{"id":175,"date":"2022-08-09T15:39:56","date_gmt":"2022-08-09T15:39:56","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=175"},"modified":"2024-02-21T06:04:15","modified_gmt":"2024-02-21T06:04:15","slug":"ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-1","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-1\/","title":{"rendered":"NCERT Solutions Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.1"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">NCERT Solutions Class 6 Maths<\/span><\/strong><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Chapter &#8211; 5 (Understanding Elementary Shapes)<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 6 Mathematics <strong>Chapter &#8211; 5 Understanding Elementary Shapes <\/strong>Exercise 5.1 has been provided here to help the students in solving the questions from this exercise.<\/span><\/p>\n<h4 id=\"chapter-5\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span id=\"Chapter_5_Understanding_Elementary_Shapes\" style=\"color: #000000;\">Chapter 5: Understanding Elementary Shapes<\/span><\/strong><\/span><\/h4>\n<ul>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-2\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.2<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-3\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.3<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-4\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.4<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-5\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.5<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-6\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.6<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-7\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.7<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-8\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.8<\/a><\/span><\/li>\n<li><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths-chapter-5-understanding-elementary-shapes-ex-5-9\" target=\"_blank\" rel=\"noopener\">NCERT Solution Class 6 Maths Exercise &#8211; 5.9<\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Exercise &#8211; 5.1<\/span><\/strong><\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>1. What is the disadvantage in comparing line segments by mere observation?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">By mere observation we can\u2019t compare the line segments with slight difference in their length. We can\u2019t say which line segment is of greater length. Hence, the chances of errors due to improper viewing are more.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>2. Why is it better to use a divider than a ruler, while measuring the length of a line segment?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">While using a ruler, chances of error occur due to thickness of the ruler and angular viewing. Hence, using divider accurate measurement is possible.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>3. Draw any line segment, say <img decoding=\"async\" id=\"output\" src=\"https:\/\/latex.codecogs.com\/svg.image?\\overline{AB}\" \/>. Take any point C lying in between A and B. Measure the lengths of AB, BC and AC. Is AB = AC + CB?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">Since given that point C lie in between A and B. Hence, all points are lying on same line segment <\/span><span style=\"color: #000000;\"><img decoding=\"async\" id=\"output\" src=\"https:\/\/latex.codecogs.com\/svg.image?\\overline{AB}\" \/>. Therefore, for every situation in which point C is lying in between A and B we may say that<br \/>\n<\/span><span style=\"color: #000000;\">AB = AC + CB<br \/>\n<\/span><strong><span style=\"color: #000000;\">For example:<br \/>\n<\/span><\/strong><span style=\"color: #000000;\">AB is a line segment of length 7 cm and C is a point between A and B such that AC = 3 cm and CB = 4 cm.<br \/>\n<\/span><span style=\"color: #000000;\">Hence, AC + CB = 7 cm<br \/>\n<\/span><span style=\"color: #000000;\">Since, AB = 7 cm<br \/>\n<\/span><span style=\"color: #000000;\">\u2234 AB = AC + CB is verified.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>4. If A, B, C are three points on a line such that AB = 5 cm, BC = 3 cm and AC = 8 cm, which one of them lies between the other two?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">Given<br \/>\nAB = 5 cm<br \/>\n<\/span><span style=\"color: #000000;\">BC = 3 cm<br \/>\n<\/span><span style=\"color: #000000;\">AC = 8 cm<br \/>\n<\/span><span style=\"color: #000000;\">Now, it is clear that AC = AB + BC<br \/>\n<\/span><span style=\"color: #000000;\">Hence, point B lies between A and C.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>5. Verify, whether D is the mid point of <img decoding=\"async\" id=\"output\" src=\"https:\/\/latex.codecogs.com\/svg.image?\\mathbf{\\overline{AG}}\" \/>.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-194\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q5-300x61.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"61\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q5-300x61.