{"id":1654,"date":"2022-11-02T09:44:56","date_gmt":"2022-11-02T09:44:56","guid":{"rendered":"https:\/\/theexampillar.com\/ncert\/?p=1654"},"modified":"2022-11-02T09:44:56","modified_gmt":"2022-11-02T09:44:56","slug":"ncert-solutions-class-7-maths-chapter-1-integers-ex-1-3","status":"publish","type":"post","link":"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-1-integers-ex-1-3\/","title":{"rendered":"NCERT Solutions Class 7 Maths Chapter 1 Integers Ex 1.3"},"content":{"rendered":"<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">NCERT Solutions Class 7 Maths<\/span><br \/>\n<span style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter &#8211; 1 (Integers)<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">The NCERT Solutions in English Language for Class 7 Mathematics <strong>Chapter &#8211; 1 Integers <\/strong>Exercise 1.3 has been provided here to help the students in solving the questions from this exercise.<\/span><\/p>\n<h4 id=\"chapter-1\"><span id=\"Chapter_1_Knowing_Our_Numbers\" style=\"color: #000000; font-family: georgia, palatino, serif;\">Chapter 1: Integers <\/span><\/h4>\n<ul>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-1-integers-ex-1-1\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 1.1<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-1-integers-ex-1-2\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 1.2<\/span><\/a><\/span><\/li>\n<li><span style=\"color: #0000ff;\"><a style=\"color: #0000ff;\" href=\"https:\/\/theexampillar.com\/ncert\/ncert-solutions-class-7-maths-chapter-1-integers-ex-1-4\" target=\"_blank\" rel=\"noopener\"><span style=\"font-family: georgia, palatino, serif;\">NCERT Solution Class 7 Maths Exercise &#8211; 1.4<\/span><\/a><\/span><\/li>\n<\/ul>\n<h2 style=\"text-align: center;\"><span style=\"color: #000000; font-family: georgia, palatino, serif;\">Exercise &#8211; 1.3<\/span><\/h2>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>1. Find each of the following products:<br \/>\n<\/strong><strong>(a) 3 \u00d7 (-1)<br \/>\n(b) (-1) \u00d7 225<br \/>\n(c) (-21) \u00d7 (-30)<br \/>\n(d) (-316) \u00d7 (-1)<br \/>\n(e) (-15) \u00d7 0 \u00d7 (-18)<br \/>\n(f) (-12) \u00d7 (-11) \u00d7 (10)<br \/>\n(g) 9 \u00d7 (-3) \u00d7 (-6)<br \/>\n(h) (-18) \u00d7 (-5) \u00d7 (-4)<br \/>\n(i) (-1) \u00d7(-2) \u00d7 (-3) \u00d7 4<br \/>\n(j) (-3) \u00d7 (-6) \u00d7 (-2) \u00d7 (-1)<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n(a) 3 \u00d7 (-1)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= 3 \u00d7 (-1)<br \/>\n= -3\u00a0 [\u2235 (+ \u00d7 \u2013 = -)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) (\u20131) \u00d7 225<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= (-1) \u00d7 225<br \/>\n= -225 [\u2235 (- \u00d7 + = -)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c) (\u201321) \u00d7 (\u201330)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= (-21) \u00d7 (-30)<br \/>\n= 630 [\u2235 (- \u00d7 \u2013 = +)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d) (\u2013316) \u00d7 (\u20131)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= (-316) \u00d7 (-1)<br \/>\n= 316 [\u2235 (- \u00d7 \u2013 = +)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(e) (\u201315) \u00d7 0 \u00d7 (\u201318)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= (\u201315) \u00d7 0 \u00d7 (\u201318)<br \/>\n= 0<br \/>\n\u2235 Any integer is multiplied with zero and the answer is zero itself.