=\"\\frac{1500}{21}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{500}{7}\" alt=\"\\frac{500}{7}\" align=\"absmiddle\" \/>\u00a0 &#8212;&#8212;- [\u2235 divide both by 3]<br \/>\n<\/span><span style=\"color: #000000;\">So, the required ratio is 500 : 7.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c) 9 m to 27 cm<br \/>\n<\/strong><\/span><span style=\"color: #000000;\">We know that,<br \/>\n<\/span><span style=\"color: #000000;\">1 m = 100 cm<br \/>\n<\/span><span style=\"color: #000000;\">Then,<br \/>\n\u21d2 <\/span><span style=\"color: #000000;\">9 m = 9 \u00d7 100 = 900 cm<br \/>\n<\/span><span style=\"color: #000000;\">Now we have to find the ratio,<br \/>\n<\/span><span style=\"color: #000000;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{900}{27}\" alt=\"\\frac{900}{27}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{100}{3}\" alt=\"\\frac{100}{3}\" align=\"absmiddle\" \/> <\/span><span style=\"color: #000000;\"> &#8212;&#8212;&#8211;\u00a0 [\u2235 divide both by 9]<br \/>\n<\/span><span style=\"color: #000000;\">So, the required ratio is 100 : 3.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d) 30 days to 36 hours<br \/>\n<\/strong><\/span><span style=\"color: #000000;\">We know that,<br \/>\n<\/span><span style=\"color: #000000;\">1 day = 24 hours<br \/>\n<\/span><span style=\"color: #000000;\">Then,<br \/>\n<\/span><span style=\"color: #000000;\">30 days = 30 \u00d7 24 = 720 hours<br \/>\n<\/span><span style=\"color: #000000;\">Now we have to find the ratio,<br \/>\n<\/span><span style=\"color: #000000;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{720}{36}\" alt=\"\\frac{720}{36}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{20}{1}\" alt=\"\\frac{20}{1}\" align=\"absmiddle\" \/>\u00a0 \u00a0 <\/span><span style=\"color: #000000;\">&#8212;&#8212;&#8212;&#8212; [\u2235 divide both by 36]<br \/>\n<\/span><span style=\"color: #000000;\">So, the required ratio is 20 : 1.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><\/span><span style=\"color: #000000;\">Using Unitary Method, we have<br \/>\n6 students require 3 computers<br \/>\n\u2234 1 student will require = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{6}\" alt=\"\\frac{3}{6}\" align=\"absmiddle\" \/> computers<br \/>\n\u2234 24 students will require = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{6}\" alt=\"\\frac{3}{6}\" align=\"absmiddle\" \/> \u00a0x 24 computers<br \/>\n\u21d2 3 \u00d7 4 computers<br \/>\n\u21d2 12 computers<br \/>\nHence the number of computers required = 12.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3. Population of Rajasthan = 570 lakhs and population of UP = 1660 lakhs. <\/strong><\/span><span style=\"color: #000000;\"><strong>Area of Rajasthan = 3 lakh km<sup>2<\/sup>\u00a0and area of UP = 2 lakh km<sup>2<\/sup>.<br \/>\n<\/strong><\/span><span style=\"color: #000000;\"><strong>(i) How many people are there per km<sup>2<\/sup>\u00a0in both these States?<br \/>\n<\/strong><\/span><span style=\"color: #000000;\"><strong>(ii) Which State is less populated?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><\/span><span style=\"color: #000000;\"><strong>(i) How many people are there per km<sup>2<\/sup>\u00a0in both these States?<br \/>\n<\/strong><\/span><span style=\"color: #000000;\">Population of Rajasthan = 570 lakh<br \/>\n<\/span><span style=\"color: #000000;\">Area of Rajasthan = 3 lakh Km<sup>2<br \/>\n<\/sup><\/span><span style=\"color: #000000;\">Then, population of Rajasthan in 1 km<sup>2<\/sup> area = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{570}{3}\" alt=\"\\frac{570}{3}\" align=\"absmiddle\" \/> <\/span><span style=\"color: #000000;\">= 190 people per km<sup>2<br \/>\n<\/sup><\/span><span style=\"color: #000000;\">Population of UP = 1660 Lakh<br \/>\n<\/span><span style=\"color: #000000;\">Area of UP = 2 Lakh km<sup>2<br \/>\n<\/sup><\/span><span style=\"color: #000000;\">Then, population of UP in 1 lakh km<sup>2<\/sup> area = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1660}{2}\" alt=\"\\frac{1660}{2}\" align=\"absmiddle\" \/> = <\/span><span style=\"color: #000000;\">830 people per km<\/span><sup style=\"color: #000000;\">2<\/sup><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) Which State is less populated?<br \/>\n<\/strong>Rajasthan is less populated state.<\/span><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Mathematics\u00a0 Chapter &#8211; 8 (Comparing Quantities) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 8 Comparing Quantities Exercise 8.1 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 8 Comparing Quantities NCERT Solution Class 7 Maths Exercise &#8211; 8.2 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[300,301,283,5],"class_list":["post-2016","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-8-comparing-quantities-in-english","tag-ncert-solutions-class-7-maths-chapter-8-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - 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