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q5-480x97.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q5.jpg 645w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">Since, it is clear from the figure that AD = DG = 3 units. Hence, D is the midpoint of<strong> <img decoding=\"async\" id=\"output\" src=\"https:\/\/latex.codecogs.com\/svg.image?\\overline{AG}\" \/><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>6. If B is the mid point of <img decoding=\"async\" id=\"output\" src=\"https:\/\/latex.codecogs.com\/svg.image?\\mathbf{\\overline{AC}}\" \/> and C is the mid point of <img decoding=\"async\" id=\"output\" src=\"https:\/\/latex.codecogs.com\/svg.image?\\mathbf{\\overline{BD}}\" \/>, where A, B, C, D lie on a straight line, say why AB = CD?<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-195\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q6-300x36.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"36\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q6-300x36.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q6-480x57.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q6.jpg 690w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><br \/>\n<span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">Given<br \/>\n<\/span><span style=\"color: #000000;\">B is the midpoint of AC. Hence, AB = BC\u00a0 \u00a0 &#8212;&#8212;&#8212; (1)<br \/>\n<\/span><span style=\"color: #000000;\">C is the midpoint of BD. Hence, BC = CD\u00a0 \u00a0&#8212;&#8212;&#8212; (2)<br \/>\n<\/span><span style=\"color: #000000;\">From (1) and (2)<br \/>\n<\/span><span style=\"color: #000000;\">AB = CD is verified<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>7. Draw five triangles and measure their sides. Check in each case, if the sum of the lengths of any two sides is always less than the third side.<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\"><strong>Solutions:<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Case 1. In triangle ABC<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-196 alignright\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7A-300x147.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"147\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7A-300x147.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7A-480x236.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7A.jpg 623w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><span style=\"color: #000000;\">AB= 2.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">BC = 4.8 cm and<br \/>\n<\/span><span style=\"color: #000000;\">AC = 5.2 cm<br \/>\n<\/span><span style=\"color: #000000;\">AB + BC = 2.5 cm + 4.8 cm <\/span><span style=\"color: #000000;\">= 7.3 cm<br \/>\n<\/span><span style=\"color: #000000;\">As 7.3 &gt; 5.2<br \/>\n<\/span><span style=\"color: #000000;\">\u2234 AB + BC &gt; AC<br \/>\n<\/span><span style=\"color: #000000;\">Hence, the sum of any two sides of a triangle is greater than the third side.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Case 2. In triangle PQR<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-197 alignright\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7B-300x145.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"145\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7B-300x145.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7B-480x232.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7B.jpg 603w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">PQ = 2 cm<br \/>\n<\/span><span style=\"color: #000000;\">QR = 2.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">PR = 3.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">PQ + QR = 2 cm + 2.5 cm <\/span><span style=\"color: #000000;\">= 4.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">As 4.5 &gt; 3.5<br \/>\n<\/span><span style=\"color: #000000;\">\u2234 PQ + QR &gt; PR<br \/>\n<\/span><span style=\"color: #000000;\">Hence, the sum of any two sides of a triangle is greater than the third side.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Case 3. In triangle XYZ<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-198 alignright\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7C-300x169.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"169\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7C-300x169.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7C-480x270.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7C.jpg 550w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">XY = 5 cm<br \/>\n<\/span><span style=\"color: #000000;\">YZ = 3 cm<br \/>\n<\/span><span style=\"color: #000000;\">ZX = 6.8 cm<br \/>\n<\/span><span style=\"color: #000000;\">XY + YZ = 5 cm + 3 cm <\/span><span style=\"color: #000000;\">= 8 cm<br \/>\n<\/span><span style=\"color: #000000;\">As 8 &gt; 6.8<br \/>\n<\/span><span style=\"color: #000000;\">\u2234 XY + YZ &gt; ZX<br \/>\n<\/span><span style=\"color: #000000;\">Hence, the sum of any two sides of a triangle is greater than the third side.