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(f) (\u201312) \u00d7 (\u201311) \u00d7 (10)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= (\u201312) \u00d7 (-11) \u00d7 (10)<br \/>\nFirst multiply the two numbers having same sign,<br \/>\n= 132 \u00d7 10 [\u2235 (- \u00d7 \u2013 = +)]<br \/>\n= 1320<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(g) 9 \u00d7 (\u20133) \u00d7 (\u2013 6)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= 9 \u00d7 (-3) \u00d7 (-6)<br \/>\nFirst multiply the two numbers having same sign,<br \/>\n= 9 \u00d7 18 [\u2235 (- \u00d7 \u2013 = +)]<br \/>\n= 162<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(h) (\u201318) \u00d7 (\u20135) \u00d7 (\u2013 4)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= (-18) \u00d7 (-5) \u00d7 (-4)<br \/>\nFirst multiply the two numbers having same sign,<br \/>\n= 90 \u00d7 &#8211; 4 [\u2235 (- \u00d7 \u2013 = +)]<br \/>\n= \u2013 360 [\u2235 (+ \u00d7 \u2013 = -)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(i) (\u20131) \u00d7 (\u20132) \u00d7 (\u20133) \u00d7 4<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= [(\u20131) \u00d7 (\u20132)] \u00d7 [(\u20133) \u00d7 4]<br \/>\n= 2 \u00d7 (-12) [\u2235 (- \u00d7 \u2013 = +), (- \u00d7 + = -)]<br \/>\n= \u2013 24<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(j) (\u20133) \u00d7 (\u20136) \u00d7 (\u20132) \u00d7 (\u20131)<br \/>\n<\/strong>By the rule of Multiplication of integers,<br \/>\n= [(\u20133) \u00d7 (\u20136)] \u00d7 [(\u20132) \u00d7 (\u20131)]<br \/>\nFirst multiply the two numbers having same sign,<br \/>\n= 18 \u00d7 2 [\u2235 (- \u00d7 \u2013 = +)<br \/>\n= 36<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>2. Verify the following:<br \/>\n<\/strong><strong>(a) 18 \u00d7 [7 + (\u20133)] = [18 \u00d7 7] + [18 \u00d7 (\u20133)]<br \/>\n(b) (-21) \u00d7 [(-4) + (-6)] = [(-21) \u00d7 (-4)] + [(-21) \u00d7 (-6)]<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n<\/strong><strong>(a) 18 \u00d7 [7 + (\u20133)] = [18 \u00d7 7] + [18 \u00d7 (\u20133)]<br \/>\n<\/strong>Let us consider the Left Hand Side (LHS) first = 18 \u00d7 [7 + (\u20133)]<br \/>\n= 18 \u00d7 [7 \u2013 3]<br \/>\n= 18 \u00d7 4<br \/>\n= 72<br \/>\nNow, consider the Right Hand Side (RHS) = [18 \u00d7 7] + [18 \u00d7 (\u20133)]<br \/>\n= [126] + [-54]<br \/>\n= 126 \u2013 54<br \/>\n= 72<br \/>\nBy comparing LHS and RHS,<br \/>\n72 = 72<br \/>\nLHS = RHS<br \/>\nHence, the given equation is verified.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) (\u201321) \u00d7 [(\u2013 4) + (\u2013 6)] = [(\u201321) \u00d7 (\u2013 4)] + [(\u201321) \u00d7 (\u2013 6)]<br \/>\n<\/strong>Let us consider the Left Hand Side (LHS) first = (\u201321) \u00d7 [(\u2013 4) + (\u2013 6)]<br \/>\n= (-21) \u00d7 [-4 \u2013 6]<br \/>\n= (-21) \u00d7 [-10]<br \/>\n= 210<br \/>\nNow, consider the Right Hand Side (RHS) = [(\u201321) \u00d7 (\u2013 4)] + [(\u201321) \u00d7 (\u2013 6)]<br \/>\n= [84] + [126]<br \/>\n= 210<br \/>\nBy comparing LHS and RHS,<br \/>\n210 = 210<br \/>\nLHS = RHS<br \/>\nHence, the given equation is verified.