{"id":1872,"date":"2022-11-03T07:29:36","date_gmt":"2022-11-03T07:29:36","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=1872"},"modified":"2022-11-03T07:29:36","modified_gmt":"2022-11-03T07:29:36","slug":"ncert-solutions-class-7-maths-chapter-4-simple-equations-ex-4-4","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-4-simple-equations-ex-4-4\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 4 Simple Equations Ex 4.4"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Mathematics\u00a0<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 4 (Simple Equations)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 4 Simple Equations <\/strong>Exercise 4.4 has been provided here to help the students in solving the questions from this exercise.\u00a0<\/span><\/p>\n<p><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Chapter : 4 Simple Equations<\/strong><\/span><\/p>\n<ul>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-4-simple-equations-ex-4-1\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 4.1<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-4-simple-equations-ex-4-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 4.2<\/a><\/span><\/li>\n<li><span style=\"color: #0000ff; font-family: georgia, palatino, serif;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-4-simple-equations-ex-4-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 7 Maths Exercise &#8211; 4.3<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 4.4\u00a0<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>1. Set up equations and solve them to find the unknown numbers in the following cases:<br \/>\n<\/strong><strong>(a) Add 4 to eight times a number; you get 60.<br \/>\n(b) One-fifth of a number minus 4 gives 3.<br \/>\n(c) If I take three-fourths of a number and add 3 to it, I get 21.<br \/>\n(d) When I subtracted 11 from twice a number, the result was 15.<br \/>\n(e) Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.<br \/>\n(f) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.<br \/>\n(g) Anwar thinks of a number. If he takes away 7 from <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mathbf{\\frac{5}{2}}\" alt=\"\\mathbf{\\frac{5}{2}}\" align=\"absmiddle\" \/>\u00a0of the numbers, the result is 23.<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(a) Add 4 to eight times a number; you get 60.<\/strong><br \/>\nLet us assume the required number be x<br \/>\nEight times a number = 8x<br \/>\nAccording to the Question<br \/>\n\u21d2 8x + 4 = 60<br \/>\nBy transposing 4 from LHS to RHS it becomes \u2013 4<br \/>\n\u21d2 8x = 60 \u2013 4<br \/>\n\u21d2 8x = 56<br \/>\nDivide both side by 8,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{8x}{8}\" alt=\"\\frac{8x}{8}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{56}{8}\" alt=\"\\frac{56}{8}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 7<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b) One-fifth of a number minus 4 gives 3.<br \/>\n<\/strong>Let us assume the required number be x<br \/>\nOne-fifth of a number = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{5}\" alt=\"\\frac{1}{5}\" align=\"absmiddle\" \/> x = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{x}{5}\" alt=\"\\frac{x}{5}\" align=\"absmiddle\" \/><br \/>\nAccording to the Question<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{x}{5}\" alt=\"\\frac{x}{5}\" align=\"absmiddle\" \/> \u2013 4 = 3<br \/>\nBy transposing \u2013 4 from LHS to RHS it becomes 4<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{x}{5}\" alt=\"\\frac{x}{5}\" align=\"absmiddle\" \/> = 3 + 4<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{x}{5}\" alt=\"\\frac{x}{5}\" align=\"absmiddle\" \/> = 7<br \/>\nMultiply both side by 5,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{x}{5}\" alt=\"\\frac{x}{5}\" align=\"absmiddle\" \/> \u00d7 5 = 7 \u00d7 5<br \/>\n\u21d2 x = 35<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c) If I take three-fourths of a number and add 3 to it, I get 21.