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Case 4. In triangle MNS<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-199 alignright\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7D-300x160.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"160\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7D-300x160.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7D-480x257.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7D.jpg 548w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">MN = 2.7 cm<br \/>\n<\/span><span style=\"color: #000000;\">NS = 4 cm<br \/>\n<\/span><span style=\"color: #000000;\">MS = 4.7 cm<br \/>\n<\/span><span style=\"color: #000000;\">MN + NS = 2.7 cm + 4 cm = <\/span><span style=\"color: #000000;\">6.7 cm<br \/>\n<\/span><span style=\"color: #000000;\">As 6.7 &gt; 4.7<br \/>\n<\/span><span style=\"color: #000000;\">\u2234 MN + NS &gt; MS<br \/>\n<\/span><span style=\"color: #000000;\">Hence, the sum of any two sides of a triangle is greater than the third side.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><strong><span style=\"color: #000000;\">Case 5. In triangle KLM<\/span><\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-200 alignright\" src=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7E-300x163.jpg\" alt=\"NCERT Class 6 Math Solution\" width=\"300\" height=\"163\" srcset=\"https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7E-300x163.jpg 300w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7E-480x261.jpg 480w, https:\/\/theexampillar.com\/ncert\/wp-content\/uploads\/2022\/07\/NCERT-Class-6-Math-Ex-5.1Q7E.jpg 509w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif;\"><span style=\"color: #000000;\">KL = 3.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">LM = 3.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">KM = 3.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">KL + LM = 3.5 cm + 3.5 cm <\/span><span style=\"color: #000000;\">= 7 cm<br \/>\n<\/span><span style=\"color: #000000;\">As 7 cm &gt; 3.5 cm<br \/>\n<\/span><span style=\"color: #000000;\">\u2234 KL + LM &gt; KM<br \/>\n<\/span><span style=\"color: #000000;\">Hence, the sum of any two sides of a triangle is greater than the third side.<\/span><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-family: georgia, palatino, serif; color: #000000;\">Therefore, we conclude that the sum of any two sides of a triangle is always greater than the third side.<\/span><\/p>\n<p>&nbsp;<\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 100%; background-color: #f2e079; text-align: center;\"><span style=\"color: #000000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong>NCERT Class 6<sup>th\u00a0<\/sup>Solution\u00a0<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-english\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 English\u201d (Edit)\">NCERT Solutions Class 6 English<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-hindi\/\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Hindi<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-maths\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Maths\u201d (Edit)\">NCERT Solutions Class 6 Maths<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"font-family: georgia, palatino, serif;\"><a href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-sanskrit\/\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #ff0000; font-size: 14pt;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\">NCERT Solutions Class 6 Sanskrit<\/span><\/strong><\/span><\/a><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 100%; text-align: left;\"><span style=\"color: #ff0000; font-size: 14pt; font-family: georgia, palatino, serif;\"><strong><span style=\"color: #0000ff; font-size: 12pt;\"><a class=\"row-title\" style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-6-social-science\/\" target=\"_blank\" rel=\"noopener\" aria-label=\"\u201cNCERT Solutions Class 6 Social Science\u201d (Edit)\">NCERT Solutions Class 6 Social Science<\/a><\/span><\/strong><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 6 Maths Chapter &#8211; 5 (Understanding Elementary Shapes) The NCERT Solutions in English Language for Class 6 Mathematics Chapter &#8211; 5 Understanding Elementary Shapes Exercise 5.1 has been provided here to help the students in solving the questions from this exercise. Chapter 5: Understanding Elementary Shapes NCERT Solution Class 6 Maths Exercise [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[12,13,4,5],"class_list":["post-175","post","type-post","status-publish","format-standard","hentry","category-class-6-maths","tag-chapter-5-understanding-elementary-shapes-in-english","tag-ncert-solutions-class-6-maths-chapter-5-in-english","tag-ncert-solutions-class-6-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.5) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.1 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"The NCERT Solutions in English Language for Class 6 Mathematics Chapter - 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