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>3.<br \/>\n(i) For any integer a, what is (\u20131) \u00d7 a equal to?<br \/>\n(ii) Determine the integer whose product with (-1) is 0.<br \/>\n(a) -22<br \/>\n(b) 37<br \/>\n(c) 0<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n(i) For any integer a, what is (\u20131) \u00d7 a equal to?<br \/>\n<\/strong>= (-1) \u00d7 a = -a<br \/>\nBecause, when we multiplied any integer a with -1, then we get additive inverse of that integer.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii). Determine the integer whose product with (\u20131) is<br \/>\n<\/strong><strong>(a) \u201322<br \/>\n<\/strong>Now, multiply -22 with (-1), we get<br \/>\n= -22 \u00d7 (-1)<br \/>\n= 22<br \/>\nBecause, when we multiplied integer -22 with -1, then we get additive inverse of that integer.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) 37<br \/>\n<\/strong>Now, multiply 37 with (-1), we get<br \/>\n= 37 \u00d7 (-1)<br \/>\n= -37<br \/>\nBecause, when we multiplied integer 37 with -1, then we get additive inverse of that integer.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c) 0<br \/>\n<\/strong>Now, multiply 0 with (-1), we get<br \/>\n= 0 \u00d7 (-1)<br \/>\n= 0<br \/>\nBecause, the product of negative integers and zero give zero only.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>4. Starting from (\u20131) \u00d7 5, write various products showing some pattern to show <\/strong><strong>(\u20131) \u00d7 (\u20131) = 1.<br \/>\n<\/strong><strong>Solution &#8211;<br \/>\n<\/strong>The various products are,<br \/>\n= -1 \u00d7 5 = -5<br \/>\n= -1 \u00d7 4 = -4<br \/>\n= -1 \u00d7 3 = -3<br \/>\n= -1 \u00d7 2 = -2<br \/>\n= -1 \u00d7 1 = -1<br \/>\n= -1 \u00d7 0 = 0<br \/>\n= -1 \u00d7 -1 = 1<br \/>\nWe concluded that the product of one negative integer and one positive integer is negative integer. Then, the product of two negative integers is a positive integer.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>5. Find the product, using suitable properties:<br \/>\n<\/strong><strong>(a) 26 \u00d7 (\u2013 48) + (\u2013 48) \u00d7 (\u201336)<br \/>\n(b) 8 \u00d7 53 \u00d7 (-125)<br \/>\n(c) 15 \u00d7 (-25) \u00d7 (-4) \u00d7 (-10)<br \/>\n(d) (-41) \u00d7 102<br \/>\n(e) 625 \u00d7 (-35) + (-625) \u00d7 65<br \/>\n(f) 7 \u00d7 (50 \u2013 2)<br \/>\n(g) (-17) \u00d7 (-29)<br \/>\n(h) (-57) \u00d7 (-19) + 57<br \/>\n<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n(a) 26 \u00d7 (-48) + (-48) \u00d7 (-36)<br \/>\n<\/strong>The given equation is in the form of Distributive law of Multiplication over Addition.<br \/>\n= a \u00d7 (b + c) = (a \u00d7 b) + (a \u00d7 c)<br \/>\nLet, a = -48, b = 26, c = -36<br \/>\nNow,<br \/>\n= 26 \u00d7 (\u2013 48) + (\u2013 48) \u00d7 (\u201336)<br \/>\n= -48 \u00d7 (26 + (-36)<br \/>\n= -48 \u00d7 (26 \u2013 36)<br \/>\n= -48 \u00d7 (-10)<br \/>\n= 480 [\u2235 (- \u00d7 \u2013 = +)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) 8 \u00d7 53 \u00d7 (\u2013125)<br \/>\n<\/strong>The given equation is in the form of Commutative law of Multiplication.