<br \/>\n<\/strong>Let us assume the required number be x<br \/>\nThree-fourths of a number = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{4}\" alt=\"\\frac{3}{4}\" align=\"absmiddle\" \/> x<br \/>\nAccording to the Question<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{4}\" alt=\"\\frac{3}{4}\" align=\"absmiddle\" \/> x + 3 = 21<br \/>\nBy transposing 3 from LHS to RHS it becomes \u2013 3<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{4}\" alt=\"\\frac{3}{4}\" align=\"absmiddle\" \/> x = 21 \u2013 3<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3}{4}\" alt=\"\\frac{3}{4}\" align=\"absmiddle\" \/> x = 18<br \/>\nMultiply both side by 4,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3x}{4}\" alt=\"\\frac{3x}{4}\" align=\"absmiddle\" \/>\u00a0\u00d7 4 = 18 \u00d7 4<br \/>\n\u21d2 3x = 72<br \/>\nDivide both side by 3,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3x}{3}\" alt=\"\\frac{3x}{3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{72}{3}\" alt=\"\\frac{72}{3}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 24<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(d) When I subtracted 11 from twice a number, the result was 15.<br \/>\n<\/strong>Let us assume the required number be x<br \/>\nTwice a number = 2x<br \/>\nAccording to the Question<br \/>\n\u21d2 2x \u201311 = 15<br \/>\nBy transposing -11 from LHS to RHS it becomes 11<br \/>\n\u21d2 2x = 15 + 11<br \/>\n\u21d2 2x = 26<br \/>\nDivide both side by 2,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{2x}{2}\" alt=\"\\frac{2x}{2}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{26}{2}\" alt=\"\\frac{26}{2}\" align=\"absmiddle\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u21d2 x = 13<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(e) Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.<br \/>\n<\/strong>Let us assume the required number be x<br \/>\nThrice the number = 3x<br \/>\nAccording to the Question<br \/>\n\u21d2 50 \u2013 3x = 8<br \/>\nBy transposing 50 from LHS to RHS it becomes \u2013 50<br \/>\n\u21d2 \u2013 3x = 8 \u2013 50<br \/>\n\u21d2 -3x = \u2013 42<br \/>\nDivide both side by -3,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-3x}{-3}\" alt=\"\\frac{-3x}{-3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{-42}{-3}\" alt=\"\\frac{-42}{-3}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 14<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(f) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.<br \/>\n<\/strong>Let us assume the required number be x<br \/>\nAccording to the Question<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(x+19)}{5}\" alt=\"\\frac{(x+19)}{5}\" align=\"absmiddle\" \/> = 8<br \/>\nMultiply both side by 5,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{(x+19)}{5}\" alt=\"\\frac{(x+19)}{5}\" align=\"absmiddle\" \/>\u00a0\u00d7 5 = 8 \u00d7 5<br \/>\n\u21d2 x + 19 = 40<br \/>\nBy transposing 19 from LHS to RHS it becomes \u2013 19<br \/>\n\u21d2 x = 40 \u2013 19<br \/>\n\u21d2 x = 21<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(g) Anwar thinks of a number. If he takes away 7 from <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\mathbf{\\frac{5}{2}}\" alt=\"\\mathbf{\\frac{5}{2}}\" align=\"absmiddle\" \/> of the number, the result is 23.<br \/>\n<\/strong>Let us assume the required number be x<br \/>\n<img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{2}\" alt=\"\\frac{5}{2}\" align=\"absmiddle\" \/> of the number = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{2}\" alt=\"\\frac{5}{2}\" align=\"absmiddle\" \/>x<br \/>\nAccording to the Question<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{2}\" alt=\"\\frac{5}{2}\" align=\"absmiddle\" \/> x \u2013 7 = 23<br \/>\nBy transposing -7 from LHS to RHS it becomes 7<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{2}\" alt=\"\\frac{5}{2}\" align=\"absmiddle\" \/>\u00a0x = 23 + 7<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5}{2}\" alt=\"\\frac{5}{2}\" align=\"absmiddle\" \/> x = 30<br \/>\nMultiply both side by 2,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5x}{2}\" alt=\"\\frac{5x}{2}\" align=\"absmiddle\" \/>\u00a0\u00d7 2 = 30 \u00d7 2<br \/>\n\u21d2 5x = 60<br \/>\nDivide both the side by 5<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5x}{5}\" alt=\"\\frac{5x}{5}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{60}{5}\" alt=\"\\frac{60}{5}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 12<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>2. Solve the following:<br \/>\n<\/strong><strong>(a) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. What is the lowest score?