<br \/>\n= a \u00d7 b = b \u00d7 a<br \/>\nThen,<br \/>\n= 8 \u00d7 [53 \u00d7 (-125)]<br \/>\n= 8 \u00d7 [(-125) \u00d7 53]<br \/>\n= [8 \u00d7 (-125)] \u00d7 53<br \/>\n= [-1000] \u00d7 53<br \/>\n= \u2013 53000 [\u2235 (- \u00d7 + = -)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c) 15 \u00d7 (\u201325) \u00d7 (\u2013 4) \u00d7 (\u201310)<br \/>\n<\/strong>The given equation is in the form of Commutative law of Multiplication.<br \/>\n= a \u00d7 b = b \u00d7 a<br \/>\nThen,<br \/>\n= 15 \u00d7 [(\u201325) \u00d7 (\u2013 4)] \u00d7 (\u201310)<br \/>\n= 15 \u00d7 [100] \u00d7 (\u201310)<br \/>\n= 15 \u00d7 [-1000]<br \/>\n= \u2013 15000<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d) (\u2013 41) \u00d7 102<br \/>\n<\/strong>The given equation is in the form of Distributive law of Multiplication over Addition.<br \/>\n= a \u00d7 (b + c) = (a \u00d7 b) + (a \u00d7 c)<br \/>\n= (-41) \u00d7 (100 + 2)<br \/>\n= (-41) \u00d7 100 + (-41) \u00d7 2<br \/>\n= \u2013 4100 \u2013 82<br \/>\n= \u2013 4182<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(e) 625 \u00d7 (\u201335) + (\u2013 625) \u00d7 65<br \/>\n<\/strong>The given equation is in the form of Distributive law of Multiplication over Addition.<br \/>\n= a \u00d7 (b + c) = (a \u00d7 b) + (a \u00d7 c)<br \/>\n= 625 \u00d7 [(-35) + (-65)]<br \/>\n= 625 \u00d7 [-100]<br \/>\n= \u2013 62500<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(f) 7 \u00d7 (50 \u2013 2)<br \/>\n<\/strong>The given equation is in the form of Distributive law of Multiplication over Subtraction.<br \/>\n= a \u00d7 (b \u2013 c) = (a \u00d7 b) \u2013 (a \u00d7 c)<br \/>\n= (7 \u00d7 50) \u2013 (7 \u00d7 2)<br \/>\n= 350 \u2013 14<br \/>\n= 336<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(g) (\u201317) \u00d7 (\u201329)<br \/>\n<\/strong>The given equation is in the form of Distributive law of Multiplication over Addition.<br \/>\n= a \u00d7 (b + c) = (a \u00d7 b) + (a \u00d7 c)<br \/>\n= (-17) \u00d7 [-30 + 1]<br \/>\n= [(-17) \u00d7 (-30)] + [(-17) \u00d7 1]<br \/>\n= [510] + [-17]<br \/>\n= 493<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(h) (\u201357) \u00d7 (\u201319) + 57<br \/>\n<\/strong>The given equation is in the form of Distributive law of Multiplication over Addition.<br \/>\n= a \u00d7 (b + c) = (a \u00d7 b) + (a \u00d7 c)<br \/>\n= (57 \u00d7 19) + (57 \u00d7 1)<br \/>\n= 57 [19 + 1]<br \/>\n= 57 \u00d7 20<br \/>\n= 1140<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>6. A certain freezing process requires that room temperature be lowered from 40\u00b0C at the rate of 5\u00b0C every hour. What will be the room temperature 10 hours after the process begins?<br \/>\n<\/strong><strong>Solution &#8211;<br \/>\n<\/strong>Temperature of the room in the beginning = 40\u00b0C<br \/>\nTemperature after 1 hour<br \/>\n= 40\u00b0C \u2013 1 \u00d7 5\u00b0C<br \/>\n= 40\u00b0C \u2013 5\u00b0C \u2013 35\u00b0C<br \/>\nSimilarly, temperature of the room after 10 hours<br \/>\n= 40\u00b0C \u2013 10 \u00d7 5\u00b0C<br \/>\n= 40\u00b0C \u2013 50\u00b0C<br \/>\n= -10\u00b0C<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>7. In a class test containing 10 questions, 5 marks are awarded for every correct answer and (\u20132) marks are awarded for every incorrect answer and 0 for questions not attempted.<br \/>\n<\/strong><strong>(i) Mohan gets four correct and six incorrect answers. What is his score?<br \/>\nSolution &#8211;<br \/>\n<\/strong>Marks awarded to Mohan = 4 \u00d7 5<\/span><br \/>\n<span style=\"color: #000000;\">= 20 for correct answers <\/span><br \/>\n<span style=\"color: #000000;\">Marks awarded to Mohan = 6 \u00d7 (-2)<\/span><br \/>\n<span style=\"color: #000000;\">= &#8211; 12 for incorrect answers.<\/span><br \/>\n<span style=\"color: #000000;\">\u2234 Total marks obtained by Mohan = 20 + (-12) = 20 \u2013 12 = 8<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(ii) Reshma gets five correct answers and five incorrect answers, what is her score?<br \/>\nSolution &#8211;<br \/>\n<\/strong>Marks awarded to Reshma for correct answers = 5 \u00d7 5 <\/span><br \/>\n<span style=\"color: #000000;\">= 25<\/span><br \/>\n<span style=\"color: #000000;\">Marks awarded to Reshma for incorrect answers = 5 \u00d7 (-2) <\/span><br \/>\n<span style=\"color: #000000;\">= -10 <\/span><br \/>\n<span style=\"color: #000000;\">\u2234 Total marks obtained by Reshma = 25 + (-10) <\/span><br \/>\n<span style=\"color: #000000;\">= 25 \u2013 10 <\/span><br \/>\n<span style=\"color: #000000;\">= 15<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(iii) Heena gets two correct and five incorrect answers out of seven questions she attempts. What is her score?<br \/>\n<\/strong><strong>Solution &#8211;<br \/>\n<\/strong>Marks awarded to Heena for correct answers = 2 \u00d7 5 = 10<br \/>\nMarks awarded to Heena for incorrect answers = 5 \u00d7 (-2) = -10<br \/>\nNumber of question not attempted by Heena = 10 \u2013 (2 + 5) = 10 \u2013 7 = 3<br \/>\nMarks awarded to Heena for non-attempted questions = 3 \u00d7 0 = 0<br \/>\n\u2234 Total marks obtained by Heena<br \/>\n= 10 + (-10) + 0<br \/>\n= 10 &#8211; 10 + 0<br \/>\n= 0<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>8. A cement company earns a profit of \u20b9 8 per bag of white cement sold and a loss of <\/strong><strong>\u20b95 per bag of grey cement sold.<br \/>\n<\/strong><strong>(a) The company sells 3,000 bags of white cement and 5,000 bags of grey cement in a month. What is its profit or loss?<br \/>\nSolution &#8211;<br \/>\n<\/strong>Profit on one white cement bag = \u20b9 8<br \/>\nloss on one grey cement bag = \u20b9 \u20135<br \/>\nProfit on 3,000 bags of white cement = \u20b9 (8 \u00d7 3,000)<br \/>\n= \u20b9 24,000<br \/>\nLoss on 5,000 bags of grey cement = \u20b9 (-5 \u00d7 5000)<br \/>\n= \u2013 \u20b9 25,000<br \/>\nTotal loss = \u2013 \u20b9 25,000 + \u20b9 24,000<br \/>\n= \u2013 \u20b9 1000<br \/>\n<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) What is the number of white cement bags it must sell to have neither profit nor loss, if the number of grey bags sold is 6,400 bags.<br \/>\n<\/strong><strong>Solution &#8211;<br \/>\n<\/strong>Selling price of grey bags at a loss of \u20b9 5 = \u20b9 (5 \u00d7 6,400) =\u00a0 \u20b9 32,000<br \/>\nFor no profit and no loss, the selling price of white bags = \u20b9 32,000<br \/>\nRate of selling price of white bags at a profit of \u20b9 8 per bag.<br \/>\n\u2234 Number of white cement bags sold = 32,000\/8 = 4000<br \/>\nHence, the 4000 bags of white cement have neither profit nor loss.