<br \/>\n<\/strong><strong>(b) In an isosceles triangle, the base angles are equal. The vertex angle is 40\u00b0. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180\u00b0).<br \/>\n(c) Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score?<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solution &#8211;<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(a) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. What is the lowest score?<\/strong><br \/>\nLet us assume the lowest score be x<br \/>\nAccording to the Question<br \/>\nThe highest score is = 87<br \/>\n\u21d2 2x + 7 = Highest score<br \/>\n\u21d2 2x + 7 = 87<br \/>\nBy transposing 7 from LHS to RHS it becomes -7<br \/>\n\u21d2 2x = 87 \u2013 7<br \/>\n\u21d2 2x = 80<br \/>\nDivide both the side by 2<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{2x}{2}\" alt=\"\\frac{2x}{2}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{80}{2}\" alt=\"\\frac{80}{2}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 40<br \/>\nHence, the lowest score is 40<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(b) In an isosceles triangle, the base angles are equal. The vertex angle is 40\u00b0. <\/strong><strong>What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180\u00b0).<br \/>\n<\/strong>Let each base angle be x degrees.<br \/>\nAccording to the Question<br \/>\nWe know that, the sum of angles of a triangle is 180<sup>o<br \/>\n<\/sup>\u21d2 x + x + 40<sup>o<\/sup>\u00a0= 180<sup>o<br \/>\n<\/sup>\u21d2 2x + 40 = 180<sup>o<br \/>\n<\/sup>By transposing 40 from LHS to RHS it becomes -40<br \/>\n\u21d2 2x = 180 \u2013 40<br \/>\n\u21d2 2x = 140<br \/>\nDivide both the side by 2<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{2x}{2}\" alt=\"\\frac{2x}{2}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{140}{2}\" alt=\"\\frac{140}{2}\" align=\"absmiddle\" \/><br \/>\n\u21d2 b = 70<sup>o<br \/>\n<\/sup>Hence, 70<sup>o<\/sup>\u00a0is the base angle of an isosceles triangle.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(c) Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score?<br \/>\n<\/strong>Let us assume Rahul\u2019s score be x<br \/>\nAccording to the Question<br \/>\nSachin scored = 2x<br \/>\n\u21d2 Rahul\u2019s score + Sachin\u2019s score = 200 \u2013 2<br \/>\n\u21d2 x + 2x = 198<br \/>\n\u21d2 3x = 198<br \/>\nDivide both the side by 3,<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3x}{3}\" alt=\"\\frac{3x}{3}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{198}{3}\" alt=\"\\frac{198}{3}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 66<br \/>\nSo, Rahul\u2019s score (x) = 66<br \/>\nAnd Sachin\u2019s score is (2x) = 2 \u00d7 66 = 132<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>3. Solve the following:<br \/>\n<\/strong><strong>(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. <\/strong><strong>Irfan has 37 marbles. How many marbles does Parmit have?<br \/>\n(ii) Laxmi\u2019s father is 49 years old. He is 4 years older than three times Laxmi\u2019s age. What is Laxmi\u2019s age?<br \/>\n(iii) People of Sundargram planted trees in a village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77?<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solution &#8211;<br \/>\n(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. How many marbles does Parmit have?<br \/>\n<\/strong>Let us assume number of Parmit\u2019s marbles = x<br \/>\nAccording to the Question<br \/>\nIrfan has 7 marbles more than five times the marbles Parmit has<br \/>\n\u21d2 5 \u00d7 Number of Parmit\u2019s marbles + 7 = Total number of marbles Irfan having<br \/>\n\u21d2 (5 \u00d7 x) + 7 = 37<br \/>\n\u21d2 5x + 7 = 37<br \/>\nBy transposing 7 from LHS to RHS it becomes -7<br \/>\n\u21d2 5x = 37 \u2013 7<br \/>\n\u21d2 5x = 30<br \/>\nDivide both the side by 5<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{5x}{5}\" alt=\"\\frac{5x}{5}\" align=\"absmiddle\" \/>\u00a0= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{30}{5}\" alt=\"\\frac{30}{5}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 6<br \/>\nSo, Permit has 6 marbles<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(ii) Laxmi\u2019s father is 49 years old. He is 4 years older than three times Laxmi\u2019s age. <\/strong><strong>What is Laxmi\u2019s age?<br \/>\n<\/strong>Let Laxmi\u2019s age to be = x years old<br \/>\nAccording to the Question<br \/>\nLakshmi\u2019s father is 4 years older than three times of her age<br \/>\n\u21d2 3 \u00d7 Laxmi\u2019s age + 4 = Age of Lakshmi\u2019s father<br \/>\n\u21d2 (3 \u00d7 x) + 4 = 49<br \/>\n\u21d2 3x + 4 = 49<br \/>\nBy transposing 4 from LHS to RHS it becomes -4<br \/>\n\u21d2 3x = 49 \u2013 4<br \/>\n\u21d2 3x = 45<br \/>\nDivide both the side by 3<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3x}{3}\" alt=\"\\frac{3x}{3}\" align=\"absmiddle\" \/>\u00a0= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{45}{3}\" alt=\"\\frac{45}{3}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 15<br \/>\nSo, Lakshmi\u2019s age is 15 years.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>(iii) People of Sundargram planted trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77?<br \/>\n<\/strong>Let the number of fruit tress be x.<br \/>\nAccording to the Question<br \/>\n3 \u00d7 number of fruit trees + 2 = number of non-fruit trees<br \/>\n\u21d2 3x + 2 = 77<br \/>\nBy transposing 2 from LHS to RHS it becomes -2<br \/>\n\u21d2 3x = 77 \u2013 2<br \/>\n\u21d2 3x = 75<br \/>\nDivide both the side by 3<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{3x}{3}\" alt=\"\\frac{3x}{3}\" align=\"absmiddle\" \/>= <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{75}{3}\" alt=\"\\frac{75}{3}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 25<br \/>\nSo, number of fruit tree was 25.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>4. Solve the following riddle:<br \/>\n<\/strong><strong>I am a number,<br \/>\n<\/strong><strong>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Tell my identity!<br \/>\n<\/strong><strong>Take me seven times over<br \/>\n<\/strong><strong>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 And add a fifty!<br \/>\n<\/strong><strong>To reach a triple century<br \/>\n<\/strong><strong>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 You still need forty!<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\"><strong>Solution &#8211;<br \/>\n<\/strong>Let us assume the number be x.<br \/>\nTake me seven times over and add a fifty = 7x + 50<br \/>\nTo reach a triple century you still need forty = (7x + 50) + 40 = 300<br \/>\n\u21d2 7x + 50 + 40 = 300<br \/>\n\u21d2 7x + 90 = 300<br \/>\nBy transposing 90 from LHS to RHS it becomes -90<br \/>\n\u21d2 7x = 300 \u2013 90<br \/>\n\u21d2 7x = 210<br \/>\nDivide both side by 7<br \/>\n\u21d2 <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{7x}{7}\" alt=\"\\frac{7x}{7}\" align=\"absmiddle\" \/> = <img decoding=\"async\" src=\"https:\/\/latex.codecogs.com\/gif.latex?\\frac{210}{7}\" alt=\"\\frac{210}{7}\" align=\"absmiddle\" \/><br \/>\n\u21d2 x = 30<br \/>\nHence the number is 30.<\/span><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Mathematics\u00a0 Chapter &#8211; 4 (Simple Equations) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 4 Simple Equations Exercise 4.4 has been provided here to help the students in solving the questions from this exercise.\u00a0 Chapter : 4 Simple Equations NCERT Solution Class 7 Maths Exercise &#8211; 4.1 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[288,289,283,5],"class_list":["post-1872","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-4-simple-equations-in-english","tag-ncert-solutions-class-7-maths-chapter-4-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.5) - 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