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>9. Replace the blank with an integer to make it a true statement.<br \/>\n<\/strong><strong>(a) (\u20133) \u00d7 __ = 27<br \/>\n(b) 5 \u00d7 __ = -35<br \/>\n(c) __ \u00d7 (-8) = -56<br \/>\n(d) __ \u00d7 (-12) = 132<\/strong><\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>Solution &#8211;<br \/>\n(a) (\u20133) \u00d7 __ = 27<br \/>\n<\/strong>Let us assume the missing integer be x,<br \/>\nThen,<br \/>\n= (\u20133) \u00d7 (x) = 27<br \/>\n= x = \u2013 (27\/3)<br \/>\n= x = -9<br \/>\nLet us substitute the value of x in the place of blank,<br \/>\n= (\u20133) \u00d7 (<span style=\"text-decoration: underline;\"><strong>-9<\/strong><\/span>) = 27 [\u2235 (- \u00d7 \u2013 = +)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(b) 5 \u00d7 __ = \u201335<br \/>\n<\/strong>Let us assume the missing integer be x,<br \/>\nThen,<br \/>\n= (5) \u00d7 (x) = -35<br \/>\n= x = \u2013 (-35\/5)<br \/>\n= x = -7<br \/>\nLet us substitute the value of x in the place of blank,<br \/>\n= (5) \u00d7 (<span style=\"text-decoration: underline;\"><strong>-7<\/strong><\/span>) = &#8211; 35 [\u2235 (+ \u00d7 \u2013 = -)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(c) __ \u00d7 (\u2013 8) = \u201356<br \/>\n<\/strong>Let us assume the missing integer be x,<br \/>\nThen,<br \/>\n= (x) \u00d7 (-8) = -56<br \/>\n= x = (-56\/-8)<br \/>\n= x = 7<br \/>\nLet us substitute the value of x in the place of blank,<br \/>\n= (<span style=\"text-decoration: underline;\"><strong>7<\/strong><\/span>) \u00d7 (-8) = -56 \u2026 [\u2235 (+ \u00d7 \u2013 = -)]<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #000000;\"><strong>(d) _____ \u00d7 (\u201312) = 132<br \/>\n<\/strong>Let us assume the missing integer be x,<br \/>\nThen,<br \/>\n= (x) \u00d7 (-12) = 132<br \/>\n= x = \u2013 (132\/12)<br \/>\n= x = \u2013 11<br \/>\nLet us substitute the value of x in the place of blank,<br \/>\n= (<span style=\"text-decoration: underline;\"><strong>\u201311<\/strong><\/span>) \u00d7 (-12) = 132 \u2026 [\u2235 (- \u00d7 \u2013 = +)]<\/span><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Maths Chapter &#8211; 1 (Integers) The NCERT Solutions in English Language for Class 7 Mathematics Chapter &#8211; 1 Integers Exercise 1.3 has been provided here to help the students in solving the questions from this exercise. Chapter 1: Integers NCERT Solution Class 7 Maths Exercise &#8211; 1.1 NCERT Solution Class 7 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[219],"tags":[281,282,283,5],"class_list":["post-1654","post","type-post","status-publish","format-standard","hentry","category-class-7-maths","tag-ncert-class-7-maths-chapter-1-integers-in-english","tag-ncert-solutions-class-7-maths-chapter-1-in-english","tag-ncert-solutions-class-7-maths-in-english","tag-ncert-solutions-in-english"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.9 (Yoast SEO v27.4) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions Class 7 Maths Chapter 1 Integers Ex 1.3 | TheExamPillar NCERT<\/title>\n<meta name=\"description\" content=\"NCERT Solutions Class 7 Maths Chapter - 1 (Integers) The NCERT Solutions in English Language for Class 7 Mathematics Chapter - 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